Guys I’ve got 15 minutes to answer all of them please help I’ve been busy with the rest of the problems help !!!!

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

yeah on the first on i got x= 54 but my brain is mush to do the rest sorry my dude

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Answers

Answer:

the answer is ACF

Step-by-step explanation:

A music club has 35 drum players. If 25% of the total number of members in the club are drum players, what is the total number of members in the club?60
70
120
140

Answers

So, all we have to do for this is
1. Turn the percent into a decimal. 25%=0.25
2. Divide the whole number by the percent. 35/0.25=140

The answer is 140

Answer:

D is the correct answer.

Step-by-step explanation:

What is 5r^2 = 80

It says solve each equation with the quadratic formula.

Answers

$5r^2 = 80 \ \ /:5\n \nr^2=(80)/(5)\n \nr^2=16\n \nr^2-16=0\n \n r^2 - 4^2 =0 \n \n(r-4)(r+4)=0$

$r-4=0 \ \ \vee \ \ r+4 =0 \n \nr=4 \ \ \vee \ \ r = -4 \n \n \n a^2-b^2 = (a- b)(a+b)$

Write an inequality to represent the phrase: The sum of a number and 7 is no more than 53.

Answers

n+7≤53

The sum of a number, which I have named 'n', and 7 can be written as the expression:

n+7

remember the word 'is' in a written problem indicates where you'll most likely use an =,≥,≤ sign. Since they say that it is 'no more than' we know that n+7 is less than or equal to the given number, so we use '≤'.

n+7≤

the number it is less than or equal to is 53, so now we have the completed inequality of:

n+7≤53

sum means add
a number=x
7=7
is no more than, means is equal to or less than aka <
53=53

x+7<53

The function y = -0.03(x - 14)^2 + 6 models the mump of a red kangaroo where x is the horizontal distance in meters and y is the vertical distance in meters for the height of the jump. What is the kangaroo's maximum height? How long is the kangaroo's jump?

Answers

From the vertex of the quadratic equation, we find that: The kangaroos maximum height is of 6 meters.

From the roots of the equation, we find that: The kangaroo's jump is 28.14 meters long.

----------------------------

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

$f(x) = ax^(2) + bx + c$

It's vertex is the point $(x_(v), y_(v))$

In which

$x_(v) = -(b)/(2a)$

$y_(v) = -(\Delta)/(4a)$

Where

$\Delta = b^2-4ac$

If a<0, the vertex is a maximum point, that is, the maximum value happens at $x_(v)$ , and it's value is $y_(v)$ .

----------------------------

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^(2) + bx + c, a\neq0$ .

This polynomial has roots $x_(1), x_(2)$ such that $ax^(2) + bx + c = a(x - x_(1))*(x - x_(2))$ , given by the following formulas:

$x_(1) = (-b + √(\Delta))/(2*a)$

$x_(2) = (-b - √(\Delta))/(2*a)$

$\Delta = b^(2) - 4ac$

----------------------------

The quadratic equation is:

$y = -0.03(x - 14)^2 + 6$

Placing in standard form:

$y = -0.03(x^2 - 28x + 196) + 6$

$y = -0.03x^2 + 0.84x + 0.12$

Thus, it has coefficients $a = -0.03, b = 0.84, c = 0.12$

----------------------------

The kangaroo's maximum height is the y-value of the vertex, thus:

$\Delta = b^2 - 4ac = (0.84)^2 - 4(-0.03)(0.12) = 0.72$

$y_(v) = -(\Delta)/(4a) = -(0.72)/(4(-0.03)) = 6$

The kangaroos maximum height is of 6 meters.

----------------------------

The length of the kangaroo's jump is the positive root. The roots are found at the values of x for which y = 0, thus, the solutions of the quadratic equation.

$x_(1) = (-0.84 + √(0.72))/(2(-0.03)) = -0.14$

$x_(2) = (-0.84 - √(0.72))/(2(-0.03)) = 28.14$

The kangaroo's jump is 28.14 meters long.

A similar question is given at brainly.com/question/16858635

Answer:

Kangaroo's maximum height is 6 m and the kangaroo's jump is 28 m long

Step-by-step explanation:

Given : $y = -0.03(x - 14)^2 + 6$

To Find : What is the kangaroo's maximum height? How long is the kangaroo's jump?

Solution:

$y = -0.03(x - 14)^2 + 6$

x is the horizontal distance in meters

y is the vertical distance in meters for the height of the jump.

Substitute y = 0

$0 = -0.03(x - 14)^2 + 6$

$0.03(x - 14)^2 = 6$

$(x - 14)^2 = (6)/(0.03)$

$(x - 14)^2 =200$

$(x - 14) =√(200)$

$(x - 14) =14.142$

$x =14.142+14$

$x =28.142$

x≈ 28 m

Now the maximum height will be attained at mid point i.e. $(28)/(2) =14$

Now substitute x= 14

$y = -0.03(14 - 14)^2 + 6$

$y = 6$

So, kangaroo's maximum height is 6 m and the kangaroo's jump is 28 m long

John has a job transporting soft drinks by truck. his truck is filled with cans that weigh 14 ounces each and bottles that weigh 70 ounces each. there is a combined total of 820 cans and bottles in his truck. let x be the number of 14 -ounce cans in his truck. write an expression for the combined total weight

Answers

14x + 70y = 820. Where we have taken y to be the number of bottles and x to be the number of cans.

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