When solving for x, the sine of 33º is used. What other angle and trigonometric function could be used to solve for x? a. cos 57º c. tan 57º b. tan 33º d. cos 33ºhurry
Answers
Answer:
The answer is A.Cos 57.
Step-by-step explanation:
Took the test..
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341.7 x 0.6818 = 232.97 mi/h
Answers
Answer:
C
Step-by-step explanation:
Use FOIL to get your answer
(3x - 4)(-6x + 5)
F: 3x*-6x = - 18x^2
O: 3x * 5 = 15x
I: - 4*-6x = 24x
L: -4 * 5 = -20
-18x^2 + 24x + 15x - 20
-18x^2 + 39x - 20
The answer is C
174
176
180
182
Can someone please help me?
Answers
Answer B
Then replace the n with term that u want so:
6(30) - 4
= 180-4
=176
So it's B
Answers
Answers
Answer:
The Interquartile range is 188
Step-by-step explanation:
Missing Data:
1,19,35,43,49,55,63,94,105,110,175,231,239,351,738
Required
Determine the Interquartile range (IQR)
The given data is ordered already.
First, we need to determine the median
For odd number of data
Median = ½(n + 1)th
In this case, n = 15; so
Median = ½(15 + 1)th
Median = ½(16)th
Median = 8th
This implies that the median is at the 8th position.
So, we have:
1,19,35,43,49,55,63 ----> Lower
(94) ---- Median
105,110,175,231,239,351,738 ---- Upper
Next, we determine the median of the lower and upper sets.
These are called lower quartile (Q1) and upper quartile (Q3) respectively
Lower: 1,19,35,43,49,55,63
Number of data, n = 7
Q1 = ½(n + 1)th
Q1 = ½(7 + 1)th
Q1 = ½(8)th
Q1 = 4th position
From the list of data in the lower set,
Q1 = 43
Upper: 105,110,175,231,239,351,738
Number of data, n = 7
Q3 = ½(n + 1)th
Q3 = ½(7 + 1)th
Q3 = ½(8)th
Q3 = 4th position
From the list of data in the upper set,
Q3 = 231
IQR is then calculated as thus:
IQR = Q3 - Q1
IQR = 231 - 43
IQR = 188
4
8
16
64
Answers
Answer:
16
Step-by-step explanation:
i know because i did the test
Answer:
16 for people with ads i really need brainliest
Step-by-step explanation: