Write 9(39) using the Distributive Property. Then simplify.

Answers

Answer 1

Answer: 9 x 3 = 27
9 x 9 = 81
27+81= 109

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Find cos theta if csc theta = square root 5

Answers

Answer:

cos theta = adjacent/hypotenuse = $(2)/(√(5) )$

Step-by-step explanation:

csc theta = hypotenuse/opposite = $√(5)$ /1 (reciprocal identity)

1^2 + b^2 = $√(5)$ ^2 (pythagorean theorem)

b^2 = 5-1

b = 2

cos theta = adjacent/hypotenuse = 2/ $√(5)$ (quotient identity)

What is the equation of the line that passes through the points (-2,2) and (0,5)?

Answers

$(-2,2), \ \ \ (0,5)\n\nFirst \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \n \n m= (y_(2)-y_(1))/(x_(2)-x_(1) ) \n \nm=( 5-2)/(0+2) = (3)/(2) \n \n Use \ point \ form \ of \ a \ line\ with \ one \ point: \n \n y-y_(1) =m(x-x _(1))\n\nm=(3)/(2), \ \ x_(1)=-2, \ \ y_(1)=2 \n \ny- 2 = (3)/(2) (x+2)\n\ny=(3)/(2)x +3+2 \n \ny=(3)/(2)x + 5$

The quantity q varies inversely with the square of m and directly with the product of r and x. When q is 2.5, m is 4 and the product of r and x is 8. What is the constant of variation?5/8
5/4
5
10

Answers

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

The quantity q varies inversely with the square of m and directly with the product fo r and x.

According to question,

$q=k(rx)/(m^2)\n\n\text{ where k denotes constant of variation}$

Since q=2.5, m=4, rx=8,

So, we put the value of all of theses in our above relation:

$q=k(rx)/(m^2)\n\n2.5=k(8)/(4^2)\n\n2.5=k(8)/(16)\n\n2.5=k(1)/(2)\n\n2.5* 2=k\n\n5=k$

Hence, Third option is correct.

q = k * (r*x)/m^2 ⇒ k = q*m^2 /(r*x)

k = 2.5 (4)^2 / 8 = 5

Answer: 5

Y=12x in standard form

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Standard form = Ax + By = C. 0=12x-y

How many fractions are equalavent to 4/5

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Equivalent fractions are multiples of a fraction that is completely reduced. And there is an infinite amount of numbers to multiply 4/5 by, so there is an infinite number of fractions equivalent to 4/5.

It's infinite. There are an infinite amount of numbers.

1/4x+3/8 factored by the GCF