6. (02.01 MC)The US Department of Health and Human Services wants to know whether the national healthcare system is achieving its goals in Florida. Much information about healthcare comes from

patient records, but that source doesn't allow us to compare people who use health services with those who don't. Therefore, the US Department of Health and Human Services conducted the

Florida Health Survey, which was used to interview a random sample of 62,348 people who live in the state of Florida.

Part A: What is the population for this sample survey? What is the sample? (4 points)

Part B: The survey found that 74% of males and 83% of females in the sample had visited a general practitioner at least once during the past year. Do you think these estimates are close to

the truth about the entire population? Explain. (6 points) (10 points)

Answers

Answer 1
Answer:

Answer:

A)i) Population: Total number of people that reside in Florida..

II) Sample: 62348 people that took part in the random survey.

B) No, the estimates are not close to the truth of the entire population.

Step-by-step explanation:

A)i) The population is the total number of people that reside in Florida.

II) The sample is the 62348 people that took part in the random survey.

B) From the details given in the question, we will see that people who are not part of the healthcare system weren't included due to the fact that they used patients records to judge. This means that if they don't have healthcare, then they will have no patient records. Therefore, we can conclude that the estimates are not close to the truth of the entire population due to the fact that that those who weren't part of the Healthcare system were not considered.


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Find the seventh term of thegeometric sequence, given the
first term and common ratio.
a_=1 and r=-2/3
[?]

Answers

Answer:

T_7 = (64)/(729)

Step-by-step explanation:

Given

a =1

r = (2)/(3)

Required

Determine the 7th term

The nth term of a gp is:

T_n = a * r^{n-1

So, we have:

T_7 = 1 * (2)/(3)^{7-1

T_7 = 1 * (2)/(3)^{6

T_7 = 1 * (2^6)/(3^6)

T_7 = 1 * (64)/(729)

T_7 = (64)/(729)

Missing letter
H,I,I, K, J,M, _, O,L, Q
What is the missing letter

Answers

Answer:

n

Step-by-step explanation:

N?

Answer:

N and P?

Step-by-step explanation:

Am i right

Sara has $180 to spend on a mixture of oranges and bananas. The oranges cost $3 per pound and the bananas cost $2 per pound. What equation can she use to graph a line showing the different amounts of oranges and bananas she can buy for $180?Explain what does each elements of the equation represent.

pleasee guys i need help

Answers

Answer:

365

Step-by-step explanation:

2+3+180+180=

A die is loaded in such a way that the probability of each face turning up is proportional to the number of dots on that face. (For example, a six is three times as probable as a two.) What is the probability of getting an even number in one throw?

Answers

Answer:

simple, divide the number by two, round as needed. 6=3x as normal, 5=2.5x as nromal, etc.

Step-by-step explanation:

You want to create an 80% confidence interval for the average age of people who attend U of O football games. You take a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years. Find the value of t* for this confidence interval. Do not round your answer. Write your answer in decimal form, not as a fraction or percent.

Answers

Answer:

80% confidence interval for the average age of people who attend U of O football games is [42.795 , 44.604].

Step-by-step explanation:

We are given that a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years.

So, the pivotal quantity for 80% confidence interval for the population average start up cost is given by;

          P.Q. = (\bar X - \mu)/((s)/(√(n) ) ) ~ t_n_-_1

where, \mu = sample average age = 43.7 years old

            \sigma = sample standard deviation = 7 years

            n = sample of attendees = 100

            \mu = population average age of people

So, 80% confidence interval for the average age of people, \mu is ;

P(-1.2915 < t_9_9 < 1.2915) = 0.80

P(-1.2915 < (\bar X - \mu)/((s)/(√(n) ) ) < 1.2915) = 0.80

P( -1.2915 * {(s)/(√(n) ) < {\bar X - \mu} < 1.2915 * {(s)/(√(n) ) ) = 0.80

P( \bar X -1.2915 * {(s)/(√(n) ) < \mu < \bar X +1.2915 * {(s)/(√(n) ) ) = 0.80

80% confidence interval for\mu = [ \bar X -1.2915 * {(s)/(√(n) ) , \bar X +1.2915 * {(s)/(√(n) ) ]

                                                 = [ 43.7 -1.2915 * {(7)/(√(100) ) , 43.7 +1.2915 * {(7)/(√(100) ) ]

                                                 = [42.795 , 44.604]

Therefore, 80% confidence interval for the population average age of people who attend U of O football games is [42.795 , 44.604].

What is the solution of the system

Answers


x - 2y = 4 \n x = 2y + 4 \n 3(2y + 4) + y = 5 \n 6y  + 12 + y = 5 \n 7y =  - 7 \n y =  - 1
x = 2(-1) + 4
x = 2