Lime your sus you walked past the body but didn't report

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Answer 1

Answer:

Answer:

You Got me im Imposter

Explanation:

Related Questions

Oppositely charged objects attract each other. This attraction holds electrons in atoms and holds atoms to one another in many compounds. However, Ernest Rutherford’s model of the atom failed to explain why electrons were not pulled into the atomic nucleus by this attraction. What change to the atomic model helped solve the problem seen in Rutherford’s model?
Calculate the maximum acceleration of a car that is heading up a 4º slope (one that makes an angle of 4º with the horizontal) under the following road conditions. Assume that only half the weight of the car is supported by the two drive wheels and that the coefficient of static friction is involved—that is, the tires are not allowed to slip during the acceleration. (Ignore rolling.) (a) On dry concrete. (b) On wet concrete. (c) On ice, assuming that μs = 0.100 , the same as for shoes on ice.
True or false. The light bulbs in an office building give off tremendous amounts of heat. Since heat is a form of energy, this heat could be trapped and used to offset our need for electricity, thus saving energy and money.
HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Some people consider the earth to be _____ because of its dynamic processes or cycles.stagnantalivechanging
A compass needle normally points toward Earth’s magnetic pole, which is near the North Pole. Which best explains why the needle moves away from the pole when it comes close to a current-carrying wire?-Current within the wire weakens the magnetic force of the pole. -Magnetism surrounding the wire weakens the magnetic force of the pole. -Magnetism surrounding the wire draws the needle toward the wire.

Compare the charges and masses of protons, neutrons and electrons.

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proton = positive charge (relative mass of 1836)

neutron = neutral or no charge (relative mass of 1839)

electron = negative charge (relative mass of 1)

What causes light to bend when it moves from one transparent medium to another?a change in amplitude

a change in color

a change in frequency

a change in speed

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Answer: The correct answer is - change in speed.

When light travels from one transparent medium to another transparent medium, it bends and this phenomenon is known as refraction.

It is caused due to difference in the speed of light in different medium as speed of light is slow in a denser medium (like water) whereas speed is faster in a lighter medium (like air).

change in speed is the answer

Choose the false statement regarding resistance. A) Longer wires have less resistance. B) Electrical resistance produces heat. C) Resistance slows the flow of current. D) The larger the diameter of the wire, the less resistance.

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The answer would be:

A. Longer wires have less resistance.

Here is why:

The statement is false because longer wires tend to have greater resistance. Look at the formula of resistance below:

$R=(\rho L)/(A)$

ρ = resistivity

L = length

A = cross-sectional area

As you can see Length of the wire is directly proportional to the resistance, which means as the Length increases, the Resistance increases.

Answer:

A. Longer wires have less resistance.

Explanation:

The height of the Empire State Building is 318.00 meters. If a stone is dropped from the top of the building, what is the stone's velocity just before it strikes the ground?

Answers

This is a free-fall problem. This can be answered using one of the free-fall equations:

V^2 = 2gh or V = √(2gh)

Where V = velocity ; h = total height (given as 318m) ; g = acceleration due to gravity (as this is on Earth, let us use 9.8 m/s^2)

With the given values, we can substitute it into the equation directly like so:

V = √(2gh)
V = √(2 x 9.8 x 318)
V = √(6232.8)
V = 78.94808 or approximately 78.95 m/s

Therefore the stone's velocity just before hitting the ground is 78.95 m/s.

A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7 1010 m (inside the orbit of Mercury), at which point its speed is 9.5 104 m/s. Its farthest distance from the Sun is far beyond the orbit of Pluto. What is its speed when it is 6 1012 m from the Sun? (This is the approximate distance of Pluto from the Sun.)

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Answer:

58515.9 m/s

Explanation:

We are given that

$d_1=4.7* 10^(10) m$

$v_i=9.5* 10^4 m/s$

$d_2=6* 10^(12) m$

We have to find the speed (vf).

Work done by surrounding particles=W=0 Therefore, initial energy is equal to final energy.

$K_i+U_i=K_f+U_f$

$(1)/(2)mv^2_i-(GmM)/(d_1)=(1)/(2)mv^2_f-(GmM)/(d_2)$

$(1)/(2)v^2_i-(GM)/(d_1)+(GM)/(d_2)=(1)/(2)v^2_f$

$v^2_f=2((1)/(2)v^2_i-(GM)/(d_1)+(GM)/(d_2))$

$v_f=\sqrt{2((1)/(2)v^2_i-(GM)/(d_1)+(GM)/(d_2))}$

Using the formula

$v_f=\sqrt{v^2_i+2GM((1)/(d_2)-(1)/(d_1))}$

$v_f=\sqrt{(9.5* 10^4)^2+2* 6.7* 10^(-11)* 1.98* 10^(30)((1)/(6* 10^(12))-(1)/(4.7* 10^(10)))$

Where mass of sun= $M=1.98* 10^(30) kg$

$G=6.7* 10^(-11)$

$v_f=58515.9 m/s$

Two charged objects, A and B, exert an electric force on each other. What happens if the distance between them is increased?

Answers

The correct answer to the question will be that the electric force between them will be decreased.

EXPLANATION:

Let us consider the charge contained by A and B are denoted as Q and Q' respectively.

Let R is the separation distance between them.

As per Coulomb's law in electrostatics, the force of attraction or repulsion between the two charge bodies A and B will be -

Coulombic force F = $(1)/(4\pi \epsilon) (QQ')/(R^2)$

Here, $\epsilon$ is the permittivity of the medium in which the charges are present.

From above, we see that electric force is inversely proportional to the square of separation distance between them.

Mathematically it can be written: $F\ \alpha\ (1)/(R^2)$

As per the question, the distance between A and B is increased.

Hence, the electric force between A and B will be decreased.

I agree with Hussein but I would like to add that when the distance between two charged objects increase, the force decreases by the Coulomb` s Law:
F= k * Q1*Q2 / r^2
where k is constant Q1, Q2-quantity of electricity and r- distance between two charged objects. So when you increase r, you divide with greater number and result decreases.
$F=k(q1 * q2)/( r^(2) )$

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