1/4 times 2 equals??

Answers

Answer 1
Answer:

Answer:

1/2

Step-by-step explanation:

Answer 2
Answer:

Answer:

1/2

Step-by-step explanation:

1/4 = 0.25 x 2 = 0.5 = 1/2


Related Questions

Find the derivation of y=sin (2x2 + 3x-4)<br />a. -cos (4x +3) b. -(6x2+3) cos (2x3+3x-4) c. Cos (2x3+3x-4)<br />d. (6x3+3) cos (2x3+3)<br />​
Dmitri wants to cover the top and sides of this box with glass tiles that are 1 cm square. How many tiles will he need? Dmitri will need [Blank] glass tiles. The dimentions are...26 , 15, 8.
Find the value of k so that the graph of the equation has the given y-intercept. y = − 1 /3x + 5/6 k; b = −10
The mass of a snowflake is approximately 0.000003 kilograms. Write this number in scientific notation.
What is the median of this data set 14,18,31,34,44,50

A new company is in the process of evaluating its customer service. The company offers two types of sales: (1) Internet sales and (2) store sales. The marketing research manager believes that the Internet sales are more than 10 percent higher than store sales. The alternative hypothesis for this problem would be stated as:

Answers

Therefore the correct  answer is for the alternative hypothesis is,

H_1:P_(internet)-P_(store)\leq0.10

Null Hypothesis:

A null hypothesis is a theory that assumes there is no statistical importance between the two variables in the hypothesis.

Let P_(internet) be the proportion of the internet sales and P_(store) be the proportion of the store sales.

The researchers claim is that ''the internet sales are more than 10% higher than store sales''.

The alternative hypothesis is,

H_1:P_(internet)-P_(store)\leq0.10

The opposite of alternative hypothesis is,

H_0:P_(internet)-P_(store)\leq0.10

It can be observed that the alternative hypothesis contains greater than a symbol.

Learn more about the topic Null Hypothesis:

brainly.com/question/19132215

Answer:

H_A: P_{\text{Internet}}-P_{\text{Store}} > 0.10

Step-by-step explanation:

We are given the following in the question:

Let P_{\text{Internet}} be the proportion of the internet sales and P_{\text{Store}} be the proportion of the store sale.

Hypothesis:

We have to conduct a hypothesis to check that the Internet sales are more than 10 percent higher than store sales.

Thus, we can design the null and alternative hypothesis as:

H_(0): P_{\text{Internet}}-P_{\text{Store}}\leq 0.10\nH_A: P_{\text{Internet}}-P_{\text{Store}} > 0.10

Alternate Hypothesis:

The alternate hypothesis states that the proportion of the internet sales is greater than the proportion of store sales by 10 percent.

5. Expla in why 4 is or is not a multiplicative inverse mod 10 of 7.

Answers

Answer:

  4 is not. (3 is)

Step-by-step explanation:

A number is the multiplicative inverse of 7 (mod 10) if the product mod 10 is 1.

7 × 4 mod 10 = 28 mod 10 = 8 . . . . not 1

The product of a number is not less than 45. The inequality for the statement is.​

Answers

Answer:

x is greater than or equal to 45

Step-by-step explanation:

8. The temperature was 8°F. It dropped so that the temperature was 0°F.°F represents the change in temperature.

Answers

Answer: -8f

Initial temperature= 8F
Final temperature = 0F

Change temperature= Final temperature-initial temperature

Change in temperature = 0-8F
Change temperature = -8F
So final answer is
change in temperature = -8F

Hope this helps ʕ•ᴥ•ʔ

Find the slope of the line that passes through 6, 0 and −3, 2

Answers

Answer:

slope = - (2)/(9)

Step-by-step explanation:

calculate the slope m using the slope formula

m = \frac{y_(2)-y_(1) }{x_{2-x_(1) } }

let (x₁, y₁ ) = (6, 0 ) and (x₂, y₂ ) = (- 3, 2 )

substitute these values into the formula for m

m = (2-0)/(-3-6) = (2)/(-9) = - (2)/(9)

A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of type A (the original paint) and 9 cans of type B (the modified paint) were selected and applied to similar surfaces. The drying times, in hours, were recorded. The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B: 4.90 hrs < μ1 - μ2 < 17.50 hrs
What does the confidence interval suggest about the population means?

A. The confidence interval includes 0 which suggests that the two population means might be equal. There​ doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
B. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.
C. The confidence interval includes only positive values which suggests that the two population means might be equal. There​ doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
D. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

Answers

This question is not complete, I got the complete one from google as below:

A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of type A (the original paint) and 9 cans of type B (the modified paint) were selected and applied to similar surfaces. The drying times, in hours, were recorded.

The summary statistics are as follows.

Type A                                   Type B

x1 = 76.3 hrs                       x2 = 65.1 hrs

s1 = 4.5 hrs                          s2 = 5.1 hrs

n1 = 11                                  n2 = 9

The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B:

4.90 hrs < μ1 - μ2 < 17.50 hrs

What does the confidence interval suggest about the population means?

A. The confidence interval includes 0 which suggests that the two population means might be equal. There​ doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

B. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

C. The confidence interval includes only positive values which suggests that the two population means might be equal. There​ doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

D. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

Answer:

Option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

Step-by-step explanation:

The 98% confidence interval for the difference in mean drying times of the two types of paints is (4.90, 17.50). This implies that Type A takes between 4.90 and 17.50 hours more to dry than type B paint.

Thus, option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.