Which medical advancements are possible using these stem cells? What ethical issues could erise from using embryonic cells to adult stem cells?

Answers

Answer 1
Answer:

Answer:

  • Stem cells are used to restore or replace tissues that were damaged by disease or injury such as heart attack, also it used to type 1 diabetes which is caused when immune system destroy the beta cells in the pancreas that are responsible to make insulin. Spinal cord injuries can also be cured with the Stem cell therapy.
  • Embryonic stem cell research is ethically controversial because it involve the destruction of human embryo or human life for research.

Related Questions

Taking away the surface of the earth to get coal is called______.strip mining reclamation mountaintop removal underground mining
Why is deforestation in tropical rainforests more devastating to the global environment than deforestation in temperate forests? (Points : 4) most temperate forests are not experiencing deforestation tropical rainforests provide less useable lumber temperate forests do not contribute to the reduction of carbon dioxide tropical rainforests are inhabited by indigenous tribes who are losing their way of life tropical rainforests have much higher biodiversity than temperate forests
During a controlled experiment, a scientist isolates and tests A. a conclusion. B. a mass of information. C. a control group. D. a single variable
Millions of species exist today. Based on Darwin's theory of evolution, which of the following best explains how this is possible?A. Organisms pass on acquired traits to evolve into more advanced life forms.B. Organisms are selectively bred to create new species.C. New species are crossed with each other to form many different organisms.D. Different genetic variations in organisms are selected in different habitats.
The carbon footprint of an activity is used to assess environmental pollution. What does it measure?

4. Which of the following statements about reinforcement is true?a. Reinforcement increases the number of intermediate phenotypes.
b. Reinforcement is a type of natural selection.
c. Reinforcement decreases the morphological difference between two incipient species.
d. Reinforcement is also called dispersive selection

Answers

The  statements about reinforcement is true is that Reinforcement decreases the morphological difference between two incipient species.

Option C is correct.

How do we explain?

Reinforcement is  described as a type of natural selection that occurs when two populations that are becoming reproductively isolated from each other start to develop preferences for mates from their own population.

This can lead to a decrease in the morphological difference between the two populations, as they become more adapted to each other's mating preferences.

In conclusion, reinforcement is a type of natural selection, not the other way around. Option d is incorrect because reinforcement is also called assortative mating, not dispersive selection.

Therefore option B is correct

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Your answer would be A

Krebs cycle occurs in the ___ of a eukaryotic cell. Question 27 answers matrix of the mitochondrion cristae membranes of the mitochondrion nucleus cytoplasm

Answers

The answer to the question stated above is matrix of the mitochondria or matrix of the mitochondrion
Krebs cycle occurs in the matrix of the mitochondria of a eukaryotic cell.
Additional information:
 >matrix of the mitochondria is the fluid filled interior of the mitochondria.

Final answer:

The Krebs Cycle occurs in the matrix of the mitochondrion of a eukaryotic cell, which is a part of the process of cellular respiration, generating energy for the cell.

Explanation:

The Krebs cycle, also known as the citric acid cycle or the tricarboxylic acid (TCA) cycle, takes place in the matrix of the mitochondrion of a eukaryotic cell. This cycle is a crucial part of cellular respiration, the process by which cells generate energy. During the Krebs cycle, the pyruvate molecules derived from glucose are oxidized and, in turn, produce ATP (adenosine triphosphate), the main source of cellular energy, and other high-energy compounds. The matrix of the mitochondrion provides the necessary environment and enzymes for this cycle to occur effectively.

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The purines in DNA area. thymine and cytosine
b. thymine and guanine
c. adenine and guanine
d. adenine and cytosine

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C - adenine and guanine

2 organisms that respire anaerobically

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protozoans and bacteria

Based on binomial classification system, the mosquito, anopheles punctulatus, is most closely related in structure toA. Clux pipiens
B. Anopheles quadrimaculatus
C. Ades aeqypti
D. Aedes sollicitans

Answers

b anopheles quadimaculatas

Final answer:

Anopheles punctulatus is most closely related to Anopheles quadrimaculatus according to the binomial classification system, because they belong to the same genus.

Explanation:

In the binomial classification system, organisms are named based on their genus and species. In this case, Anopheles punctulatus and Anopheles quadrimaculatus are both part of the Anopheles genus meaning they share a lot of similarities in term of structure and genetics. Therefore, Anopheles punctulatus is most closely related in structure to Anopheles quadrimaculatus.

Clux pipiens, Ades aeqypti, and Aedes sollicitans are species from other genus, hence they are not as closely related. Although they are all mosquitoes and have certain common features, they do not share as many similarities as within the same genus. Hence, Anopheles punctulatus has compared to other options, the most similarities with Anopheles quadrimaculatus.

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A block of metal has dimensions of 2.00 x 5.50 x 1.25 cm. It has a mass of 37.1 grams. What is its density?-512 g/cm3
-0.372 g/cm3
-2.69 g/cm3
-4.24 g/cm3

Answers

Answer:

                   Density  =  2.69 g.cm⁻³

Solution:

Data Given;

                   Density  =  ??

                   Mass  =  37.1 g  

                   Volume  =  2.0 cm × 5.5 cm × 1.25 cm  =  13.75 cm³

Formula Used;

                   Density  =  Mass ÷ Volume  

Putting values,

                   Density  =  37.1 g ÷ 13.75 cm³

                   Density  =  2.69 g.cm⁻³

2.69 is the correct answer