Find the value of a²-b² when a-b=3 and a+b=4​

Answers

Answer 1
Answer:

Answer:

12

{x}^(2) -  {y}^(2) = (x - y) * (x + y) = 3 * 4 = 12


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How do you do this.?

Answers

ok so
parabola standard form is
y=ax^2+bx+c

if you have the points
(-2,18)
(0,4)
(4,24)

sub points to find a,b and c

(-2,18)
sub -2 for x and sub 18 for y
18=a(-2)^2+b(-2)+c
18=4a-2b+c

(0,4)
sub 0 for x, nice a, an b cancel
4=a(0)^2+b(0)+c
4=0+0+c
4=c
we can sub that back later

(4,24)
24=a(4)^2+b(4)+c
24=16a+4b+c

we have

18=4a-2b+c
c=4
24=16a+4b+c
sub 4 for c

18=4a-2b+4
24=16a+4b+4
minus 4 from both sides

14=4a-2b
20=16a+4b
simlify all equations
7=2a-b
5=4a+b
add to solve for 6a
12=6a+0b
12=6a
divide both sides by 6
2=a

sub back
7=2a-b
7=2(2)-b
7=4-b
-3=b

equation is
y=2x^2-3x+4

MARKING BRAINLIEST!An airline knows that 9 out 50 passengers who book a flight do not show up. If 300 people booked a flight , how many will not show up?

Answers

54 people dont show up

Jessica took out a, $84,000 loan to buy her grandmother a house. After 10 years, she had paid $31.500 in interest. What was herinterest rate?

Answers

3.75%
_________
please mark brainliest if correct

What is the distance between points (10, 7) and (2, 7) on a coordinate plane?

Answers

The distance between points (10, 7) and (2, 7) on a coordinate plane is 8 units.

The given coordinate points are (10, 7) and (2, 7).

What is distance formula?

The distance formula which is used to find the distance between two points in a two-dimensional plane is also known as the Euclidean distance formula. On 2D plane the distance between two points (x1, y1) and (x2, y2) is Distance = √[(x2-x1)²+(y2-y1)²].

Substitute (x1, y1)=(10, 7) and (x2, y2)=(2, 7) in the distance formula, we get

Distance = √[(2-10)²+(7-7)²]

= √64

= 8 units

Therefore, the distance between points (10, 7) and (2, 7) on a coordinate plane is 8 units.

To learn more about the distance formula visit:

brainly.com/question/27262878.

#SPJ2

Hey there, you can solve this using the distance formula! 

Distance = \sqrt{(x_(2)- x_(1))^2+(y_(2)- y_(1))^2}

Where x_(1) = 10
            x_(2) = 2
            y_(1) = 7
            y_(2) = 7

So...
Distance = √((2- 10)^2+(7- 7)^2)
Distance = √((-8)^2+(0))
Distance = √(64)
Distance = 8 units

Ray is purchasing a laptop that is on sale for 25% off. He knows the function that represents the sale price of his laptop is c(p) = 0.75p, where p is the original price of the laptop. He also knows he has to pay 8% sale's tax on the laptop. The price of the laptop with tax is f(c) = 1.08c, where c is the sale price of the laptop.Determine the composite function that can be used to calculate the final price of Ray's laptop by solving for f[c(p)].

f[c(p)] = 1.83p
f[c(p)] = 1.83cp
f[c(p)] = 0.81p
f[c(p)] = 0.81cp

Answers

Answer: f[c(p)]=0.81p

Step-by-step explanation:

Given: Ray is purchasing a laptop that is on sale for 25% off.

The function that represents the sale price of his laptop :

c(p) = 0.75p, where p is the original price of the laptop.

The price function of the laptop with tax :

f(c) = 1.08c, where c is the sale price of the laptop.

Now, consider the composite function that can be used to calculate the final price of Ray's laptop .

\text{ i.e.  }f[c(p)]=f[0.75p]\n\n\Rightarrow f[c(p)]=1.08(0.75p)\n\n\Rightarrow f[c(p)]=0.81p

c(p) = 0.75p   where p is the original price of the laptop
f(c) = 1.08c    where c is the sales price of the laptop

the composite function is:

f(c(p)) = 1.08(0.75p)
f(c(p)) = 0.81p


If (x2 +3x +5)(x2 +3x - 5) = m2-n2, then find m ?

Answers

(x^2+3x+5)(x^2+3x-5)=m^2-n^2\n\n\ [(x^2+3x)+5][(x^2+3x)-5]=(m+n)(m-n)\n\nm=x^2+3x;\ n=5