6thh grade is harddd yall
6thh grade is harddd yall - 1

Answers

Answer 1
Answer:

Answer:

56

Step-by-step explanation:

i recommend using mathaway, type in "4,8,14"

Answer 2
Answer: For 4 the lcm is 2 for 8 the lcm is 4 and for 14 it is seven if I am not wrong

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What is the value of y in the equation 4y – 2(1 – y) = –44?–23–15–14–7
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Henreys earnings over the past three weeks were $525, 575, and 475 what is his average earnings per week?

Write each number as a power of given base.8/27;base 2/3

Answers

Suppose x=log(8/27)with base 2/3

Then,

(2/3)^x=8/27

(2/3)^x=(2/3)^3

So, x=3

Hence, the value of log(8/37) under base 2/3 is 3.



Marisa can buy 3 oranges for 1.35 dollars ,four oranges for $1.80 or five oranges for $2.25 per second by 10 oranges for a price that fits this pattern or a bag of 10 oranges for four dollars and 25 Cents Which Way cost less for 10 oranges explain

Answers

3 oranges= $1.35, so one orange cost $0.45
4 oranges= $1.80, one orange cost $0.45
5 oranges= $2.25, one orange cost $0.45
If one orange cost $0.45, then ten cost $4.50 ($0.45*10)

If you were to buy ten oranges are $4.25, this would make each orange $0.425 ($0.43 rounded).

This means that if you were to buy ten oranges, it would be cheaper to buy ten for $4.25, instead of buying two lots of 5 for $2.25 each.

Hope this helps :) 

Answer:

10 for $4.25 has a better value than 2 bunches of 5 for $2.25 each.

Step-by-step explanation:

3 oranges = $1.35

(1)/(3) :(y)/(1.35)

y × 3 = 1 × 1.35

3y = 1.35

3y ÷ 3 = 1.35 ÷ 3

y = $0.45

4 oranges = $1.80

(1)/(4): (y)/(1.8)

y × 4 = 1 × 1.8

4y = 1.8

4y ÷ 4 = 1.8 ÷ 4

y = $0.45

5 oranges = $2.25

(1)/(5) :(y)/(2.25)

y × 5 = 1 × 2.25

5y = 2.25

5y ÷ 5 = 2.25 ÷ 5

y = $0.45

(1)/(10) :(0.45)/(y)

y × 1 = 0.45 × 10

y = $4.50

(1)/(10) :(y)/(4.25)

y × 10 = 1 × 4.25

10y = 4.25

10y ÷ 10 = 4.25 ÷ 10

y = 0.425

$0.425 ≈ $0.43

Solve using DISTANCE = RATE X TIMEMike left home on his bicycle at 10:00 A.M., traveling at 50 m/h. At noon, he arrived at his destination. How many miles did he drive?

Answers

The rate is speed which 50m/h. so he left the home at 10:00 and arrived at noon which 12:00pm so the difference is 2 hours which means he took 2 hours to get there.
to find the distance. 
D=RxT = 50 x 2 = 100mile
Distance = Rate * Time

The rate he is going at is 50 mph
The time it took is 10 am to 12 pm. That is 2 hours.

Distance = 50 mph * 2 hr

Distance = 100 miles

Mike drove 100 miles.

I need help on number 5

Answers

A fraction is undefined if its denominator is zero, because then it's saying
"Division by zero !" which is a definite no-no.

Can the denominator of the fraction in #5 ever be zero ?

The denominator is a quadratic polynomial.  Do you know
how to solve (a quadratic polynomial) = 0  ?

This problem is even easier than that, because it gives you some choices.
So you don't even have to solve the quadratic equation.  All you have to do
is check out the choices.
Do you see choice of 'x' values that make the denominator zero ?

Big sloppy hint:  Look at choice-E very very carefully.

Is that enough help ?

How do you solve this?

Answers

x^2-3x-4=0\n\nx^2-2x\cdot(3)/(2)=4\ \ \ /+((3)/(2))^2\n\nx^2-2x\cdot(3)/(2)+((3)/(2))^2=4+((3)/(2))^2\n\n(x-(3)/(2))^2=4+(9)/(4)\n\n(x-(3)/(2))^2=(16)/(4)+(9)/(4)\n\n(x-(3)/(2))^2=(25)/(4)\n\nx-(3)/(2)=\pm\sqrt(25)/(4)

x-(3)/(2)=\pm(√(25))/(\sqrt4)\n\nx-(3)/(2)=\pm(5)/(2)\n\nx-(3)/(2)=-(5)/(2)\ or\ x-(3)/(2)=(5)/(2)\n\nx=-(5)/(2)+(3)/(2)\ or\ x=(5)/(2)+(3)/(2)\n\nx=-(2)/(2)\ or\ x=(8)/(2)\n\nx=-1\ or\ x=4
Why not simply factor the left side ?

(x - 4) times (x + 1) = 0

This equation is true if either factor is zero.

(x - 4) = 0
x = 4

(x + 1) = 0
x = -1

Factor this radical expression. 50a^2-10ab/20a^3b^3

Answers

remembe
(ax)/(bx)=(a/b)(x/x)=(a/b)1
find ones aka common factors and use distributive

top
50a^2-10ab
common facotrs is 10a
undistribute (ab+ac=a(b+c))
10a(5a-b)

bottom
20a^3b^3
see if 10a is also a common factor and undistribute that to cancel and make ones
10a(2a^2b^2)

now we have
(10a(5a-b))/(10a(2a^(2)b^(3))=(10a)/(10a)(5a-b)/(2a^(2)b^(3))
1)split into two fractions 
(50a^(2) )/(20a ^(3) b ^(3) )(10ab )/(20a ^(3) b ^(3) )

2) cancel what you can on both sides
(5)/(2ab ^(3) )(1)/(2a ^(2)b ^(2) )

3) Make the denominators the same by cross multiplying and then put together as 1 fraction again
(5a-b)/(2a ^(2)b ^(2) )