Simplify: 3a + 5a PLS ANSWER ILL GIVE BRAINLIEST

Answers

Answer 1
Answer:

Answer:

the answer is 8a

Step-by-step explanation:

becuase the numbers are simply being added, you can just add 3+5.

for example, say a=3

3(a)+5(a)=3(3)+5(3)

9+15=24

but 3+5(a)=8(a)

8(3)=24

Answer 2
Answer:

Answer:

8a2

Step-by-step explanation:


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What’s the correct answer for this?

You have also set up a card game in which a player picks a card from a standard deck of 52 cards. The player wins if these two events occur together: E1, in which the card drawn is a black card, and E2, in which the card drawn is a numbered card, 2 through 10.What is the probability of getting a black card and a numbered card? Calculate the probabilities P(E1) and P(E2) as fractions.

Answers

n (S) = 5\n n (E_1) = 2 x 13 = 26\nP (E_1) (n (E_1))/(n (S)) = \frac {26}{52} = (1)/(2) \n\n n (E_2) 4 x 9 = 36\nP (E_2)(n (E_2))/(n (S))=(36)/(52)= (9)/(13)

EDMENTUM / PLATO ANSWER!!!!!!!!

CAN JUST WRITE:

P (E_1) (n (E_1))/(n (S)) = \frac {26}{52} = (1)/(2) =  (50%)

P (E_2)(n (E_2))/(n (S))=(36)/(52)= (9)/(13) =  (69.2%) :)))))

First, let's count:

there are 26 possible outcomes for E1 (black card)

there are 4x9 = 36 possible outcomes for E2, to pick a numbered card (any color)

there are 2x9 =18 possible outcomes for E1 (black) AND E2 (numbered, spade + clower)

the probability of E1 AND E2 is the ratio of the count of possible outcomes for E1 + E2 and the count of all possible outcomes (52 choices to pick a card from the deck):

P(E1 and E2) = 18/52 (34.6%)

And as asked:

P(E1) = 26/52 = 1/2 (50%)

P(E2) = 36/52 = 9/13 (69.2%)

Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]

Answers

Answer:

The answer is "\bold{\left[\begin{array}{cc}a&b\nc&d\end{array}\right] = \left[\begin{array}{cc}7&-2\n -(1)/(2)&(7)/(2)\end{array}\right]}".

Step-by-step explanation:

\bold{\left[\begin{array}{cc}1&2\n3&4\end{array}\right] \left[\begin{array}{cc}a&b\nc&d\end{array}\right] = \left[\begin{array}{cc}6&5\n 19&8\end{array}\right]}

Solve the L.H.S part:

\left[\begin{array}{cc}1&2\n3&4\end{array}\right] \left[\begin{array}{cc}a&b\nc&d\end{array}\right]\n\n\n\left[\begin{array}{cc}a+2c&b+2d\n3a+4c&3b+4d\end{array}\right]

After calculating the L.H.S part compare the value with R.H.S:

\left[\begin{array}{cc}a+2c&b+2d\n3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\n 19&8\end{array}\right]} \n\n

\to a+2c =6....(i)\n\n\to b+2d =5....(ii)\n\n\to 3a+4c =19....(iii)\n\n\to 3b+4d = 8 ....(iv)\n\n

In equation (i) multiply by 3 and subtract by equation (iii):

\to 3a+6c=18\n\to 3a+4c=19\n\n\text{subtract}... \n\n\to 2c = -1\n\n\to  c= - (1)/(2)

put the value of c in equation (i):

\to a+ 2 (- (1)/(2))=6\n\n\to a- 2 * (1)/(2)=6\n\n\to a- 1=6\n\n\to a =6 +1\n\n\to a = 7\n

In equation (ii) multiply by 3 then subtract by equation (iv):

\to 3b+6d=15\n\to 3b+4d=8\n\n\text{subtract...}\n\n\to 2d = 7\n\n\to d= (7)/(2)\n

put the value of d in equation (iv):

\to 3b+4 ((7)/(2))=8\n\n\to 3b+4 * (7)/(2)=8\n\n\to 3b+14=8\n\n\to 3b =8-14\n\n\to 3b = -6\n\n\to b= (-6)/(3)\n\n\to b= -2

The final answer is "\bold{\left[\begin{array}{cc}a&b\nc&d\end{array}\right] = \left[\begin{array}{cc}7&-2\n -(1)/(2)&(7)/(2)\end{array}\right]}".

Rewrite the equation by completing the square. x^2-14+33=0

Answers

Answer:

(x - 7)² = 16

General Formulas and Concepts:

Pre-Algebra

  • Order of Operations: BPEMDAS
  • Equality Properties

Algebra I

  • Completing the Square

Step-by-step explanation:

Step 1: Define

x² - 14x + 33 = 0

Step 2: Rewrite

  1. Isolate x terms:                    x² - 14x = -33
  2. Complete the Square:         x² - 14x + 49 = -33 + 49
  3. Reduce:                               (x - 7)² = 16

And we have our rewritten form!

Consider the following functions. f(x) = x − 3, g(x) = x2 Find (f + g)(x). Find the domain of (f + g)(x). (Enter your answer using interval notation.) Find (f − g)(x). Find the domain of (f − g)(x). (Enter your answer using interval notation.) Find (fg)(x). Find the domain of (fg)(x). (Enter your answer using interval notation.) Find f g (x). Find the domain of f g (x). (Enter your answer using interval notation.)

Answers

Answer:

(f+g)(x)=x-3+x^2 ; Domain = (-∞, ∞)

(f-g)(x)=x-3-x^2 ; Domain = (-∞, ∞)

(fg)(x)=x^3-3x^2 ; Domain = (-∞, ∞)

((f)/(g))(x)=(x-3)/(x^2) ; Domain = (-∞,0)∪(0, ∞)

Step-by-step explanation:

The given functions are

f(x)=x-3

g(x)=x^2

1.

(f+g)(x)=f(x)+g(x)

Substitute the values of the given functions.

(f+g)(x)=(x-3)+x^2

(f+g)(x)=x-3+x^2

The function (f+g)(x)=x-3+x^2 is a polynomial which is defined for all real values x.

Domain of (f+g)(x) = (-∞, ∞)

2.

(f-g)(x)=f(x)-g(x)

Substitute the values of the given functions.

(f-g)(x)=(x-3)-x^2

(f-g)(x)=x-3-x^2

The function (f-g)(x)=x-3-x^2 is a polynomial which is defined for all real values x.

Domain of (f-g)(x) = (-∞, ∞)

3.

(fg)(x)=f(x)g(x)

Substitute the values of the given functions.

(fg)(x)=(x-3)x^2

(fg)(x)=x^3-3x^2

The function (fg)(x)=x^3-3x^2 is a polynomial which is defined for all real values x.

Domain of (fg)(x) = (-∞, ∞)

4.

((f)/(g))(x)=(f(x))/(g(x))

Substitute the values of the given functions.

((f)/(g))(x)=(x-3)/(x^2)

The function ((f)/(g))(x)=(x-3)/(x^2) is a rational function which is defined for all real values x except 0.

Domain of (f/g)(x) = (-∞,0)∪(0, ∞)

(f + g)(x) = x^2 + x - 3, domain: all real numbers.

(f - g)(x) = -x^2 + x - 3, domain: all real numbers.

(fg)(x) = x^3 - 3x^2, domain: all real numbers.

f(g(x)) = x^2 - 3, domain: all real numbers.

To find (f + g)(x), we need to add the functions f(x) and g(x).

The function f(x) = x - 3 and the function g(x) = x^2.

So, (f + g)(x) = f(x) + g(x) = (x - 3) + (x^2).

Expanding this equation, we get (f + g)(x) = x^2 + x - 3.

To find the domain of (f + g)(x), we need to consider the domain of the individual functions f(x) and g(x).

Since both f(x) = x - 3 and g(x) = x^2 are defined for all real numbers, the domain of (f + g)(x) is also all real numbers.

To find (f - g)(x), we need to subtract the function g(x) from f(x).

So, (f - g)(x) = f(x) - g(x) = (x - 3) - (x^2).

Expanding this equation, we get (f - g)(x) = -x^2 + x - 3.

The domain of (f - g)(x) is also all real numbers, since both f(x) and g(x) are defined for all real numbers.

To find (fg)(x), we need to multiply the functions f(x) and g(x).

So, (fg)(x) = f(x) * g(x) = (x - 3) * (x^2).

Expanding this equation, we get (fg)(x) = x^3 - 3x^2.

The domain of (fg)(x) is all real numbers, since both f(x) and g(x) are defined for all real numbers.

To find f(g(x)), we need to substitute g(x) into the function f(x).

So, f(g(x)) = f(x^2) = x^2 - 3.

The domain of f(g(x)) is also all real numbers, as g(x) = x^2 is defined for all real numbers, and f(x) = x - 3 is defined for all real numbers.

In summary:

- (f + g)(x) = x^2 + x - 3, domain: all real numbers.

- (f - g)(x) = -x^2 + x - 3, domain: all real numbers.

- (fg)(x) = x^3 - 3x^2, domain: all real numbers.

- f(g(x)) = x^2 - 3, domain: all real numbers.

To Learn more about real numbers here:

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An architect uses a scale of 2/3inch to represent 1 foot on a blueprint for a building. If the east wall of the building is 24 feet long, how long (in inches) will the line be on the blueprint?

Answers

 Length of the wall on blueprint will be 16 inches.

Use of scale to calculate the distances or length,

  Scale used by an architect on a blueprint,

                 (2)/(3)\text{ inch}= 1\text{ foot}

Scale represents the ratio of the length of the wall on blueprint and actual length,

\frac{\text{Length on the blueprint}}{\text{Actual length}} =\frac{(2)/(3)\text{ inches}}{1\text{ feet}}

\frac{\text{Length on the blueprint}}{\text{Actual length}} =(2)/(3)

If actual length of the east wall of the building = 24 feet

Substitute the value in the expression representing the ratio,

\frac{\text{Length on the blueprint}}{24} =(2)/(3)

Length of the blueprint = (2)/(3)* 24

                                       = 16 inches

    Therefore, length of the wall on blueprint will be 16 inches.

Learn more about the use of scale to calculate the distances on map.

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Answer:

16 in.

Step-by-step explanation:

We have the ratio

(in.)/(ft): ((2)/(3) )/(1)

How about let's make this easier.  Easier is better, right?  Let's get rid of the fraction 2/3.  We will do that by multiplying 2/3 by 3 and 1 by 3 to get the equivalent ratio of

(in.)/(ft):(2)/(3)

Now we need to know how many inches there would be if the number of feet is 24:

(in.)/(ft):(2)/(3)  =(x)/(24)

Cross multiply to get

3x = 48 so

x = 16 in.

From a set of 5 nickels, 10 dimes and 15 quarters, six coins are removed at random without replacement. a. Find the probability of not removing 6 quarters.
b. Find the probability of removing exactly 2 nickels, 2 dimes and 2 quarters.

Answers

Answer:

(a) 1 - (15 C 6) / (30 C 6)

(b)  (5 C 2) x (10 C 2) x (15 C 2) / (30 C 2)

Step-by-step explanation:

Number of  nickels = 5

Number of dimes = 10

Number of quarters = 15

(a) The probability of getting 6 quarters  

= (15 C 6) / (30 C 6)

So, the probability of not getting 6 quarters = 1 - (15 C 6) / (30 C 6)

(b) Probability of getting 2 nickels , 2 dimes and 2 quarters

= (5 C 2) x (10 C 2) x (15 C 2) / (30 C 2)