MATHEMATICS HIGH SCHOOL

Solve each of the following equations. a.
24 = -3 + 3n

b.
11 + 4x = x - 10

c.
-216 = 1 + 7(1 + 8m)

d.
3p - 3(2 - 2p) = 34 + 4p

You must show all of your work to receive credit.
I will give you 27 points if you solve this by showing your work plz

Answers

Answer 1
Answer:

Answer:

A) n=9

B)X=-7

C)m=-4

D)P=8

Step-by-step explanation:

A)24=-3+3n

move variable to the lefthand side &change its sign

-3n+24=-3

move the constant to the righthand side &change its sign

-3n=-3-24

calculate the difference

-3n=-27

devide both sides by-3

Solution:

n=9

B)11+4x=x-10

11+4x-x=-10

move variable to the lefthand side &change its sign

4x-x=-10-11

move constant to the righthand &change its sign

4x-x=-10-11

collect like terms

3x=-21

devide both sides of the equation by 3

solution :

x=-7

C)-216=1+7(1+8m)

multiply the parentheses by 7

-216=1+7+56m

add the numbers

-216=8m+56m

move variable to the lefthand side &change its sign

-56m-216=8

move constant to the righthand side &change its sign

-56m=8+216

add the numbers

-56m=224

devide both sides of the equation by -56

solution:

m=-4

D)3p-3(2-2p)=34+4p

multiply the parentheses by -3

3p-6+6p=34+4p

collect like terms

9p-6=34+4p

move the variable to the lefthand side &change its sign

9p-4p-6=34

move the constant to the righthand side &change its sign

9p-4p=34+6

collect like terms &calculate the sum

5p=40

devide both sides by 5

solution:

P=8

HiI hope this helps..

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