PLEASE HELP ASAP!!!!!
PLEASE HELP ASAP!!!!! - 1

Answers

Answer 1
Answer:

Answer:

C. Have a good day. :)

Step-by-step explanation:


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How do you solve 5/x=x-4
Please help me!! 1. In the equation y = 25x, what is the constant of variation?A. 25B. 1/25C. ZeroD. Undefined2. In the equation of y = 25x, the number 25 also represents what? A Rate of changeB the y - interceptC the x-interceptIn the equation y = -4x, what is the constant of variation?A. 4B. zeroC. -4D. undefined4. The value of y varies directly with x and the constant of variation is 5. What is the value of x when y = 100? *25954205. The value of y varies directly with x and the constant of variation is 13. What is the value of y when x = 6? *A. 78B. 2.16C. 0.46D. zeroThe height of a stack of boxes varies directly with the number of boxes. A stack of 10 boxes is the 20 feet high. How tall is a stack of 18 boxes? *9 feet5 feet36 feet40 feetPerry's pay is in direct variation to the hours she works. Perry earns $84 for 14 hours. How much will she earn for 24 hours? *A. $ 144B. $120C. $2, 016D. $336Submit

Find the selling price cost to store:50$ markup 10%

Answers

If you would like to find the selling price, you can calculate this using the following steps:

10% of $50 = 10% * 50 = 10/100 * 50 = $5

$50 + $5 = $55

The correct result would be $55.

Answer:

$55

Step-by-step explanation:

$55

Devon wants to write an equation for a line that passes through 2 of the data points he has collected. The points are (8, 5) and (–12, –9). He writes the equation 7x – 10y = 3. Is this a good model? Explain your reasoning.

Answers

For this case we have the following equation:
 7x - 10y = 3
 From here, we must substitute ordered pairs of the form:
 (x, y)
 If the ordered pair satisfies the equation, then it belongs to the line.
 We have then:

 For (8, 5):
 
We substitute the following values:
 x = 8 y = 5 7 (8) - 10 (5) = 3 56 - 50 = 3 6 = 3
 We observe that the equation is not satisfied and therefore, this point does not belong to the line.
 Since one of the points does not belong to the line, then the equation is not a good model.

 Answer:
 
It is not a good model. One of the points does not belong to the line.

Which fraction is bigger 5/8, 9/16, 1/2, 15/32

Answers

work them out as decimals first to make it easier:
5/8 = 62.5 (5÷8 ×100) <---- Use this equation
9/16 = 56.25
1/2 = 50
15/32 = 46.875
so this means 5/8 is biggest because it makes the biggest decimal.
(5)/(8) ,  (9)/(16) ,  (1)/(2) ,  (15)/(32)  \n(5)/(8)= (5)/(8) * (4)/(4)= (20)/(32)   \n   (9)/(16)= (9)/(16)* (2)/(2)= (18)/(32)  \n   (1)/(2)= (1)/(2)* (16)/(16)= (16)/(32)  \n (15)/(32) \n \n (15)/(32)\ \textless \ (16)/(32) \ \textless \  (18)/(32)\ \textless \ (20)/(32) \n \n (15)/(32)\ \textless \ (1)/(2) \ \textless \  (9)/(16)\ \textless \ (5)/(8)

For the values a = 3.4 and b = 2.6, which are legs of a right triangle, find c, the hypotenuse, to the nearest tenth.A. 4.3

B. 2.4

C. 2.2

D. 4.8

Answers

The length of the hypotenuse is 4.3. This is calculated as the square root of 3.4 squared plus 2.6 squared.

Answer:

Using Pythagoras theorem.

In any right angle triangle:

\text{Hypotenuse side}^2 = \text{Sum of the square of side}

As per the statement:

For the values a = 3.4 and b = 2.6, which are legs of a right triangle.

We have to find c, the hypotenuse:

Apply the Pythagoras theorem, we have;

c^2 = a^2+b^2

Substitute the values we have;

c^2=3.4^2+2.6^2 = 11.56+6.76 = 18.32

then;

c=√(18.32) = 4.28018691

Therefore, the value of c, the hypotenuse, to the nearest tenth is, 4.3 units

If u spenpend 20 minutes a night doing homework how many seconds

Answers

Answer:

1200 seconds per 20 minute study session

Step-by-step explanation:

20 min x 60 sec = 1200 seconds

Answer:1,200 secs

Step-by-step explanation:

This math my life depends on it

Answers

A geometric sequence is one in which consecutive terms form a fixed ratio r. In other words, if aₙ is the nth term in the sequence, then

a_n = a_(n-1)r

For example, if a₁ = a is the 1st term, then

2nd term = a₂ = a₁r

3rd term = a₃ = a₂r = a₁r²

4th term = a₄ = a₃r = a₁r³

and so on. It's fairly easy to infer that

nth term = a_n = a_(n-1)r = a_(n-2)r^2 = a_(n-3)r^3 = \cdots = a_1r^(n-1)

14. We're given the 2nd and 5th terms, a₂ = -243 and a₅ = -9, and we use them to find the ratio r.

a₅ = a₄r = a₃r² = a₂r³

-9 = -243 r³

r³ = 1/27

⇒   r = 1/3

Then the 1st term is

a₁ = a₂/r = -243/(1/3) = -729

and the nth term is recursively given by

a_n = \frac13a_(n-1)

and explicitly by

a_n = \left(\frac13\right)^(n-1) a_1 = -(729)/(3^(n-1)) = -(3^6)/(3^(n-1)) = -3^(7-n)

15. Now we have a₄ = 1/72 and a₃ = -1/12. Using what we know about geometric sequences, we have

a₄ / a₃ = (a₃r) / a₃ = r

so that

r = (1/72) / (-1/12) = -1/6

Then the 1st term is

a₁ = a₂/r = a₃/r² = (-1/12) / (-1/6)² = -3

and the nth term is recursively given by

a_n = -\frac16a_(n-1)

and explicitly by

a_n = \left(-\frac16\right)^(n-1) (-3) = -3\cdot(-6)^(1-n) = 3\cdot(-1)^n\cdot6^(1-n)