Solve each equation by factoring.
1) a^2- 9a + 14 = 0
Solve each equation by factoring. 1) a^2- 9a + 14 - 1

Answers

Answer 1
Answer: it’s c [7,2] for sure! :)

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2 + 2 + 6 / 9 ^2 + 600 + 2400 + 45 - 42

Answers

4 + 6/81 + 3000 + 3 = 3007 + 2/27 = 3007 + 0.07 = 3007.07;

Answer:

Step-by-step explanation:

3000.07

What is the product of -9 and -15?
135
-135
-24
24

Answers

-9 * (-15) = 135
it's positive 135 because when you have negative time a negative it's always positive.

Answer:

Please mark me brainliest and I hope this helped!

135

Step-by-step explanation:

The product of something is what the outcome is when you multiply the numbers together. Since 9 and 15 are both negatives, they cancel each other out and become positives. Then we just multiply 9 and 15. That gives us 135.

Use the Factor Theorem to determine whether the first polynomial is a factor of the second polynomial. x - 5; 3x2 + 7x + 40

Answers

Answer:

The polynomial (x -5) is not a factor of second polynomial 3x^2 + 7x + 40

Step-by-step explanation:

Factor theorem states that if you divide a polynomial p(x) by a factor x -a of that polynomial, then you will get a zero remainder.

i.,e p(x) = (x-a)q(x)   which means that if x - a is a factor of p(x), then the remainder, when we do synthetic division by  x= a, will be zero.

Determine whether the first polynomial is a factor of the second polynomial.

Given the polynomial:  f(x)=3x^2 + 7x + 40

For  x-5 to be a factor of f(x)=3x^2 + 7x + 40, the factor theorems implies that x = 5 must be a zero of f(x).

Now, to test whether x-5  is a factor;

Set x -5 = 0

⇒x = 5

Then,

we will use synthetic division method to divide f(x) by x =5

you can see the figure as shown below in the attachment.

Since, the remainder is 150 which is not equal to zero, then Factor theorem says that (x-5) is not a  factor of 3x^2 + 7x + 40



Answer:

No,(x-5) is not a factor of 3x^2+7x+40

Explanation:

Factor theorem states that if (x-a) is a factor of the function f(x) then f(a) = 0.

We can use this theorem to check whether a polynomial is a factor of other polynomial or not.

Further Explanation:

Here, we have to check if (x-5) is a factor of 3x^2+7x+40 or not.

For this we can use the above mentioned factor theorem.

In our case,

a = 5

and f(x)=3x^2+7x+40

So, we find f(5) and see if it is zero or not. If f(5) = 0 then (x-5) must be the factor the polynomial.

f(5)=[tex]3(5)^2+7(5)+40\n\n=75+35+40\n\n=150\neq0

Since, f(5) is not zero. Hence, from factor theorem, (x-5) is not a factor of 3x^2+7x+40

Learn More:

brainly.com/question/12482195 (Answered by Kudzordzifrancis)

brainly.com/question/11378552 (Answered by Alinakincsem)

Keywords:

Factor theorem, Remainder theorem.

Write "P (x) = -36x^2 + 900x - 1584" in standard vertex form, help please!

Answers

y = a(x – h)2 + k, where (h, k) is the vertex;

in our case, P(x) = a
(x + b/2a)^(2) - Δ/4a ;

a = -36; b = 900; c = -1584;

b/2a = 900/-72 = -12.5;

Δ = b^(2) - 4ac = 810000 - 144*1584 = 581904 => -Δ/4a = 4041;

P(x) = (-36)(x - 12.5)^2 + 4041, where (12.5 , 4041) is the vertex;


Answer:

y = a(x – h)2 + k, where (h, k) is the vertex;

in our case, P(x) = a Δ/4a ;

a = -36; b = 900; c = -1584;

b/2a = 900/-72 = -12.5;

Δ =  4ac = 810000 - 144*1584 = 581904 => -Δ/4a = 4041;

P(x) = (-36)(x - 12.5)^2 + 4041, where (12.5 , 4041) is the vertex;

Graph (1,1), (1,2), (1,3), (1,4)

Answers

Answer:

There is not a way that I can show you how to graph it, so I will try and explain it.

Step-by-step explanation:

(1,1)

^  ^     y-axis

x-axis

You are just going right however many, and then up however many it says.

So if it's (1,1) you will go right one space, and then up one space.

Once you have all of your points on the graph, you put a line through them.

Hope this helps! :)

Which statements are true about the graph of the function f(x) = x2 - 8x + 5? Select three options.The function in vertex form is f(x) = (x - 4)2 - 11.
The vertex of the function is (-8,5).
The axis of symmetry is x = 5.
The y-intercept of the function is (0.5).
The function crosses the x-axis twice

Answers

The statements that are true about the graph of the function are

  • The function in vertex form is f(x) = (x - 4)^2 - 11.
  • The y-intercept of the function is (0,5).
  • The function crosses the x-axis twice

Vertex and intercept of a function

The standard equation of a function in vertex form is expreseed as:

a(x-h)^2 + k

Given the quadaratic function  f(x) = x^2 - 8x + 5, the expression in vertex form is given as:
f(x) = (x^2-8x + 4^2) - 16 + 5

f(x) = (x-4)^2 - 16 + 5
f(x) = (x-4)^2 - 11

Find the y-intercept.

This is the point here x = 0
f(0) = 0^2 - 8(0) + 5
f(0) = 5

Hence the y-intercept of the function is at (0, 5)

Since the quadratic function has a leading degree of 2, hence the  function crosses the x-axis twice  

Learn more on vertex and intercepts here: brainly.com/question/12778829

Answer:

A, D, E

Step-by-step explanation: