MATHEMATICS HIGH SCHOOL

URGENT WILL GIVE 20 POINTS AND BRAINLIEST:If the BASE ANGLES of an isosceles triangle ARE 44 degrees, what is the measure of the VERTEX ANGLE?

Answers

Answer 1

Answer:

Answer:

92 degrees

Step-by-step explanation:

2(44)= 88

180-88= 92

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Find the value of the expression log27√3

Answers

$\log _( 27 ){ \left( \sqrt { 3 } \right) } \n \n =\frac { \log _( 3 ){ \left( \sqrt { 3 } \right) } }{ \log _( 3 ){ \left( 27 \right) } }$

$\n \n =\frac { \log _( 3 ){ \left( { 3 }^{ \frac { 1 }{ 2 } } \right) } }{ 3 } \n \n =\frac { \frac { 1 }{ 2 } \log _( 3 ){ 3 } }{ 3 } \n \n =\frac { \frac { 1 }{ 2 } }{ 3 }$

$\n \n =\frac { 1 }{ 2 } \cdot \frac { 1 }{ 3 } \n \n =\frac { 1 }{ 6 }$

$\log_(27)\sqrt3=(\log_3\sqrt3)/(\log_327)=((1)/(2))/(3)=(1)/(6)$

A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as editing) and variable costs (such as printing). The one-time fixed costs will total $60,239
. The variable costs will be
$10.50
per book. The publisher will sell the finished product to bookstores at a price of
$25.25
per book. How many books must the publisher produce and sell so that the production costs will equal the money from sales?

Answers

so the total=60239
so 10.5 per book
but -25.25 per book (since this is a negative cost or a gain)
so lets say they sell 1 book
it cost 10.5 and they gain 25.25 so they gain 14.75 total per book

so 14.75 times x books=60239
divide both sdies by 14.75
x=60239/14.75
then divide 60239 by 14.75 and get x=4084
they will need to sell 4084 books

assume the number of books X

the cost of the books = 60.239 + (10.50 X)
the sale amount = 25.25 * X

so 60.239 + 10.5 X = 25.25 X
60.239 = (25.25 - 10.5)X
60.239 = 14.75 X
X = 60.239 / 14.75

So X = 4.084
so the publisher needs to sell 4 books

What is the factored form of 3c²+24c+48 ?

Answers

1st step factor 3 out of each number in the equation to get:

3(c^2+8c+16)

16 can be rewritten as 4^2 to get:
3(c^2+8c+4^2)

4+4 = 8 ( the middle number)

so the factor would be 3(c+4)^2

A⁴+b⁴=a²b² ,prove that a⁶+b⁶=0

Answers

$a^4+b^4=a^2b^2\n a^4-a^2b^2+b^4=0\n a^4-2a^2b^2+b^4+a^2b^2=0\n (a^2+b^2)^2=-a^2b^2$

The only possible option is that $a^2+b^2=0 \wedge a^2b^2=0\n$ and this condition is met only when $a=0 \wedge b=0$ .

$0^6+0^6=0\n 0=0$

The average high temperature in Anchorage, Alaska, in January is 21°F with a standard deviation of 10°. The average high temperature in Honolulu in January is 80°F with a standard deviation of 8°. In which location would it be more unusual to have a day in January with a high of 57°F?