MATHEMATICS COLLEGE

You want to purchase a new car in 3 years and you anticipate the cost of the car to be $25,000. You are given an investment plan with a fixed APR of 5.3% if you make regular monthly deposits. How much should you deposit at the end of each month to reach your goal of $25,000 in 3 years?

a.$642.23

c.$648.62

b.$645.65

d.$649.13

Answers

Answer 1

Answer:

Answer:

The answer is A: $642.23

Step-by-step explanation:

I just took the test lol

Related Questions

WILL BE MARKED BRAINLYESTRay OJ bisects Angle LOK. Measurement of Angle LOK = 82 degrees.Solve for x.
Solve the inequality. 3x + 7 > 4x + 2 A) x > 5 B) x < 5 C) x > 9 D) x < 9
The ratio of green apples to red apples at a grocery store is 2 to 3. There are 78 red apples at the grocery store. What is the total number of apples at the store?
Please help , i don’t know how to do these
"Young's modulus is a quantitative measure of stiffness of an elastic material. Suppose that for metal sheets of a particular type, its mean value and standard deviation are 75 GPa and 2.1 GPa, respectively. Suppose the distribution is normal. (Round your answers to four decimal places.)(a) Calculate P(74 ? X ? 76) when n = 25.(b)How likely is it that the sample mean diameter exceeds 76 when n = 49?"

You are at a restaurant and the check comes to a total of $23. If you want to leave a 20% tip, how much total money should you pay, to the nearest cent?

Answers

Answer:

$27.60

Step-by-step explanation:

23×1.2=27.60 is the answer

Final answer:

To calculate a 20% tip on a $23 check, multiply $23 by 0.20 to get the tip amount of $4.60. The total amount you should pay, including the tip, is $27.60.

Explanation:

To calculate a 20% tip on a $23 check, you need to multiply the total bill amount by the percentage of the tip, expressed as a decimal. 20% as a decimal is 0.20. So you simply multiply $23 by 0.20 to get the tip amount.

Here is the math:

Start with the total bill amount: $23.
Convert the tip percentage into a decimal: 20% = 0.20.
Multiply the total bill amount by the tip percentage in decimal form: $23 x 0.20 = $4.60.
Add the tip amount to the total bill amount: $23 + $4.60 = $27.60.

So, if you want to leave a 20% tip on a $23 check, you should pay a total of $27.60.

Learn more about Tip Calculation here:

brainly.com/question/34773518

#SPJ3

Convert 1010101001 from binary to hexadecimal.

Answers

Answer:

2A9

Step-by-step explanation:

What is the answer hurry please
36k = -9

Answers

Answer:

k=-0.25

Step-by-step explanation:

The daily high temperature in Chicago for the month of August is approximately normal with mean 78 degrees F, and standard deviation 9 degrees F. a. What is the probability that a randomly selected day in August will have a high temperature greater than the mean daily high temperature of 78 degrees F?
b. What is the percentile for a day in August with a high temperature of 75 degrees F?
c. What is the 75th percentile for the daily high temperature for the month of August?
d. What is the interquartile range for the daily high temperature for the month of August?

Answers

Answer:

a) $P(X>78) = P(Z> (78-78)/(9)) = P(Z>0)= 0.5$

b) $P(X<75)= P(Z< (75-78)/(9)) = P(Z<-0.333) = 0.370$

So then 75 F correspond to approximately the 37 percentile

c) $z=0.674<(a-78)/(9)$

And if we solve for a we got

$a=78 +0.674*9=84.07$

So the value of height that separates the bottom 75% of data from the top 25% is 84.07 F.

d) $IQR = 84.07-71.93= 12.14$

See explanation below.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the daily high temperature in Chicago for the month of August of a population, and for this case we know the distribution for X is given by:

$X \sim N(78,9)$

Where $\mu=78$ and $\sigma=9$

We are interested on this probability

$P(X>78)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=(x-\mu)/(\sigma)$

Using the z score we got:

$P(X>78) = P(Z> (78-78)/(9)) = P(Z>0)= 0.5$

Part b

For this case we can find the percentile with the following probability:

$P(X<75)$

If we use the z score formula we got:

$P(X<75)= P(Z< (75-78)/(9)) = P(Z<-0.333) = 0.370$

So then 75 F correspond to approximately the 37 percentile

Part c

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.25$ (a)

$P(X<a)=0.75$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.674. On this case P(Z<0.674)=0.75 and P(z>0.674)=0.25

If we use condition (b) from previous we have this:

$P(X<a)=P((X-\mu)/(\sigma)<(a-\mu)/(\sigma))=0.75$

$P(z<(a-\mu)/(\sigma))=0.75$

But we know which value of z satisfy the previous equation so then we can do this:

$z=0.674<(a-78)/(9)$

And if we solve for a we got

$a=78 +0.674*9=84.07$

So the value of height that separates the bottom 75% of data from the top 25% is 84.07 F.

Part d

For this case we know that $IQR = Q_3 - Q_1 = P_(75)-P_(25)$

So then we just need to find the percentile 25.

$P(X>a)=0.25$ (a)

$P(X<a)=0.75$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.25 of the area on the left and 0.75 of the area on the right it's z=-0.674. On this case P(Z<-0.674)=0.25 and P(z>-0.674)=0.75

If we use condition (b) from previous we have this:

$P(X<a)=P((X-\mu)/(\sigma)<(a-\mu)/(\sigma))=0.25$

$P(z<(a-\mu)/(\sigma))=0.25$

But we know which value of z satisfy the previous equation so then we can do this:

$z=-0.674<(a-78)/(9)$

And if we solve for a we got

$a=78 -0.674*9=71.93$

So the value of height that separates the bottom 25% of data from the top 75% is 71.93 F.

So then the interquartile range would be:

$IQR = 84.07-71.93= 12.14$

There are twenty classes at each of two middle schools. The number of students in each class at each school is shown in the dot plots below.Number of Students in Each Class at Poplar Middle School
A dot plot. A number line going from 20 to 29 labeled Number of Students. There are 3 dots above 20, 5 above 21, 7 above 22, 4 above 23, 1 above 24, and 0 above 25, 26, 27, 28, and 29.

Number of Students in Each Class at Oak Middle School
A dot plot. A number line going from 20 to 29 labeled Number of Students. There is 1 dot above 20, 2 above 21, 2 above 22, 4 above 23, 3 above 24, 2 above 25, 2 above 26, 2 above 27, 1 above 28, and 1 above 29.

Which statement correctly compares the mean number of students for the data in the plots?
There are about 2 more students in each class at Poplar Middle School than at Oak Middle School.
There are about 2 more students in each class at Oak Middle School than at Poplar Middle School.
There are about 5 more students in each class at Poplar Middle School than at Oak Middle School.
There are about 5 more students in each class at Oak Middle School than at Poplar Middle School.

Answers

The dot plot is missing, so i have attached it.

Answer:

B: there are about 2 more students in each class at Oak Middle School than at Poplar Middle School.

Step-by-step explanation:

From the dot plot attached, we can find the average number of students per class for each school.

For Poplar Middle School;

Total number of students = (20 × 3) + (21 × 5) + (22 × 7) + (23 × 4) + (24 × 1) = 435 students.

There are 20 classes.

Thus;

average number of students per class = 435/20 = 21.75

For Oak Middle School;

Total number of students = (20 × 1) + (21 × 2) + (22 × 2) + (23 × 4) + (24 × 3) + (25 × 2) + (26 × 2) + (27 × 2) + (28 × 1) + (29 × 1) = 483

Average number of students per class ; 483/20 = 24.15

Difference in average = 24.15 - 21.75 = 2.40

This implies that there are about 2 more students in each class at Oak Middle School than at Poplar Middle School.

Answer:

da answer is B lesss goooo

Step-by-step explanation:

Simplify (x + 4)(x2 − 6x + 3). x3 − 14x2 + 3x + 12 x3 − 6x2 − 17x + 12 x3 − 10x2 − 27x + 12 x3 − 2x2 − 21x + 12

Answers

Answer:

36 x^3 - 32 x^2 + (x + 4) (x^2 - 6 x + 3).x^3 - 62 x + 12

Step-by-step explanation:

Answer:

x^6-2x^5-21x^4+48x^3-32x^2-62x+12

Step-by-step explanation:

Mark me as brainliest!!!!

Other Questions

Find the indicated probability. a bag contains four chips of different colors, including red, blue, green, and yellow. a chip is selected at random from the bag and then replaced in the bag. a second chip is then selected at random. make a list of the possible outcomes (for example rb represents the outcome red chip followed by blue chip) and use your list to determine the probability that the two chips selected are the same color. (hint: there are 16 possible outcomes.)

Please help me find the area

What are five qualities of an entrepreneur that you can use to help you navigate the ""new normal ""

A social scientist believed that less than 30 percent of adults in the United States watch 15 or fewer hours of television per week. To test the belief, the scientist randomly selected 1,250 adults in the United States. The sample proportion of adults who watch 15 or fewer hours of television per week was 0.28, and the resulting hypothesis test had a p-value of 0.061. The computation of the p- value assumes which of the following is true? (A) The population proportion of adults who watch 15 or fewer hours of television per week is 0.28. Submit (B) The population proportion of adults who watch 15 or fewer hours of television per week is 0.30. (C) The population proportion of adults who watch 15 or fewer hours of television per week is less than 0.30. (D) The population mean number of hours adults spend watching television per week is 15. (E) The population mean number of hours adults spend watching television per week is less than 15.