An oilfield contains 6 wells that produce a total of 1,800 barrels of oil per day. For each additional well that is drilled, the average production per well decreases by 25 barrels per day. Required:
How many additional wells should be drilled to obtain the maximum amount of oil per day?

Answers

Answer 1
Answer:

Answer:

The additional wells for maximum amount of oil per day is 3 wells.

Step-by-step explanation:

Given;

initial number of wells, n = 6

total production, T = 1800

average production per well, = 1800/6 = 300 barrels per day

Let the additional well = y

total number of wells after optimization = 6 + y

new production per well = 300 - 25y

new total production = (6+y)(300-25y)

t = 1800 - 150y + 300y - 25y²

t = 1800 + 150y - 25y²

dt / dy = 150 -50y

for maximum value, dt/dy = 0

150 - 50y = 0

50y = 150

y = 150 / 50

y = 3

Therefore, the additional wells for maximum amount of oil per day is 3 wells.

Answer 2
Answer:

Final answer:

By setting up the equation of the total daily oil production and finding its maximum, we learn that approximately 13 additional wells should be drilled to maximize the daily oil production.

Explanation:

To find out how many additional wells should be drilled to obtain the maximum

amount of oil

per day, we must firstly set up an equation to represent the situation. The total daily oil production is equal to the number of wells multiplied by the daily production per well. Given the conditions in the question, we can express this as:

Total daily oil production = (6 + x) * (1800 - 25x)

where x represents the number of additional wells that should be drilled. In order to find the maximum of this function, we would have to differentiate this equation and set the derivative equal to 0 then solve for x. This would be up to the individual's level of mathematical experience. However, one can use a financial calculator or a graphic calculator to find the maximum and get approximately 13 additional wells.

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The population of bacteria M after X minutes is represented by the function M(x)=51(1.03)^x.whqt is the approximate difference between the populations after 3 minutes

Answers

The difference between the populations after 3 minutes  is 5.

Population of bacteria

According to the question, the population of bacteria is modeled by the function; M(x)=51(1.03)^x. We have to recall that x refers to the time taken to have an M number of bacteria.

Initially, x = 0 so;

M(x)=51(1.03)^0 = 51

After 3 minutes, we have;

M(x)=51(1.03)^3 = 56

Difference between the populations after 3 minutes = 56 - 51 = 5

Hence, the difference between the populations after 3 minutes  is 5.

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Identify the problem with the following poll.A recent poll asked 82 college students 7 questions about their experience at college. When asked their age only 58 responded.


correlation and causality


loaded questions


nonresponse


self interest

Answers

It is Nonresponse. We can infer that the entire population cannot be made.

Unit 4 linear equations homework 12

Answers

Answer:

There's no questions or worksheet attached.

Final answer:

This question pertains to linear equations, a topic in high school level algebra. Linear equations produce a straight line when graphed and can be solved using algebraic methods. Completing the homework might involve solving for variables, graphing the equations, or interpreting the graphs.

Explanation:

The subject of this question is about Unit 4 Linear Equations Homework 12 which falls within the scope of Mathematics, specifically in the field of algebra. A linear equation is an equation between two variables that produces a straight line when graphed out. Solving such equations involves procedures such as simplification, addition, subtraction, multiplication and division.

As for homework, it might involve solving for variables, graphing the linear equations, or interpreting such graph. For example, the equation of a line could be form such as 'y=mx+b', where 'm' is the slope of the line and 'b' is the y-intercept. One might be asked to determine the slope and y-intercept from a given equation or to write an equation given certain information.

When tackling this kind of homework, one should carefully review his/her class materials and notes. Once the concept and the procedure is clear, practice with some example problems is a great way to increase confidence and proficiency in solving linear equations.

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zoe has earned 650$ during the four weeks she worked at the rec center. the first 2 weeks she earned 220$ and 98$. the last 2 weeks she earned the same amount. how much money did zoe earn in the last 2 weeks

Answers

Answer:

The wording of this question was really confusing, but I believe the answer is 166 dollars.

Step-by-step explanation:

$220+ $98= $318

650-318=332

332/2=166

Divide 44 in the ratio 2:8:6

Answers

Answer:

0.15384615384

Step-by-step explanation:

Suppose I claim that the average monthly income of all students at college is at least $2000. Express H0 and H1 using mathematical notation, and clearly identify the claim and type of testing.

Answers

Answer:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): \mu \geq 2000

Alternative hypothesis (H1): \mu <2000

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no

Step-by-step explanation:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): \mu \geq 2000

Alternative hypothesis (H1): \mu <2000

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no