MATHEMATICS HIGH SCHOOL

The area of a rectangular field is 6688 m squared if the length of the field is 88m what is the width

Answers

Answer 1
Answer:

Answer:

76m

Step-by-step explanation:

You divide 6688 by 88 and your answer will be 76.

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If √6 is the geometric mean between 4 and another number, then the number is

Answers

If you have two numbers x, y.  The geometric mean is:  √xy

For 4 and x.  Geometric Mean =  √4x  and this is equal to √6

             √4x  =  √6     Square both sides.  The square root disappears.

               4x = 6 
                 x  = 6/4 = 3/2 = 1.5

The other number is 1.5.

 

9 gal/s=______at/min

Answers

9 gal............................................................1second
?how many gallons......................................60 seconds(1min)

to find out you do 9*60=540 gallons per minute
9 gals/second
xgals/minute
1 minute=60 seconds
xgals/60 seconds=9gals/1 second
x/60=9/1
solve for x
x/60=9/1
x/60=9
multily both sides by 60 to clear fraciton
x times 60/60=9 times 60
x times 60/60=x times 1=x

x=540

the answer is 540 gallons per minute

Convert 4 . 5 4.5 yards to inches. 4.5 yd = __ in. 4.5 yd = __ in.O A.1.5
O B.54
O C.144
O D.162


help!!!!!!!!

Answers

Answer:

C. i think

Step-by-step explanation:

What is the value of SZT?

Answers

Answer:

\boxed{m \angle SZT = 121 \degree }

Given:

m \angle RZT = 137 \degree \n m\angle RZS = 56 \degree

Step-by-step explanation:

= > m \angle RZT = m\angle RZS + m \angle SZT \n \n = >157 \degree = 36 \degree+ m \angle SZT \n \n = > 157 \degree - 36 \degree = m \angle SZT \n \n = > 121 \degree = m \angle SZT \n \n = > m \angle SZT = 121 \degree

Which corresponds to the perimeter of triangle ABC?A (-5,-1)
B (-2,3)
C (6,-3)


A. 15 units
B. square root 250 units
C.15+ square root 125 units
D.125+ square root 125 units

Answers

Answer:

The answer to your question is: letter C

Step-by-step explanation:

Data

A (-5 , -1)

B (-2, 3)

C (6, -3)

Perimeter = ?

Formula

d = \sqrt{(x2 - x1)^(2) + (y2 - y1)^(2) }

distance AB      d = \sqrt{(-2 + 5)^(2) + (3 + 1)^(2) }

                         d = \sqrt{(3)^(2) + (4)^(2) }

                         d = √((9 + (16) )

                                 d = √(25)

                                        d = 5

Distance BC    d = \sqrt{(-3 - 3)^(2) + (6 + 2)^(2) }

                         d = \sqrt{(-6)^(2) + (8)^(2) }

                         d = √(36 + 64)                    

                         d = √(100)

                                d = 10

Distance AC     d = \sqrt{(-3 + 1)^(2) + (6 + 5)^(2) }

                         d = \sqrt{(-2)^(2) + (11)^(2) }

                         d = √(4 + 121)

                         d = √(125)

                                d = 11.2

Perimeter = 5 + 10 + 11.2

                = 15 + √(125)

What is the volume of a four- sided pyramid with base edge of 5 ft and h = 4 ft.

Answers

V = (5^(2) * 4)/3 = 100/3;

Answer:

da

Step-by-step explanation:
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