What affect does doubling the net force have on the acceleration of the object (whenthe mass of the object stays the same)? Identify a set of two trials that support your answer to question 1

Answers

Answer 1
Answer:

Answer: The acceleration doubles

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Explanation:

Consider a mass of 10 kg, so m = 10

Let's say we apply a net force of 20 newtons, so F = 20

The acceleration 'a' is...

F = ma

20 = 10a

20/10 = a

2 = a

a = 2

The acceleration is 2 m/s^2. Every second, the velocity increases by 10 m/s.

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Now let's double the net force on the object

F = 20 goes to F = 40

m = 10 stays the same

F = ma

40 = 10a

10a = 40

a = 40/10

a = 4

The acceleration has also doubled since earlier it was a = 2, but now it's a = 4.

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In summary, if you double the net force applied to the object, then the acceleration doubles as well.

Answer 2
Answer:

Acceleration is directly proportional to the net force on an object, and inversely proportional to its mass.

So if an object's mass stays the same while the net force on it doubles, then its acceleration will also double.

We don't know anything about the "trials".  This sounds like it might be a follow-up to a lab experiment that was performed when we weren't there.

We also don't know anything about "question 1".


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A speed versus time graph is shown:15.
Which statement accurately describes the motion of the object in the graph above? Options: Option 1: It is moving from 0s to 4s at a constant speed of 2 cm/s. Option 2: It is at rest for 4 seconds from 4s to 8s and then speeds up. Option 3: It is moving from 4s to 8s at a constant speed of 4 cm/s. Option 4: It is speeding up from 0s to 4s, then it is at rest.

Answers

Option 3: It is moving from 4s to 8s at a constant speed of 4 cm/s.

Linus builds an electrical circuit with a battery and with wires that carry the current. As the battery weakens, the current also weakens. How does this affect the magnetic field around the wires? A. The field gets stronger.

B. The field gets weaker.

C. The field changes direction.

D. The field disappears completely.

Answers

Answer: The correct answer is option (B).

Explanation:

The current carrying wire produces the magnetic field around it. More the current in the wire, stronger will be the magnetic strength around the wire. The magnetic field is stronger near this wire.

The direction of the magnetic field depends on the direction of the current.

In the given problem, Linus builds an electrical circuit with a battery and with wires that carry the current.The strength of the magnetic field depends on the amount of current flowing in the wire.  As the battery weakens, the current also weakens.

Therefore, the magnetic field around the wires is weaker.

The magnetic field getting weaker is the correct answer when Linus builds an electrical circuit with a battery and with wires that carry the current. The correct answer is (B).

The strength of the magnetic field around the wires is directly proportional to the current flowing through the wires. As the battery weakens and the current decreases, the magnetic field strength around the wires also decreases.

Conversely, if the current increases, the magnetic field strength increases. This relationship is described by Ampere's law and the right-hand rule, which state that the magnetic field is directly proportional to the current.

Therefore, The correct answer is (B). The magnetic field getting weaker is the correct answer.

To know more about the magnetic field:

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What is the approximate diameter of an inflatedbasketball?
(1) 2 × 10^–2 m (3) 2 × 10^0 m
(2) 2 × 10^–1 m (4) 2 × 10^1 m

Answers

The approximate diameter of an inflated basketball is 2 × 10^–2 m. The answer is number 1. The rest of the choices do not answer the question above because they are too big for the diameter of the basketball.

a cylinder of mass 34.5 kg rolls without slipping on a horizontal surface. At a certain instant, its center of mass has a speed 9.5 m/s. Determine the rotational kinetic energy

Answers

Answer:

\displaystyle 778,40625\:J

Explanation:

\displaystyle (1)/(2)mv^2 = KE

* For cylinders, it is unique. Since you have two circular bases, you take half the mass in the formula:

\displaystyle (1)/(4)mv^2 = KE \n \n (1)/(4)[34,5]9,5^2 = KE → \displaystyle (1)/(4)[34,5][90,25] = 778,40625\:J

I am joyous to assist you anytime.

Answer:

778 J

Explanation:

Rotational energy is:

RE = ½ Iω²

For a solid cylinder I = ½ mr².

Rolling without slipping means ω = v/r.

RE = ½ (½ mr²) (v/r)²

RE = ¼ mv²

Plug in values:

RE = ¼ (34.5 kg) (9.5 m/s)²

RE ≈ 778 J

Round as needed.

5. A graduated syringe contains air. It is put in a freezer to cool it down. When it is removed from the freezer the piston has moved inwards. A. B. C. D. cm 3 cm 0.6 kg/m³ 1.2 kg/m³ 2.4 kg/m³ 4.8 kg/m³ 2 3 The density of the air in the syringe when cooled is 2.4 kg/m³. What was the density of the air at room temperature? piston syringe when cooled syringe at room temperature​

Answers

Answer:

The change in the density of the air inside the syringe is due to the change in temperature. When the air inside the syringe is cooled, it contracts, causing the density to increase.

The principle that explains this phenomenon is known as Charles's Law, which states that the volume of a gas is directly proportional to its temperature, provided the pressure and the amount of gas remain constant.

In this case, the density of the air doubles when the syringe is cooled, implying that the volume of the air inside the syringe is halved. Therefore, if the density of the air when cooled is 2.4 kg/m³, the density of the air at room temperature (when the volume is twice as much) would have been half of this value, or 1.2 kg/m³.

So, the density of the air at room temperature was 1.2 kg/m³.

In which state of matter are particles packed tightly together and stay in fixed positions?

Answers

solid..................