MATHEMATICS COLLEGE

Find the value of X
72 (x +4)

Answers

Answer 1

Answer:

Answer:

72x + 288

Step-by-step explanation:

You would multiply 72 with (x + 4), which would leave you with 72x + 288. The value of x would be 72 i think

Related Questions

What is the surface area of the pyramid 8in 8 in 6in.
What is the slope of the line?
A university financial aid office polled a random sample of 528 male undergraduate students and 651 female undergraduate students. Each of the students was asked whether or not they were employed during the previous summer. 295 of the male students and 463 of the female students said that they had worked during the previous summer. Give a 80% confidence interval for the difference between the proportions of male and female students who were employed during the summer.A) Find the values of the two sample proportions (round to three decimals)B) Find the critical value that should be used in constructing the confidence interval.C) Find the value of the standard error. Round your answer to three decimal places.D) Construct the 95% confidence interval. Round your answers to three decimal places.
There are 12 squares and 9 circles . What is the simplest ratio of circles to total shapes?
If you can simplify this equation to the final stage I will reward you!! Try you're best!! I will not give my points to people that don't deserve them :)

Kristl has saved 30%of her tuition for
dance class. She
needs to have $600
save. How much has
she saved so far?

Answers

Answer:

$180

Step-by-step explanation:

What is the image of 2,-1 after a reflection over the y axis

Answers

The image of the point after a reflection over the y-axis is (-2, -1)

Calculating the image of the point after a reflection over the y-axis?

From the question, we have the following parameters that can be used in our computation:

Point = (2, -1)

Transformation rule

A reflection over the y-axis

The rule of a reflection over the y-axis is

(x, y) = (-x, y)

Using the above as a guide, we have the following:

Image = (-2, -1)

Hence the image of the point after a reflection over the y-axis is (-2, -1)

Answers

Final answer:

The local linearizations of f(x) and g(x) at a = 1 are Lf(x) = 4x - 5 and Lg(x) = 2x - 2 respectively. The function h(x) ≈ Lf(x)/Lg(x) because the local linearizations provide a good approximation of the numerator and denominator of h(x) near x = 1.

Explanation:

The local linearization of a function at a given point is an approximation of the function using a linear equation. To find the local linearization of a function f at a = 1, we need to find the slope of the tangent line at a = 1, which is equivalent to finding the derivative of f at x = 1. By taking the derivative of f(x) = x³ + x - 2, we get f'(x) = 3x² + 1. Evaluating f'(1), we find that the slope of the tangent line at a = 1 is 4. Therefore, the local linearization of f at a = 1, denoted as Lf(x), is given by Lf(x) = f(a) + f'(a)(x - a), which becomes Lf(x) = -1 + 4(x - 1) = 4x - 5.

Similarly, to find the local linearization of g(x) = x² - 1 at a = 1, we need to find the slope of the tangent line at a = 1. The derivative of g(x) is g'(x) = 2x. Evaluating g'(1), we find that the slope of the tangent line at a = 1 is 2. Therefore, the local linearization of g at a = 1, denoted as Lg(x), is given by Lg(x) = g(a) + g'(a)(x - a), which becomes Lg(x) = 0 + 2(x - 1) = 2x - 2.

When investigating the behavior of the function h(x) = (f(x))/(g(x)) near the point x = 1, we can approximate h(x) using the local linearizations of f and g at a = 1. Near the point a = 1, h(x) ≈ Lf(x)/Lg(x) because Lf(x) and Lg(x) provide a good approximation of the numerator and denominator, respectively, of h(x). This approximation holds as long as x is close to 1.

Learn more about local linearizations of functions here:

brainly.com/question/34258619

What are the cordinates of the image of the point (11,1)after a translation 10 units down followed by a reflection over the y-axis

Answers

Answer:

(-11,-9)

Step-by-step explanation:

translate 10 units down: y value: 1-10=-9

reflect over y-axis: x-value becomes opposite: 11 becomes -11

Rolling a 12 sided die find the odds in favor of rolling a 5
rolling a multiple of 3
rolling an odd number
rolling a number greater than 6

Find each probability of
P(5)
P(# less than 3)
P(odd)
P(13)

Answers

Answer:

1/12 , 1/3 , 1/2 , 1/2

Step-by-step explanation:

P(x) = favorable of x / total

plug in your conditions and you get the probablility

Answer:

1/12 for rolling a 5.

4/12 for multiples of 3. (3,6,9,12)

6/12 for rolling an odd number.(1,3,5,7,9,11)

6/12 for rolling a number greater than 6. (7,8,9,10,11,12)

Step-by-step explanation:

Minimizing Construction Costs The management of the UNICO department store has decided to enclose a 945 ft2 area outside the building for displaying potted plants and flowers. One side will be formed by the external wall of the store, two sides will be constructed of pine boards, and the fourth side will be made of galvanized steel fencing. If the pine board fencing costs $7/running foot and the steel fencing costs $4/running foot, determine the dimensions of the enclosure that can be erected at minimum cost. (Round your answers to one decimal place.)

Answers

Answer:

Pine board side = 16.4 ft

Steel fencing side = 57.5 ft

Step-by-step explanation:

Let 'B' be the length of each side constructed of pine boards, and 'S' be the length of the side with the steel fencing, the area (A) and cost (C) functions are:

$945 = B*S\nB=(945)/(S) \nC= 4*S+7*2B\nC=4S+(13,230)/(S)$

The value of S for which the derivate of the cost function is zero, minimizes cost:

$C'=0=4+(-13,230)/(S^2)\n S=√(3,307.5) \nS=57.5 ft$

The value of B is:

$B=(945)/(57.5)\nB=16.4 \ ft$

Pine board side = 16.4 ft

Steel fencing side = 57.5 ft

Final answer:

To minimize the construction costs for the enclosure, the dimensions should be calculated using the calculus optimization technique. By incorporating the cost and area requirements into calculated equations and solving, you will find x = 2 times y. This is how you minimize the cost.

Explanation:

This problem involves the application of calculus and optimization techniques. Given that the area of the enclosure needs to be 945 ft2, and that it is adjacent to an external wall of the department store, we can infer that its shape is rectangular.

Let the width of the enclosure parallel to the department store be x (feet), and its length perpendicular to the store be y (feet). According to the area requirement, we have the equation x*y = 945 ft2.

The cost of the enclosure is the sum of the cost of the pine board fences and the steel fence. Since 2 sides are made of pine boards, and 1 side made of steel, the cost can be expressed as C = 2xy p + y s, where 'p' is the cost of pine board per foot ($7), and 's' is the cost of steel per foot ($4).

Since we are looking for the minimum cost, we derive this equation and set it equal to zero to find the dimensions x and y. After substituting and simplifying, we find that the minimum cost is obtained when x = 2 y. By substituting this into the area equation, we can solve for the dimensions of the enclosure.