Determine if the equations are parallel, perpendicular, or neither.5x + 3y = 3 and 3x + 5y = -25

Answer:

The value of U = 4

The value of W = -6

The value of V = 5

The value of Z = 1

The value of x = 3

The value of y =2

Step-by-step explanation:

Given:

20a³b³ – 24a⁵b² + 4a³b²

Solution:

Lets first factorize this expression:

20a³b³ – 24a⁵b² + 4a³b²

= −24a⁵b² + 20a³b³  +4a³b²

Taking  4a³b² common

= 4a³b² (−6a² + 5b + 1)   ___ (1)          

Now you can see this expression takes the form:

Ua^xb^y (Wa^2 + Vb+ z), where U > 0.

Now you can clearly see from (1)

The value of U is 4

The value of W is -6

The value of V is 5

The value of Z is 1

The value of x is 3

The value of y is 2

However if we take minus common from above equation:

20a³b³ – 24a⁵b² + 4a³b²

= −24a⁵b² + 20a³b³  +4a³b²

Taking  4a³b² common

= - 4a³b² (6a² - 5b - 1)   ___ (1)  

In this case the value of U is - 4, W is 6 , V is -5, Z is -1 , x is 3 and b is 2

Answer:

A

Step-by-step explanation:

Remark

The trick here is convert what you have to Ax + By = C

Solution

Given

y - 3 = 1/2 ( x + 6)                        Multiply both sides by 2

Solve

• 2(y - 3) = 2 * 1/2 (x + 6)               Do the multiplication
• 2(y - 3) = x + 6                            Remove the brackets
• 2y - 6 = x + 6                              Add 6 to both sides.
• 2y - 6 + 6 = x + 6 + 6                  Combine
• 2y = x + 12                                   Subtract x from both sides.
• -x + 2y = x - x + 12                       Combine
• -x + 2y = 12

Answer

• A = - 1
• B = 2
• C = 12

or

• When you multiply through by - 1 you get x - 2y = - 12 which is A