Choose the equivalent number.
4,000 + 800 + 20+3=

Answers

Answer 1

Answer:

Answer:

4823 is the answer you're welcome

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Jase wrote the prime factorization of 99. Which expressions could he have written? Select all that apply. A. 32 × 11 B. 9 × 9 C. 3 × 3 × 3 × 11 D. 34 E. 3 × 3 × 11
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Evaluate. [42 ÷ (2 + 3 • 2)] + [4 • (36 – 52)] I really need help!!!

Simplify a - {5b - [a - (3b - 2c) + c - (a - 2b - c)]}.-a - 6b + 4c

a - 6b + 4c

a - 10b + 4c

-a + 10b + 4c

Answers

a - {5b - [a - (3b - 2c) + c - (a - 2b - c)]}
= a - 5b - a - 3b + 2c + c - a + 2b + c
= -a - 6b + 4c

answer is -a - 6b + 4c (first choice)

your answer should be -6b+4c

Best of Luck!!!

:):):)

The circular ring of the fountain has a radius of 9 feet. what is the area of the ring?a. 4.5 square feet

b. 28.26 square feet

c. 63.61 square feet

d. 254.34 square feet

Answers

The area of the circular ring of the fountain with a radius of 9 feet is approximately 254.34 square feet.

To find the area of the ring, we need to subtract the area of the smaller circle from the area of the larger circle. The area of a circle is given by the formula A = πr^2, where r is the radius of the circle. Therefore, the area of the larger circle is π(9^2) = 81π square feet, and the area of the smaller circle is π((9/2)^2) = 20.25π square feet.

Subtracting the area of the smaller circle from the area of the larger circle, we get:

81π - 20.25π = 60.75π

Using the approximation π ≈ 3.14, we get:

60.75π ≈ 60.75(3.14) ≈ 190.845

Therefore, the area of the ring is approximately 190.845 square feet, which is closest to option (d) 254.34 square feet.

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Solve for x. 3x – 4 + 2x = 36

Answers

Answer:

x=8

Step-by-step explanation:

3x-4+2x=36

5x-4=36

5x=36+4

5x=40

8x5=40

A Geometry textbook has a mass of 48 grams.The textbook is in the shape of a rectangular prism with dimensions show below.

To find density use: density

mass

volume

5 cm

16 cm

10 cm

Determine the density of the Geometry textbook in g/cm3.

Round your answer to the nearest hundredths place.

Answers

The density of the Geometry textbook is 0.06 g/cm^3.

To find the density of the Geometry textbook in g/cm^3, we need to find its volume first. The volume of a rectangular prism is given by the formula V = l x w x h, where l is the length, w is the width, and h is the height.

In this case, the length is 16 cm, the width is 10 cm, and the height is 5 cm. Therefore, the volume of the Geometry textbook is:

V = l x w x h = 16 cm x 10 cm x 5 cm = 800 cm^3

Now, we can find the density of the textbook using the formula:

$density = mass / volume$

Plugging in the given mass of 48 grams and the calculated volume of 800 cm^3, we get:

density = 48 g / 800 cm^3 = 0.06 g/cm^3

Therefore, the density of the Geometry textbook is 0.06 g/cm^3. We rounded our answer to two decimal places as the original mass was given in grams to two decimal places.

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The price of a silk scarf is $32. The sales tax is $1.92. What is the sales-tax rate?