(2x-8)times(3x-2) pls help

Answers

Answer 1
Answer: 6x^2-28x+16 hope this helps
Answer 2
Answer:

Answer:

6x^2-28x+16

Step-by-step explanation:


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A farmer notes that in a field full of horses and chickens there are 35 heads and 98 feet. How many of each animal are there?

Answers

Answer:

There are 14 horses and 21 chickens.

Step-by-step explanation:

First, you have to make expression for horse and chicken. So we can let x be the number of horses and y will be the number of chickens. Next, given that the total number of feet for both animals is 98 so you have to make simultaneous equation :

4x + 2y = 98

(horse has 4 feet and chicken has 2 feet)

There are a total of 35 heads so the other equation will be :

x + y = 35

Lastly, you have to solve it :

4x + 2y = 98

2(2x + y) = 98

2x + y = 49 -  -  - (1)

x + y = 35 -  -  - (2)

(1) - (2)

2x  + y - x - y = 49 - 35

x = 14

substitute \: x = 14 \: into \: (2)

14 + y = 35

y = 35 - 14

y = 21

Raj recorded the scores of six of his classmates in the table.Math Scores
98
76
100
88
82
70

What is the range of their test scores?

Answers

The answer is 30. Range: largest number - smallest number = range

There are two more assignments in your course before the semester ends, and if you get an A on at least one of them, you will get an A for the semester. Your "what-if" scenario looks like this:Event Probability

A on paper and A on presentation 0.25
A on paper only 0.10
A on presentation only 0.30
Do not get an A on either 0.35

Answer the following questions: (1 point each, except the last item, 2 points)

a. What is the probability of getting an A on the paper?
b. What is the probability of getting an A on the presentation?
c. What is the probability of getting an A in the course?
d. Are the grades on the assignments independent? Explain your answer

Answers

Answer:

Step-by-step explanation:

Hello!

Given the events:

A: "obtain an A in the paper assigment" ⇒ P(A)= 0.10

B: "obtain A in the presentation assigment" ⇒ P(B)= 0.30

Ac: "do not get an A in the paper assigment" ⇒ P(Ac)= 1 - 0.10= 0.9

Bc: "do not get an A in the presentation assigment" ⇒ P(Bc)= 1 - 0.30= 0.7

P(A∩B)= 0.25

P(Ac∩Bc)= 0.35

a. P(A)= 0.10

b. P(B)= 0.30

c. To get an A in the course you have to get an A in the paper and an A in the presentation, symbolically: P(A∩B)= 0.25

d. If the events A and B are independent, then the ocurrence of one of them doesn't affect the probability of the other ocurring, if this is so then:

P(A)= P(A/B)

P(A/B)= (P(AnB))/(P(B)) = (0.25)/(030)= 0.83

P(A) ≠ P(A/B) this means that "B" ocurring modifies the probability of ocurrence of A, i.e. both events are not independent.

I hope it helps!

Evaluate the function.
f(x)=-2x^2-7x+6

Find f(−3)

Answers

Answer:

f(-3) = 9

Step-by-step explanation:

Step 1: Define

f(x) = -2x² - 7x + 6

f(-3) = x = -3

Step 2: Substitute and evaluate

f(-3) = -2(-3)² - 7(-3) + 6

f(-3) = -2(9) + 21 + 6

f(-3) = -18 + 21 + 6

f(-3) = 3 + 6

f(-3) = 9

Substituting x = -3 into the function f(x) = -2x^2 - 7x + 6, we get f(-3) = -33. Therefore, the value of the function at x = -3 is -33.

To evaluate the function f(x)=−2x ^2 −7x+6 at  x=−3, substitute  −3 for x in the function: f(−3)=−2{(−3) }^2 −7(−3)+6

Now, calculate each part of the expression:

(−3) ^2   is 9  because the square of  −3 is  9.

−2 times 9 is  −18 because −2⋅9 =−18.

−7 times −3 is  21 because −7⋅−3=21.

Now, plug these values back into the expression:

f(−3)=−18−21+6

Finally, add and subtract:

f(−3)=(−18−21)+6=−39+6=−33

So, f(−3)=−33.

The value of the function

f(x)=−2x^ 2 −7x+6 at  x=−3 is  −33.

For more questions on function

brainly.com/question/11624077

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The opening prices per share Y1 and Y2 of two similar stocks are independent random variables, each with a density function given by

Answers

Answer:given by what?

Driving along, terry notices that the last four digits on his car's odometer are palindromic. a mile later, the last five digits are palindromic. after driving another mile, the middle four digits are palindromic. one more mile, and all six are palindromic. what was the odometer reading when terry first looked at it? form a linear system of equations that expresses the requirements of this puzzle.

Answers

Designate the initial digits, left to right, as {a, b, c, d, d, c}.

After adding one mile, the digits are {a, b, c, d, c, b}, so the relevant equation is
  10c +b = 10d +c +1

After adding another mile, the digits are {a, b, c, c, b, e}, so the relevant equation is
  100c +10b +e = 100d +10c +b +1

After another mile, the digits are {a, b, c, c, b, a}, so the relevant equation is
  a = e +1

In summary, we have 3 equations in 5 unknowns.
  b + 9c -10d = 1
  9b +90c -100d +e = 1
  a - e = 1

along with the constraints {a, b, c, d, e} ∈ {0, ..., 9}


_____
These have the solution {a, b, c, d, e} = {1, 9, 8, 8, 0}, so the odometer readings were
  198888
  198889
  198890
  198891