HELP!!!! I HAVE 2 MINUTES!!!A substance placed into an open plastic container at room temperature exerts a force against the bottom of the container but not the sides of the container. What is the most likely phase of this substance?
A. gas
B. solid
C. liquid
D. plasma

Answers

Answer 1
Answer:

Answer:

a solid

Explanation:

because because gas would excerpt forced throughout the whole container and plasma would be too hot for the plastic container and liquid would flow throughout the container touching the sides and solid is the only one that would probably only touch the bottom of the plastic container exerting force through there


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Using the half-reaction method, balance the following redox reaction occurring in acidic solution:Ag + NO3- -> Ag+ + NO

Answers

to solve this half-reaction method, we divide the reaction into two equations- reduction and oxidation side. The oxidation is simply Ag= Ag+ + e-. The reduction side is 4H+ + NO3-+e-=NO+2H20. H2O is used to balance O and H+ is used to balance H. Hence the final equation is Ag+4H+ + NO3-= NO+2H2O. 

17. What standard reduction electrode has a half-cell potential of 0.00 V? Oxygen hydrogen
lithium
Fluorine

Answers

I believe Hydrogen is the standard reduction electrode that has a half-cell potential of 0.00 V. In electrochemical cell, an electric potential is created between two dissimilar metals. This potential is a measure of the energy per unit charge which is available from reduction or oxidation reactions to drive the reaction. 

Compared to a 2.0 M aqueous solution of NaCl at 1 atmosphere, a 3.0 M aqueous solution of NaCl at 1 atmosphere has a(1) lower boiling point and a higher freezing point
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Answers

The correct answer is option 4. A 3.0 M aqueous solution of NaCl has a higher boiling point and a lower freezing point than a 2.0 M aqueous solution of NaCl where both are at 1 atmosphere. This is explained by the colligative properties of solutions. For the two properties mentioned, the equation for the calculation of the depression and the elevation is expressed as: ΔT = -Km and ΔT = Km, respectively. As we can see, concentration and the change in the property has a direct relationship.

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Answers

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What is the term used to describe the energy needed to get a reaction started?a. adhesion energy
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Answers

When a reaction starts, activation energy is needed. 

Answer: b. activation energy

State hess's law.how is it used

Answers

 Hess' Law states that the enthalpy change in a reaction can be calculated from the enthalpy changes of reactions that, when combined, result in the desired reaction. 

For example, to check the enthalpy change that occurs when benzene undergoes incomplete combustion to water and carbon monoxide is not an easy task, because the products invariably contain CO2. However, by combining the reactions of the complete combustion of benzene and the combustion of CO, you can get the reaction you want. 

Reaction wanted: 2C6H6 + 9O2 → 12CO + 6H2O 
Reactions provided: 2C6H6 + 15O2 → 12CO2 + 6H2O and 2CO + O2 → 2CO2, and their associated ΔH. 

Rearrange the reactions so that, when they add up, they result in the wanted reaction. 

2C6H6 + 15O2 → 12CO2 + 6H2O (leave as is; no changes to ΔH) 
12CO2 → 12CO + 6O2 (reverse and multiply by 6; this changes the sign of ΔH and multiplies it by 6) 

Added up, it will result in 2C6H6 + 9O2 → 12CO + 6H2O. Add up the ΔH values for the rearranged reactions to find ΔH for this particular reaction.

Answer: Hess's Law says the total enthalpy change does not rely on the path taken from beginning to end. Enthalpy can be calculated in one grand step or multiple smaller steps.

To solve this type of problem, organize the given chemical reactions where the total effect yields the reaction needed. There are a few rules that you must follow when manipulating a reaction.

The reaction can be reversed. This will change the sign of ΔHf.

The reaction can be multiplied by a constant. The value of ΔHf must be multiplied by the same constant.

Any combination of the first two rules may be used.

Finding a correct path is different for each Hess's Law problem and may require some trial and error.