Determine whether the equations are parallel or not for y= 3x-2 and y= 1/3x -11

Answers

Answer 1
Answer:

Answer:

not parallel

Step-by-step explanation:

while the lines have a different y-intercept they do not have the same slope which they would need to be parallel. With two different slopes the lines will eventually cross.

Answer 2
Answer:

Answer:

To know if these lines are parallel, you just have to look at the slope. In this case they are not.

Step-by-step explanation:

The slope is the number in front of your x. So for the first formula the slope is 3 and for the second one it is 1/3. The slope tells you in which direction the line goes, so if they are the same, that means that the lines are parallel. In this case the slopes are not the same, so the lines are not parallel.


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A study is being conducted to compare the average training time for two groups of airport security personnel: those who work for the federal government and those employed by private security companies. From a random sample of 12 government-employed security personnel, average training time was 72 hours, with a sample standard deviation of 8 hours. In a random sample of 16 privately employed security personnel, training time was 65.4 hours, with a sample standard deviation of 12.3 hours. Assume that training time for each group is normally distributed. Use the following notations:μ1: The mean training time for the population of airport security personnelemployed by the federal government.μ2: The mean training time for the population of airport security personnelemployed by private security companies.The goal of the statistical analysis is to determine whether the sample data support the hypothesis that average training time for government-employed security personnel is higher than those employed by private security companies.1. What is the null hypothesis H0?Select one:a. μ1- μ2 <= 0b. μ1- μ2 < 0c. μ1- μ2 =/ 0d. μ1- μ2 > 02. What is the alternative hypothesis Ha?Select one:a. μ1- μ2 > 0b. μ1- μ2 <= 0c. μ1- μ2 = 0d. μ1- μ2 >= 0
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Graph the image of the given triangle after the transformation that has the rule (x, y)→(−x, −y)

Answers

Firstly, we will find corner points

A=(-2,5)

B=(6,7)

C=(7,4)

the transformation that has the rule (x, y)→(−x, −y)

x---->-x

We will multiply x-values by -1

A=(-2*-1,5)=(2,5)

B=(6*-1,7)=(-6,7)

C=(7*-1,4)=(-7,4)

y---->-y

We will multiply y-values by -1

A=(2,5*-1)=(2,-5)

B=(-6,7*-1)=(-6,-7)

C=(-7,4*-1)=(-7,-4)

now, we can draw points and find graph

we get




PLS HELP ITS 6TH GRADE!
Evaluate the expression for m=4;-48/m

Answers

Answer:

-12

Step-by-step explanation:

Given, m = 4

solution:

=-48/m

=-48/4

=-12

Identify the roots of gx= x2+3x-4 x^2-4x+29

Answers

Answer:

x1=1

x2= -4

x3= (2 + 5i)

x4= (2 - 5i)

Step-by-step explanation:

STEP 1-

Find the roots of the first term.

(x^2 + 3x -4)=0

Then group the terms that contain the same variable, and move the constant to the opposite side of the equation.

(x^2 + 3x)=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

(x^2 + 3x + 1.5^2)=4 + 1.5^2

(x^2 + 3x + 1.5^2)=6.25

Rewrite as perfect squares

(x + 1.5)^2=6.25

Square root both sides.

(x + 1.5) = (+/-)2.5

x= -1.5(+/-)2.5

x= -1.5 + 2.5 = 1

x= -1.5 + 2.5= -4

so the factored form of the first term.

(x^2 + 3x + 4) = (x - 1) (x + 4)

STEP 2-

Find the roots of the second term

(x^2 - 4x + 29)= 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^2 - 4x)= -29

Complete the square. Remember to balance the equation by adding the same constants to each side

(x^2 - 4x + 4) = - 29 + 4

(x^2 -4x + 4) = -25

Rewrite as perfect squares

(x - 2)^2 = -25

Remember that

i = square root of -1

Square root both sides

(x - 2) = (+/-)5i

x= 2 (+/-)5i

x= 2 + 5i

x= 2 - 5i

so the factored form of the second term is

(x^2 - 4x + 29) = (x - (2 + 5i))(x - (2 - 5i))

STEP 3-

Substitute the factored form of the first and second term in g(x)

g(x) = (x-1)(x + 4)(x- (2+ 5i))(x- ( 2-5i)

there for you have your answers

The legend on a map states that 1 cm is 20 km. If you measure 9 centimeters on the map, how many kilometers would the actual distance be?

Answers

Making a proportion helps solve this problem. Cm on top, km on bottom.


1 9

---- = ----

20 ?


Cross multiply to get 1? = 180


? = 180.


The distance is 180 km.

Final answer:

The conversion of 9 cm on the map to an actual distance, using the given scale of 1 cm for 20 km, results in an actual distance of 180 kilometers.

Explanation:

The question is asking for the actual distance corresponding to 9 cm on the map. According to the given scale on the map, 1 cm corresponds to an actual distance of 20 km. So to find out how many kilometers 9 cm on the map would be in real life, we simply multiply the length measured on the map by the distance each centimeter represents. This gives us:

9 cm * 20 km/cm = 180 km

So, according to the map, 9 cm corresponds to an actual distance of 180 kilometers.

Learn more about Map Scale Conversion here:

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Find the scale factor of the line segment dilation. AB: endpoints (-6, -3) and (-3,-9) to A'B': endpoints at (-2, -1) and (-1, -3). A) -1/3 B) 1/3 C) 3D) -3

Answers

we know that the endpoints of AB are

\begin{gathered} (x_1,y_1)=\mleft(-6,-3\mright) \n (x_2,y_2)=(-3,-9) \end{gathered}

and the distance formula is given by

d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}

By substituying these points, we have that

d=\sqrt[]{(-3-(-6))^2+(-9-(-3))^2}

which is equal to

\begin{gathered} d=\sqrt[]{(-3+6)^2+(-9+3)^2} \n d=\sqrt[]{3^2+(-6)^2} \end{gathered}

then

\begin{gathered} d=\sqrt[]{9+36} \n d=\sqrt[]{45} \n d=\sqrt[]{9\cdot5} \n d=\sqrt[]{9}\cdot\sqrt[]{5} \n d=3\sqrt[]{5}\ldots..(A) \end{gathered}

On the other hand, if

\begin{gathered} (x_1,y_1)=(-2,-1) \n (x_2,y_2)=(-1,-3) \end{gathered}

similarly to the previous case, the distance between the endpoint for A'B' is

d=\sqrt[]{(-1-(-2))^2+(-3-(-1))^2}

which is equal to

\begin{gathered} d=\sqrt[]{(-1+2)^2+(-3+1)^2} \n d=\sqrt[]{1^2+(-2)^2} \n d=\sqrt[]{1+4} \n d=\sqrt[]{5}\ldots..(B) \end{gathered}

Now, by comparing equation A and equation B, we can see that, the scale factor is 1/3.

Then, the answer is B.

Forty percent of all Americans who travel by car look for gas stations and food outlets that are close to or visible from the highway. Suppose a random sample of n=25 Americans who travel by car are asked how they determine where to stop for food and gas. Let x be the number in the sample who respond that they look for gas stations and food outlets that are close to or visible from the highway. a. What are the mean and variance of x?
b. Calculate the interval μ±2σμ±2σ. What values of the binomial random variable x fall into this interval?
c. Find P(6≤≤x$\leq$14). How does this compare with the fraction in the interval μ±2σμ±2σ for any distribution? For mound-shaped distributions?

Answers

Answer:

Explained below.

Step-by-step explanation:

Let the random variable X be defined as the number of Americans who travel by car look for gas stations and food outlets that are close to or visible from the highway.

The probability of the random variable X is: p = 0.40.

A random sample of n =25 Americans who travel by car are selected.

The events are independent of each other, since not everybody look for gas stations and food outlets that are close to or visible from the highway.

The random variable X follows a Binomial distribution with parameters n = 25 and p = 0.40.

(a)

The mean and variance of X are:

\mu=np=25* 0.40=10\n\n\sigma^(2)=np(1-p)-25*0.40*(1-0.40)=6

Thus, the mean and variance of X are 10 and 6 respectively.

(b)

Compute the values of the interval μ ± 2σ as follows:

\mu\pm 2\sigma=(\mu-2\sigma, \mu+ 2\sigma)

           =(10-2\cdot√(6),\ 10+2\cdot√(6))\n\n=(5.101, 14.899)\n\n\approx (5, 15)

Compute the probability of P (5 ≤ X ≤ 15) as follows:

P(5\leq X\leq 15)=\sum\limits^(15)_(x=5){{25\choose x}(0.40)^(x)(1-0.40)^(25-x)}

                        =0.0199+0.0442+0.0799+0.1199+0.1511+0.1612\n+0.1465+0.1140+0.0759+0.0434+0.0212\n\n=0.9772

Thus, 97.72% values of the binomial random variable x fall into this interval.

(c)

Compute the value of P (6 ≤ X ≤ 14) as follows:

P(6\leq X\leq 14)=\sum\limits^(14)_(x=6){{25\choose x}(0.40)^(x)(1-0.40)^(25-x)}

                        =0.0442+0.0799+0.1199+0.1511+0.1612\n+0.1465+0.1140+0.0759+0.0434\n\n=0.9361\n\n\approx P(5\leq X\leq 15)

The value of P (6 ≤ X ≤ 14) is 0.9361.

According to the Tchebysheff's theorem, for any distribution 75% of the data falls within μ ± 2σ values.

The proportion 0.9361 is very large compared to the other distributions.

Whereas for a mound-shaped distributions, 95% of the data falls within μ ± 2σ values. The proportion 0.9361 is slightly less when compared to the mound-shaped distribution.

Final answer:

The mean of x is 10 and the variance is 6. The interval μ ± 2σ is 10 ± 2√6. P(6 ≤ x ≤ 14) can be calculated using the binomial probability formula.

Explanation:

To find the mean of x, we multiply the sample size (n) by the probability of success (p), which is 40% or 0.4. So, the mean (μ) is 0.4 * 25 = 10. To find the variance of x, we multiply the sample size (n) by the probability of success (p) and the probability of failure (1-p), which is 0.6. So, the variance is 25 * 0.4 * 0.6 = 6.

To calculate the interval μ ± 2σ, we need to find the standard deviation (σ) first. The standard deviation is the square root of the variance, so σ = √6. Then, the interval is μ ± 2σ. Plugging in the values, the interval is 10 ± 2√6. To find the values of x that fall into this interval, we can subtract and add 2√6 from the mean, resulting in the range 10 - 2√6 to 10 + 2√6.

To find P(6 ≤ x ≤ 14), we need to find the probability of x being between 6 and 14. We can use the binomial probability formula to calculate this. P(6 ≤ x ≤ 14) = P(x = 6) + P(x = 7) + ... + P(x = 14). Using a binomial probability table or a calculator, we can find the probabilities of each x value and sum them up.

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