Answers
Answer: wavelength =3.52m
Explanation:
,λ=c/μ
where c=speed of the light,λ=wave length, μ=frequncy
c=3x10^8m/s
And
μ=83.5/MHz =85.3x10^6Hz==85.3x10^6Hz=
=85.3x10^6s-1
λ=c/μ
=3x10^8m/s/85.3x10^6s-1
=3.51699883
=3.52m
Related Questions
A rock is thrown vertically upward from some height above the ground. It rises to some maximum height and falls back to the ground. What one of the following statements is true if air resistance is neglected? The acceleration of the rock is zero when it is at the highest point. The speed of the rock is negative while it falls toward the ground. As the rock rises, its acceleration vector points upward. At the highest point the velocity is zero, the acceleration is directed downward. The velocity and acceleration of the rock always point in the same direction.
What is the weight of a 45 kg box?
A crystalline grain of nickel in a metal plate is situated so that a tensile load is oriented along the [111] crystal direction (a) If the applied stress if 0.45 MPa, what will be the resolved shear stress, tRss, along the [101] direction within the (11 T) plane? (b) What tensile stress is required to produce a critical resolved shear stress, TcRss of 0.242 MPa
What is required for a sound wave to be reflected?
Answers
Answers
Answer:
The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C, but the direction is still to the right.
Explanation:
From coulomb's law, F = Eq
Thus,
F = E₁q₁
F = E₂q₂
Then
E₂q₂ = E₁q₁
where;
E₂ is the external electric field due to second test charge = ?
E₁ is the external electric field due to first test charge = 4 x 10⁶ N/C
q₁ is the first test charge = 13 mC
q₂ is the second test charge = 23 mC
Substitute in these values in the equation above and calculate E₂.
The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C when 13 mC test charge is replaced with another test charge of 23 mC.
However, the direction of the external field is still to the right.
Answers
You draw 3 circles around the stations with the size of the circle equal to the distance from the earthquake. Then you simply find where the edge circles all overlap.
B. decreases.
C. stays the same.
D. It depends on the exact type of electromagnetic wave.
Answers
At the time when the frequency of an electromagnetic wave increases, its energy increased.
The following information should be considered:
- When the electromagnetic wave increases so the energy should be increased.
- Due to all this, the speed, wavelength all should be decreased.
Therefore we can conclude that At the time when the frequency of an electromagnetic wave increases, its energy increased.
Learn more: brainly.com/question/6201432
I hope I was able to satisfyingly answer your question. :)
G = 6.67 x 10-11 Nm2/kg2
a. Calculate the value of the gravitational force between an electron (mass = 9.11 x 10-31 kg) and a proton (mass is 1836 times greater than the mass of an electron) if the two particles are separated by 3.602 nanometers. (1 nanometer or 1 nm = 1 x 10-9 m)
F= ______ N
b. The force created in the above question is:
1. repulsive
2. attractive
Answers
Answer:
a.
b.Attractive
Explanation:
We are given that
Mass of an electron,
Mass of proton,
Distance between electron and proton,R=
a.Substitute the values then we get
b.We know that like charges repel to each other and unlike charges attract to each other.
Proton and electron are unlike charges therefore, the force between proton and electron is attractive.
Why does the balloon stick to the
wall?
Answers
Answer:
The balloon is electrostatically charged
Explanation:
After rubbing it on the hair, the balloon is electrically charged, and as such, when approaching the wall it draws opposite charges from the wall creating locally on the wall's surface an accumulation of the charges opposite to the balloon . and repelling deeper into the wall those charges of the same sign.