MATHEMATICS HIGH SCHOOL

Every month Neha takes a fixed amount of ₹3750 from her mother for her expenses. What is the amount she is spending in a year. What is the quality reflected here?

Answers

Answer 1
Answer:

Answer:

Yearly expenses = ₹45,000

Step-by-step explanation:

Given:

Monthly expenses = ₹3,750

Find:

Yearly expenses

Computation:

Yearly expenses = 12 x ₹3,750

Yearly expenses = ₹45,000

Neha is unemployed and his expenses are totally fixed during the whole year.

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Factor completely x^2 - 4x - 12
Explain the steps.
^ = to the power of

Answers

Well x^2 is the same as x-squared (I don't know how to type it). 
So to start off, you have x-squared-4x-12 
Then you just have to combine the x's, and 1x-4x=-3x 
so your final answer would be -3x-squared-12 

There is a 0.23 probability that a typical convenience store customer buys gasoline. The probability that a customer buys groceries is 0.76 and the conditional probability of buying groceries given that the customer buys gasoline is 0.85.a) Find the probability that a typical customer buys both gasoline and groceries.

Answers

Answer:

The probability that a typical customer buys both gasoline and groceries, P(Ga n Gr) = 0.1955

Step-by-step explanation:

Let the probability that a customer guys groceries be represented by P(Gr) and that of buying gasoline be P(Ga)

Given

P(Gr) = 0.76

P(Ga) = 0.23

P(Gr|Ga) = 0.85

For mutually exclusive events,

P(B|A) = (P(B n A))/P(A)

P(Gr|Ga) = (P(Gr n Ga))/P(Ga)

P(Gr n Ga) = P(Gr|Ga) × P(Ga)

P(Gr n Ga) = 0.85 × 0.23 = 0.1955

Hope this Helps!!!!

Solve:

3/5 − 6/11

A:3/55

B:3/6

C:3/11

Answers

The answer is: [A]:  3/55 .
__________________________________
Explanation:
__________________________________
(3/5) - (6/11) =  [(3*11) / (5*11) ] - [(6*5) / (11*5)] = (33/55) - (30/55) = 3/ 55.
____________________________________________________

Although Dan's psychology class is sometimes longer or shorter than usual, on average each class is 50 minutes. If the lengths of these classes form a normal curve, which statistic would enable Dan to estimate the probability that any single class will last somewhere between 47 and 53 minutes?

Answers

Answer:

the sample standard deviation

Step-by-step explanation:

The statistic that would enable Dan to estimate the probability that any single class will last somewhere between 47 and 53 minutes is the sample standard deviation. If we have the mean and the standard deviation and we know that the lenghts of the classes form a normal curve, we can compute probabilities either with the empirical rule or using a table of probabilities from a book. The normal distribution is completely determined with the mean and the standard deviation.

The wingspan of one butterfly is 1 9/16. The wingspan of another butterfly is 1 5/8 inches. write an inequality comparing the two wingspan

Answers

1 9/16 < 1 5/8     one nine sixteenths is larger than one five eighths
19/16< 15/8 one nine sixteenth is larger than one five eighths

Denelle draws one card from a standard deck of 52 cards. Determine the probability of drawing either a two or a queen.

Answers

There are four queens in a deck of cards, so the probability of drawing a queen is 4/52. There is also a 4/52 chance of drawing a two. Because you can draw either a two or Queen, you add the probability of each.

4/52 + 4/52 = 8/52

8/52 can be simplified to 2/13
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