MATHEMATICS COLLEGE

How can you solve linear equations by combining like terms?

Answers

Answer 1
Answer:

Answer: In algebra, like terms are terms that have the same variables and powers. The coefficients do not need to match. Unlike terms are two or more terms that are not like terms, i.e. they do not have the same variables or powers. The order of the variables does not matter unless there is a power. For example, 8xyz² and −5xyz² are like terms because they have the same variables and power while 3abc and 3ghi are unlike terms because they have different variables. Since the coefficient doesn't affect likeness, all constant terms are like terms.

I HOPE THIS HELPED ! :) mark me brainlist pls

Answer 2
Answer:

Answer:

by combining them like the ordinary like ordinary integers.

Step-by-step explanation:

For example we have

8x + 4y = 3x - 6

you will bring 3x to the left so it will become -3x

8x - 3x + 4y = -6

then combine like terms

there you have

5x + 4y = -6

The given:

8x + 4y = 3x - 6

8x - 3x + 4y = -6

5x + 4y = -6

answer for the example: 5x + 4y = -6

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Hope they get enough saved.

The sum of two numbers is -14, if one number is subtracted from the other, their difference is 2, find the numbers.

Answers

Answer:uu

-10 and -12

Step-by-step explanation:

1/2(x-6.5) = 3.16 what is x?

Answers

Answer:

x =12.82

Step-by-step explanation:

1/2(x-6.5) = 3.16

Multiply each side by 2

1/2(x-6.5) *2 = 3.16 *2

(x-6.5) = 6.32

Add 6.5 to each side

(x-6.5+6.5) = 6.32+ 6.5

x =12.82

Answer: 12.82

Step-by-step explanation:

1/2(x-6.5)= 3.16

x=12.82

Fast plz
The options are
-Is
-Is not

Answers

Answer:

the rate of change is constant

Step-by-step explanation:

The equation T^2=A^3 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU. If planet Y is twice the mean distance from the sun as planet X, by what factor is the orbital period increased?

Answers

the answer for your question is going to be. 2^((3)/(2)) I know this cause I just took a quiz with this question on it

Answer:

2 Superscript three-halves

Step-by-step explanation:

Edge

Triangle M was dilated by a scale factor of 1.2 to form triangle M. How does the area of triangle M'relate to the area of triangle M?
A- The area of triangle M'is 0.6 times the area of triangle M.
B- The area of triangle M'is 1.2 times the area of triangle M.
C- The area of triangle M'is 1.44 times the area of triangle M.
D- The area of triangle M' is 2.4 times than the area of triangle M.

Answers

Answer:

The area of triangle M is 1.44 times the area of triangle M.

Step-by-step explanation:

From Geometry we remember that the area formula of the triangle is:

A = (1)/(2)\cdot b\cdot h(1)

Where:

b - Base of the triangle, dimensionless.

h - Height of the triangle, dimensionless.

A - Area of the triangle, dimensionless.

The dillation of the triangle by a scale factor means that:

A' = (1)/(2)\cdot b'\cdot h'(2)

b' = k\cdot b(3)

h' = k\cdot h(4)

Where:

b' - Dilated base of the triangle, dimensionless.

h' - Dilated height of the triangle, dimensionless.

A' - Dilated area of the triangle, dimensionless.

k - Dilation factor, dimensionless.

If we know that k = 1.2, then the area formula for the dilated triangle is:

A' = (1)/(2)\cdot (k\cdot b)\cdot (k\cdot h)

A' = k^(2)\cdot (1)/(2)\cdot b\cdot h

A' = k^(2)\cdot A

Therefore, the area of triangle M is 1.44 times the area of triangle M.

Answer:

C- The area of triangle M'is 1.44 times the area of triangle M.

Step-by-step explanation:

1.44 divided by 1.2=1.2
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