In a circle centered at point O, the ratio of the area of sector AOB to the area of the circle is . What is the approximate measure, in radians, of the central angle corresponding to ? Round the answer to two decimal places
Answers
3/5 = θ/2π
5θ = 6π
θ = (6/5) π
= (6/5) * 3.14159
= 18.85/5
= 3.77
I hope this helps you *-*
Answer:
D. 3.77
Step-by-step explanation:
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The volume of a cylinder is V = r2h. Solve for h (height) in this formula.
Answers
Answers
Step-by-step explanation:
Given data:
Cars Vans Others
60 21 3
The data represents the number of cars on a single day.
Find the relative frequency;
It is the number of times an event occurs.
Here the time frame is within a day;
Relative frequency =
Relative frequency = 60 + 21 + 3 = 84vehicles per day
ii.
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One of the side lengths is 8 cm.
What is the length of the other side?
Answers
Answer:
6 cm
Step-by-step explanation:
We can use the Pythagorean Theorem to find the length of the missing side.
The Pythagorean Theorem states that the hypotenuse of a right triangle will be , where a and b are the leg lengths.
Together, we get the formula .
Since we know the hypotenuse (c) and one of the sides (let's say a), we can find the missing side (b) by substituting inside the equation.
So the missing side is 6 cm long.
Hope this helped!
Answer:
6 cm
Step-by-step explanation:
use Pythagorean theorem a² + b² = c²
let c = 10 cm , b = 8 cm
plug in values
a² + 8² = 10²
a² = 10² - 8²
a =
a = 6 cm
A)6
B)5
C)4
Answers
Answers
Answer:
8 times
Step-by-step explanation:
28/3.5 = 8
2^5/8 = 2^2
By finding the quotient of the bases to be,1/4 and cancelling common factors
By finding the quotient of the bases to be, 1/4 and simplifying the expression
By simplifying 8 to 2^3 to make both powers base two, and subtracting the exponents
By simplifying 8 to 2^3 to make both powers base two, and adding the exponents
Answers
(x^m)/(x^n)=x^(m-n)
we know that 8=x^3
so
(2^5)/8=2^2 can be rewritten as
(2^5)/(2^3)=2^2
and 5-3=2 so it's true
answer is
third one
by simplifieng 8 to 2^3 to make both powers base two, and subtraction the exponents
(2^5)/8 = 2^2
Now, 8 = 2^3. So we can sub
(2^5)/(2^3) = 2^2
Now, there's a rule that states that (a^m)/(a^n) = a^(m-n)
so (2^5)/(2^3) = 2^(5-3) = 2^2
So the statement stands.
The answer is C