MATHEMATICS HIGH SCHOOL

(7n - 5)(5n - 8)
Multiply polynomials

Answers

Answer 1
Answer:

Answer:

35n^2-81n+40

Step-by-step explanation:
Answer 2
Answer:

Answer:

35n^2+81n+40

Step-by-step explanation:

(7n-5)(5n-8)

35n^2-56n-25n+40

35n^2+81n+40

Related Questions

Karin has $3 to spend in the arcade. The game she likes coast 50 cents per play. What are the possible numbers of times that she can play
Can you tell me what is 15-2x=3x
Jeremy drove from Portland to Miami. He determines that the expression 450x + 150 represents the distance in miles he traveled, where x is the number of days after the first day. Which statement describes correctly what the coefficient of x represents?
f (x), has (x-7) and (x+4i) as factors. F(X)=2x^5-13x^4+22x^3-187x^2-160x+336 what is the total number of real numbers of real zeros of f(X)
Miles and Nick each separately apply for and receive loans worth $5,000 apiece. Miles has a very good credit score, so his loan has an APR of 7.75%, compounded monthly. Nick’s credit score is rather low, so his loan has an APR of 13.10% interest, compounded monthly. If both of them repay their loans over a four year period, making equal monthly payments based on their own loan, how much more will Nick have paid than Miles? (Round all dollar values to the nearest cent.) a.$619.68 b.$267.50 c.$1,609.57 d.$1,070.00

10. Reka Rahim is employed at a restaurant. She has family medical coverage through the company's groupmedical plan. The annual cost of Reka's family coverage is $3,700.00. The company pays 35% of the cost. How
much does Reka pay annually for medical insurance?
$3,700.00
$1,295.00
$2,405.00
$4,050.00

Answers

The answer is 2,405.00

What is 47 rounded to the nearest 100

Answers

0. 47 is less than 50 (5), therefore, rounding it to the nearest 100 results in 0.

Solve : 11 (9-v)=0 a) -9 b) 9 c) 99 d)-99

Answers

B. V=9Multiply it out, then subtract 99 from both sides, then divide by 11
the answer would be 9

Terry bought some gum and some candy. The number of packs of chewing gum was one more than the number of mints. The number of mints was three times the number of chocolate bars. If gum cost 6 cents a pack, mints cost 3 cents each, and chocolate bars cost 10 cents each, how many of each confection did he get for 80 cents?

Answers

Mumber of mints=x
Number of packs of chewing gum=x+1
Number of chocolate bars=y

The number of mints was three times the number of chocolate bars; then
x=3y

We can suggest this system of equations:
x=3y
6(x+1)+3x+10y=80

we can solve this system of equations by substitution method.
6(3y+1)+3(3y)+10y=80
18y+6+9y+10y=80
18y+9y+10y=80-6
37y=74
y=74/37
y=2

x=3y
x=3*(2)=6

Number of mints=x=6
number of packs of chewing gum=x+1=6+1=7
number of chocolate bars=y=2

Answer: the number of mints is 6, the number of packs of chewing gum is 7, and the number of chocolate bars is 2.

Answer:

He bought 13 pkgs of gum

He bought 12 mints

He bought 4 candy bars

Step-by-step explanation:

Let +a+ = number of packages of gum Terry bought

Let +b+ = number of mints

Let +c+ = number of candy bars

------------------------------

(1) +a+=+b+%2B+1+

(2) +b+=+3c+

(3) +24a+%2B+10b+%2B+35c+=+572+ ( in cents )

-------------------------------------

There are 3 equations and 3 unknowns, so it's solvable

(2) +c+=+b%2F3+

Substitute (2) into (3)

(3) +24a+%2B+10b+%2B+35%2A%28+b%2F3%29+=+572+

Substitute (1) into (3)

(3) +24%2A%28+b+%2B+1+%29+%2B+10b+%2B+35%2A%28+b%2F3+%29+=+572+

(3) +24b+%2B+24+%2B+10b+%2B+%2835%2F3%29%2Ab+=+572+

Multiply both sides by +3+

(3) +3%2A34b+%2B+3%2A24+%2B+35b+=+3%2A572+

(3) +102b+%2B+72+%2B+35b+=+1716+

(3) +137b+=+1644+

(3) +b+=+12+

and

(1) +a+=+b+%2B+1+

(1) +a+=+12+%2B+1+

(1) +a+=+13+

and

(2) +c+=+b%2F3+

(2) +c+=+12%2F3+

(2) +c+=+4+

---------------------

He bought 13 pkgs of gum

He bought 12 mints

He bought 4 candy bars

-----------------------

check:

(3) +24a+%2B+10b+%2B+35c+=+572+ ( in cents )

(3) +24%2A13+%2B+10%2A12+%2B+35%2A4+=+572+

(3) +312+%2B+120+%2B+140+=+572+

(3) +572+=+572+

OK

Solve for p3(p + q) = p
A. q = -2/3p
B. q = -3/2p
C. p = -2/3q
D. p = -3/2q

Answers

it’s A! hope this helps you out!

1)In a sample of 100 households, the mean number of hours spent on social networking sites during the month of January was 50 hours. In a much larger study, the standard deviation was determined to be 6 hours.
Assume the population standard deviation is the same. What is the 98% confidence interval for the mean hours devoted to social networking in January?

2)Two studies were completed in Florida. One study in northern Florida involved 2,000 patients; 64% of them experienced flu-like symptoms during the month of December.
The other study, in southern Florida, involved 3,000 patients;
54% of them experienced flu-like symptoms during the same month. Which study has the smallest margin of error for a 95% confidence interval?

Answers

So the following is the answer of the following question in your problem and please do not post to many question in just one posting. 
#1 The 98% confidence interval for the mean hours is between 6 and 50.
#2 The smallest margin of error between the two is southern florida with 1.8% margin of error.
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