MATHEMATICS COLLEGE

The orange shape is a dilation of the black shape. What is the scale factor of the dilation?1/10 1/2 10 2

Answers

Answer 1

Answer:

Scale = ¼

Step-by-step explanation:

See attachment for complete question.

In the attached, we have.

Width = 4 units. ----- Orange

Width = 16 units ------- Black

Required

Determine the scale of dilation

The scale of dilation can be calculated as:

Scale = Width(orange)/Width (black)

Scale = 4/16

Scale = ¼

Hence, the scale of dilation is ¼

Related Questions

True or False 100% of any number must greater than orequal to 100
Cual es el termino, coeficiente, constante y el factor de las siguientes expresiones a. 12a^3 + 16a +4b. 21x^2 + 3x - 15x^2 + 9
Help PLEASE!!!!!!!If BD bisects angle ABC, measure of DBC = 79 degrees, and measure of angle ABC= 9x-4, find the value of x.
A motorist left Lagos at 11:30 am and arrived at Ibadan at1:30pm. If the distancebetween Lagos & Ibadan is168km, what was the averagespeed of the motorist?
I need these please

Scarlett is playing a video game. She spends 900 minerals to create 18 workers. Each worker costs the same number of minerals.

Answers

Answer: m=50w

Step-by-step explanation:

When you divide 900 by 18, you get 50.

Since we are trying to find the amount of minerals per worker, m is the first variable. w is the second because that is the number of workers you can get with the minerals Scarlett has.

So you would do 900÷18 to get the amount each worker is worth, which would be 50 minerals.

A plant produces 500 units/hour of an item with dimensions of 4” x 6” x 2”. The manager wants to store two weeks of supply in containers that measure 3 ft x 4 ft x 2 ft. (Note: She can store the units in the containers such as that the 4” dimension aligns with either the 3 ft width or the 4 ft length of the box, whichever allows more units to be stored.) A minimum of 2 inches of space is required between adjacent units in each direction. If the containers must be stacked 4-high, and the warehouse ceiling is 9 feet above the floor, then determine the amount of floor space required just for storage.

Answers

Answer:

564 ft²

Step-by-step explanation:

To account for the extra space between units, we can add 2" to every unit dimension and every box dimension to figure the number of units per box.

Doing that, we find the storage box dimensions (for calculating contents) to be ...

3 ft 2 in × 4 ft 2 in × 2 ft 2 in = 38 in × 50 in × 26 in

and the unit dimensions to be ...

(4+2)" = 6" × (6+2)" = 8" × (2+2)" = 4"

A spreadsheet can help with the arithmetic to figure how many units will fit in the box in the different ways they can be arranged. (See attached)

When we say the "packing" is "462", we mean the 4" (first) dimension of the unit is aligned with the 3' (first) dimension of the storage box; the 6" (second) dimension of the unit is aligned with the 4' (second) dimension of the storage box; and the 2" (third) dimension of the unit is aligned with the 2' (third) dimension of the storage box. The "packing" numbers identify the unit dimensions, and their order identifies the corresponding dimension of the storage box.

We can see that three of the four allowed packings result in 216 units being stored in a storage box.

If storage boxes are stacked 4 deep in a 9' space, the 2' dimension must be the vertical dimension, and the floor area of each stack of 4 boxes is 3' × 4' = 12 ft². There are 216×4 = 864 units stored in each 12 ft² area.

If we assume that 2 weeks of production are 80 hours of production, then we need to store 80×500 = 40,000 units. At 864 units per 12 ft² of floor space, we need ceiling(40,000/864) = 47 spaces on the floor for storage boxes. That is ...

47 × 12 ft² = 564 ft²

of warehouse floor space required for storage.

_____

The second attachment shows the top view and side view of units packed in a storage box.

Write the prime factorization of 20 using exponents

Answers

Prime factorization expresses an integer in terms of multiples of prime numbers. The prime factorization of 20 using exponents can be written as 2²×5¹.