MATHEMATICS HIGH SCHOOL

Clare and Han have summer jobs stuffing envelopes for two different companies. Clare's earnings can be seen in the table.

Number of Envelopes Money in Dollars
400 40
900 90
Han earns $15 for every 300 envelopes he finishes.

a. Who would make more money stuffing 1500 envelopes?

How much more would they make? $ more

b. What is the rate of change for each situation.

Clare = per

Hans = per

c. Who gets pair more in their job?

gets paid more.

Answers

Answer 1

Answer:

Answer:

yes

Step-by-step explanation:

15 x 300 = 7500

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What is the elapsed time between 2:16 am to 8:10pm

Paolo pays $244 for 5 indentical calculators. About how munh dose paolo pay for one calculators?

Answers

Hello ;)

244÷5= 48,8

So the result is: $48,8

LOOK, 25 POINTS Y'ALLthis is a logic-math combo question that was from my 5th grade math book (singapore math). just for fun. I never solved it on my own. MUST SHOW ALL WORK

there are 4 single digit whole numbers represented by A, B, C, D. They are all different numbers.

when you multiply ABCD with D, you get DCBA

solve for the values of A,B,C, and D

(note: if A=2,B=3,C=4,D=5 then ABCD=2,345, but that is not the solution)

Show all work and do not copy

Answers

To start, ABCD(D)=DCBA means that D×A=D because they're all single digit numbers and since nothing carries over to make DCBA a 5 digit number A must be 1. If A is 1 for ABCD(D)=DCBA that would mean D^2 is a number ending in 1 so the only possibility for D is 9. Since D is 9, D×B has to be less than 10 because we know nothing carries over to the D×A (9×1) so B has to be 0. So far we have 10*9(9)=9*01 and since D×D (9×9) is 81 we need a number divisible by 9 that ends with 2 to add to the 8 digit which the only possibility is 72 from 8×9. SO A=1, B=0, C=8, D=9
1089(9)=9801

Josh spent $30 at the movies. 1/5 was spent on a drink, 45% on a ticket and the rest on food. How much did he spend on food?

Answers

Answer:

$10.5

Step-by-step explanation:

Given data

Total amount=$30

Drink = 1/5*30= $6

Ticket= 45% of 30

=45/100*30

=0.45*30

=$13.5

The remainder is for food

=30-6-13.5

=$10.5

Ethan stands 256 cm at point C from a lamp post AB. He is 180 cm tall and his shadow from the lamp is 144 cm long. Find the height AB, in metres, of the lamp post.

Answers

Answer:500 cm

Step-by-step explanation:

Given

height of ethan = 180 cm

length of shadow =144 cm

Distance of ethan from lamp =256 cm

from diagram, we can write

$\Rightarrow tan \theta =(FC)/(EC)\quad \ldots(i)$

$\Rightarrow \tan \theta =(AB)/(BE)\quad \ldots (ii)$

From (i) and (ii) we get

$\tan \theta =(FC)/(EC)=(AB)/(BE)$

$\Rightarrow (180)/(144)=(h)/(144+256)$

$\Rightarrow h=(180)/(144)* 400$

$\Rightarrow h=500\ cm$

So, height of lamp post AB is $500\ cm$

Weather records show that the probability of rainfall in Florida in June is 0.86. What is the probability that it rains there in June at least 9 times in a decade?

Answers

0.5816 = 58.16% probability that it rains there in June at least 9 times in a decade.

For each June 9 in Florida, there are only two possible outcomes. Either it rains, or it does not. The probability of raining on June 9 of an year is independent of rain on June 9 on any other year, which means that the binomial probability distribution is used to solve this question.

---------------------------------------

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)$

In which $C_(n,x)$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_(n,x) = (n!)/(x!(n-x)!)$

And p is the probability of X happening.

---------------------------------------

0.86 probability of rain means that $p = 0.86$
A decade means 10 years, so $n = 10$

---------------------------------------

What is the probability that it rains there in June at least 9 times in a decade?

This is:

$P(X \geq 9) = P(X = 9) + P(X = 10)$

In which

$P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)$

$P(X = 9) = C_(10,9).(0.86)^(9).(0.14)^(1) = 0.3603$

$P(X = 10) = C_(10,10).(0.86)^(10).(0.14)^(0) = 0.2213$

Thus

$P(X \geq 9) = P(X = 9) + P(X = 10) = 0.3603 + 0.2213 = 0.5816$

0.5816 = 58.16% probability that it rains there in June at least 9 times in a decade.

A similar question is found at brainly.com/question/9631195

R - it is rain (probablity: 0.86)
N - it is not rain (probablity: 1-0.86 = 0.14)
You've got these cases:

R R R R R R R R R N
R R R R R R R R N R
R R R R R R R N R R
. . .
N R R R R R R R R R - it is 10 cases. Probablity each case is
(0.86)^9 * 0.14 - it is approximately 0.036 (9R and 1N - you multiply everything)

It is 10 cases so you have to multiply by 10 and you get 0.36

There is also eleventh case:

R R R R R R R R R R

Probablity is (0.86)^10 approximately 0.22

Add these cases and you'll get your probablity: 0.36 + 0.22 = 0.58

If (x, 1/100) lies on the graph of y = 10x, then x =

2
-1/2
-2