MATHEMATICS HIGH SCHOOL

The lengths of the sides of a quadrilateral are 4 consecutive even integers. The perimeter of the quadrilateral is 36 inches. What is the length of the longest side?\WILL GIVE BRAINLIEST
NEED THIS ASAP

Answers

Answer 1

Answer:

Answer:

The length of the longest side is 9 inches

Step-by-step explanation:

The given parameters for the quadrilateral is that the length of the sides are;

The length of the sides are consecutive integers = x, x + 2, x + 4, x + 6

The perimeter of the rectangle = 36 inches

The side length to be found = The length of the longest side = x + 3

2 6 10 14 18

∴ x + x + 2 + x + 4 + x + 6 = 36

4·x + 12 = 36

4·x = 36 - 12 = 24

4·x = 24

x = 24/4 = 6

x = 6 inches

The length of the longest side = x + 3 = 6 + 3 = 9

The length of the longest side = 9 inches.

Answer 2

Answer:

Answer:

The length of the longest side is 9 inches

Step-by-step explanation:

The given parameters for the quadrilateral is that the length of the sides are;

The length of the sides are consecutive integers = x, x + 2, x + 4, x + 6

The perimeter of the rectangle = 36 inches

The side length to be found = The length of the longest side = x + 3

2 6 10 14 18

∴ x + x + 2 + x + 4 + x + 6 = 36

4·x + 12 = 36

4·x = 36 - 12 = 24

4·x = 24

x = 24/4 = 6

x = 6 inches

The length of the longest side = x + 3 = 6 + 3 = 9

The length of the longest side = 9 inches.

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John bought an odd shaped lot that was 100 feet deep, but the front footage was 160 feet and the length of the back side of the lot was 80 feet what is the square footage of his lot?

Answers

Answer:

12000 $ft^(2)$

Step-by-step explanation:

The lot has the shape of a trapezoid. This means that the area can be find using the formula:

$Area= ((B_(1)+B_(2))/(2))h$

Where $B_(1)$ and $B_(2)$ are the two paralle sides (in this case the front side of 160 feet and, the back side of 80) and, h is the height (the deep of 100 feet). So :

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Two airplanes left the same airport and arrived at the same destination at the same time. The first airplane left at 8:00 a.m. and traveled at an average rate of 496 mph. The second airplane left at 8:30 a.m. and traveled at an average rate of 558 mph. How many hours did it take the first plane to travel to the destination?Let x represent the number of hours that the first plane traveled.
Enter an equation that can be used to solve this problem in the first box.
Solve for x and enter the number of hours in the second box.

Answers

First plane: 496x
Second plane: 558( x - 1/2)

Equation: 496x = 558( x - 1/2)

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Hope this helps.

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Answers

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Answers

Answer:

40 weeks

Step-by-step explanation:

We must find the relationship between weeks and years. Given that 52 weeks make a year, it means that 3/4 of the year would be equivalent to

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= 39 +1

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now add one week since Shanna attended one week longer

and now you get 37 weeks Shanna attended school

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