What is 35 times 10 equal

Answers

Answer 1
Answer:

Answer:

350

Step-by-step explanation:


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The number of chocolate chips in an​ 18-ounce bag of chocolate chip cookies is approximately normally distributed with a mean of 1252 chips and standard deviation 129 chips.​(a) What is the probability that a randomly selected bag contains between 1000 and 1500 chocolate​ chips, inclusive? ​(b) What is the probability that a randomly selected bag contains fewer than 1025 chocolate​ chips? ​(c) What proportion of bags contains more than 1200 chocolate​ chips? ​(d) What is the percentile rank of a bag that contains 1425 chocolate​ chips?

Answers

Using the normal distribution, it is found that:

a) There is a 0.947 = 94.7% probability that a randomly selected bag contains between 1000 and 1500 chocolate​ chips, inclusive.

b) There is a 0.0392 = 3.92% probability that a randomly selected bag contains fewer than 1025 chocolate​ chips.

c) 0.3446 = 34.46% of bags contains more than 1200 chocolate​ chips.

d) The bag is in the 91st percentile.

In a normal distribution with mean \mu and standard deviation\sigma, the z-score of a measure X is given by:

Z = (X - \mu)/(\sigma)

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • Mean of 1252 chips, thus \mu = 1252.
  • Standard deviation of 129 chips, thus \sigma = 129.

Item a:

The probability is the p-value of Z when X = 1500 subtracted by the p-value of Z when X = 1000, thus:

X = 1500:

Z = (X - \mu)/(\sigma)

Z = (1500 - 1252)/(129)

Z = 1.92

Z = 1.92 has a p-value of 0.9726.

X = 1000:

Z = (X - \mu)/(\sigma)

Z = (1000 - 1252)/(129)

Z = -1.95

Z = -1.95 has a p-value of 0.0256.

Then, 0.9726 - 0.0256 = 0.947

There is a 0.947 = 94.7% probability that a randomly selected bag contains between 1000 and 1500 chocolate​ chips, inclusive.

Item b:

This probability is the p-value of Z when X = 1025, thus:

Z = (X - \mu)/(\sigma)

Z = (1025 - 1252)/(129)

Z = -1.76

Z = -1.76 has a p-value of 0.0392.

There is a 0.0392 = 3.92% probability that a randomly selected bag contains fewer than 1025 chocolate​ chips.

Item c:

This proportion is 1 subtracted by the p-value of Z when X = 1200, thus:

Z = (X - \mu)/(\sigma)

Z = (1200 - 1252)/(129)

Z = -0.4

Z = -0.4 has a p-value of 0.3446.

0.3446 = 34.46% of bags contains more than 1200 chocolate​ chips.

Item d:

This percentile is the p-value of Z when X = 1425, thus:

Z = (X - \mu)/(\sigma)

Z = (1425 - 1252)/(129)

Z = 1.34

Z = 1.34 has a p-value of 0.91.

The bag is in the 91st percentile.

A similar problem is given at brainly.com/question/13680644

Final answer:

The probability and percentiles can be found using the z-score formula and then looking these z-scores up in the standard normal distribution table.

Explanation:

In this question, we're dealing with a normal distribution. For a normal distribution, probabilities can be calculated using the z-score formula which is given by Z = (X - μ) / σ, where X is the value from which you want to find the probability, μ is the mean and σ is the standard deviation.

(a) To find the probability that a randomly selected bag has between 1000 and 1500 chocolate chips, we need to find the z-scores for both 1000 and 1500 and then find the area between these two z-scores in the standard normal distribution table.  (b) To find the probability that a randomly selected bag has less than 1025 chips, we find the z-score for 1025 and find the area to the left of it in the standard normal distribution table. (c) To find the proportion of bags containing more than 1200 chips, we find the z-score for 1200 and then find the area to the right of it in the standard normal distribution table. (d) Percentile rank can be found by finding the z-score for 1425 chips, and then finding the corresponding percentile in the standard normal distribution table.

Learn more about Normal Distribution here:

brainly.com/question/34741155

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Suppose you read online that children first count to 10 successfully when they are 32 months old, on average. You perform a hypothesis test evaluating whether the average age at which gifted children first count to 10 is different than the general average of 32 months. What is the p-value of the hypothesis test? Choose the closest answer.

Answers

Answer:

p_v =2*P(t_((35))<-1.822)=0.0885  

Step-by-step explanation:

Assuming this info from R

hist(gifted$count)

##    Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

##   21.00   28.00   31.00   30.69   34.25   39.00

## Sd

## [1] 4.314887

Data given and notation  

\bar X=30.69 represent the mean  

s=4.3149 represent the sample standard deviation

n=36 sample size  

\mu_o =32 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different than 32, the system of hypothesis would be:  

Null hypothesis:\mu = 32  

Alternative hypothesis:\mu \neq 32  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=(\bar X-\mu_o)/((s)/(√(n)))  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=(30.69-32)/((4.3149)/(√(36)))=-1.822    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=36-1=35  

Since is a two sided test the p value would be:  

p_v =2*P(t_((35))<-1.822)=0.0885  

True or false: The number 0 (zero) IS an integer

Answers

Answer:

true. zero is an integer number

Step-by-step explanation:

Answer:

True,  it is Known as a neutral integer Because it is neither negative or positive whole number

Step-by-step explanation:

suzi starts her hike at a elevation if -225 below sea level. When she reaches the end of the hike, she is still nelow sea level at -127 feet. What was the vhange in elevation from the beginning of Suzi's hike to the end of the hike?

Answers

The change is elevation is 98 feet.

There are a couple different ways to get this answer. You could:
A. Subtract 127 from (positive) 225, to get the height difference. Or...
B. Subtract the starting height from the ending height (-127 - (-225)) which would also give you the height difference.

I hope this helps!

10. Sarah is planning to fence in her backyard garden. One side of the garden is 34 feet long, another side is 30 feet long, and the third side is 67 feet long.Find the perimeter of Sarah’s garden to determine the amount of fencing material needed.A.262 ft.
B.68,340 ft.
C.250 ft.
D.131 ft.

Answers

Answer:

131ft is the amount of fencing material needed

Step-by-step explanation:

Perimeter is the distance around a shape: we have to sum all the distances

P = d1 + d2 + d3

P = 34 ft + 30 ft + 67 ft = 131 ft

Answer:

D. 131 ft.

Step-by-step explanation:

If Sarah is planning to fence in her backyard garden and one side of the garden is 34 feet long, another side is 30 feet long, and the third side is 67 feet long. The perimeter of Sarah’s garden to determine the amount of fencing material needed is 131 feet.

Alejando read 4 pages in a book in 6 minutes. How long would you expect him to read 6 pages at this rate

Answers

Answer:

So simple

4 pages = 6 min

1 page = 6/4 min

6 pages = 6 × 6/4

6 pages = 9 min

he would read 6 pages in 9 minutes