Find the area of a sector with a central angle of 32° and a radius of 8.5 millimeters. Round to the nearest tenth.

Answers

Answer 1

Answer: You use the formula:
A = angles/360*pi*r^2
A = 32/360pi*8.5^2 = 0.279* 72.25= 20.15775 rounded to 20.2
I hope that this is the answer that you were looking for and it has helped you.

Answer 2

Answer:

Answer:

The area of sector is 20.2 millimeter².

Step-by-step explanation:

The formula for area of sector is

$A=\pi r^2* ((\theta)/(360))$

The central angle of the sector is 32° and the radius of the circle is 8.5 millimeters.

$A=\pi* (8.5)^2* ((32)/(360))$

$A=\pi* (6.42222222222)$

$A=20.1760061531$

$A\approx 20.2$

Therefore the area of sector is 20.2 millimeter².

Related Questions

Please explain as best as you can :)
Which is the graph of f(x) = -(x + 3)(x + 1)?
find the height of a cylinder with a surface area of 108 pie square meters. the radius of the cylinder is twice the height
Pleasee help and explain
the area of a rectangle is given by 6x²+19x+15. factor to find binomial that represent the length and width of the rectangle.

I need help with this one I’m stuck on it.

Answers

Answer:4.5

Step-by-step explanation:

Ax+by=1
bx-ay=a+b
solve in linear equation in 2 variables

Answers

$\left\{\begin{array}{ccc}ax+by=1&/\cdot a\nbx-ay=a+b&/\cdot b\end{array}\right\n\n+\left\{\begin{array}{ccc}a^2x+aby=a\nb^2x-aby=ab+b^2\end{array}\right\n------------\n.\ \ \ \ \ a^2x+b^2x=a+ab+b^2\n.\ \ \ \ \ \ (a^2+b^2)x=a+ab+b^2\n.\ \ \ \ \ \ \ \ \ \ \ \ x=(a+ab+b^2)/(a^2+b^2)\n\na\cdot(a+ab+b^2)/(a^2+b^2)+by=1\n\n(a^2+a^2b+ab^2)/(a^2+b^2)+by=1\n\nby=1-(a^2+a^2b+ab^2)/(a^2+b^2)$

$by=(a^2+b^2)/(a^2+b^2)-(a^2+a^2b+ab^2)/(a^2+b^2)\n\nby=(a^2+b^2-a^2-a^2b-ab^2)/(a^2+b^2)\n\nby=(b^2-a^2b-ab^2)/(a^2+b^2)\n\ny=(b^2-a^2b-ab^2)/(a^2b+b^3)$

$y=(b(b-a^2-ab))/(b(a^2+b^2))\n\ny=(b-a^2-ab)/(a^2+b^2)\n\nAnswer:\n\nx=(a+ab+b^2)/(a^2+b^2)\ and\ y=(b-a^2-ab)/(a^2+b^2)$

ax+by=1
bx-ay=a+b
The solution in attached file

The slope of the line whose equation is 5 x - 3 y = 4 is
5/3
4/5
-3/5

Answers

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

We have:

$5x-3y=4\qquad|\text{subtract 5x from both sides}\n\n-3y=-5x+4\qquad|\text{divide both sides by (-3)}\n\ny=(5)/(3)x-(4)/(3)$

Answer: 5/3

Look at the linear equation below.2x - 3y = -13

Which pair of numbers is a solution to the equation?
Select one:
(-5, 1)
(5, 1)
(5, -1)
(-5, -1)

Answers

The answer is (-5,1) because 2(-5)-3(1)=-13 :)

Josie went to the local hairstylist to get her hair cut. It cost $34 for the haircut. Josie tipped the hairdresser 20%. What was the total amount Josie paid? Round to nearest cent.

Answers

Answer:

$40.80 is the answer

What number needs to be added to both sides of the equation in order to complete the square?

Answers

To complete the square for the equation X^2 + 16X + __ = 18 + __, we need to add 64 to both sides to get the equation X^2 + 16X + 64 = 18 + 64.

To complete the square for the given quadratic equation, we need to add a specific value to both sides of the equation. That specific value is the square of half the coefficient of the X term. In this case, the X term's coefficient is 16, so we need to take half of 16 (which is 8) and square it (which is 64).

So, the number to be added to both sides of the equation is 64.

The completed square equation then becomes: X^2 + 16X + 64 = 18 + 64.

Learn more about Completing the square here:

brainly.com/question/4822356

#SPJ2

The probable question may be:

What number needs to be added to both sides of the equation in order to complete the square?

X^2+16X+____=18+___

Answer:

Step-by-step explanation:

Given x^2 + 16x = 18. Complete the square:

Take half of the coefficient of x (in other words, take half of 16) and square the result: we get 8^2 = 64.