A bicycle wheel has a circumference of 75 inches. What is the approximate radius of the wheel?
Answers
Answer:
23.87
Step-by-step explanation:
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I need help quick A student is cutting a square out of a piece of poster board. The area of the poster board can be represented as (4x ^ 2 + 14x - 8) in ^ 2 The area of the square can be represented as (x ^ 2 + 8x + 16) in^2 Write an expression to represent the area of the poster board left over after the student cuts out the square
A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 6 L/min; the well-mixed solution is pumped out at the same rate. Find the number A(t) of grams of salt in the tank at time t.
Answers
The factored expression of the expression x^3 + 4x^2 +5x + 20 is (x^2 + 5)(x + 4)
How to determine the factors?
The expression is given as:
x^3 + 4x^2 +5x + 20
Group the expression into two
(x^3 + 4x^2) + (5x + 20)
Factorize each group
x^2(x + 4) + 5(x + 4)
Factor out x + 4
(x^2 + 5)(x + 4)
Hence, the factored expression of the expression x^3 + 4x^2 +5x + 20 is (x^2 + 5)(x + 4)
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Answers
Answer:
Possible options:
= -4 * 3 1/4
= -4 * 13/4
= -4 * 3.25
Step-by-step explanation:
Without the options that seemed to go along with this question, it will be difficult to give the exact expression, but here are a few options.
-4 * 3 1/4 = -13
-4 * 13/4 = -13
-4 * 3.25 = -13
Each of these expressions will give the product of -4 and 3 1/4.
Cheers
Answers
Answer:
The answer is 2 7/8
Final answer:
Hector exercises 2.875 hours per week, which is calculated by dividing the total of 11 1/2 hours he exercised during the 4 weeks by 4.
Explanation:
Hector wants to compare his exercise rate with the fitness challenge rate. To find out how many hours per week Hector exercises, we need to divide the total hours he exercised in a 4-week period by the number of weeks.
Hector exercised for 11 1/2 hours during 4 weeks, which is equal to 11.5 hours. Dividing 11.5 hours by 4 weeks gives us:
11.5 hours ÷ 4 weeks = 2.875 hours per week
Thus, Hector exercises 2.875 hours per week, which is slightly more than the 2 1/2 hours (or 2.5 hours) per week recommended by the fitness challenge.
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Answers
Answer:
Missing reason/statements:
- R1, R2, R3 - Given
- S4. ∠1 ≅ ∠3
- R4. Transitive property
- R5. Definition of congruence
- S6. m∠1 = 120°
- R6. Substitution
Answers
Use the empirical rule (68 - 95 - 99.7%) to estimate the probability of a gorilla living longer than 14.3
years.
Percent % pls
Answers
the probability of a gorilla living longer than 14.3 years is 83.9%
Given :
The lifespans of gorillas in a particular zoo are normally distributed
Mean is 16 years and standard deviation is 1.7 years
Empirical rule diagram is attached below
We need to find the probability of a gorilla living longer than 14.3
Lets find out 14.3 lies in which standard deviation on left or right
mean is 16
14.3 lies on first standard deviation on left of mean 16
So we find out the area that covers after 14.3
The area after 14.3 is
the probability of a gorilla living longer than 14.3 years is 83.9%
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Final answer:
The probability of a gorilla living longer than 14.3 years is estimated to be 81.2% using the empirical rule.
Explanation:
To estimate the probability of a gorilla living longer than 14.3 years, we can use the empirical rule, also known as the 68-95-99.7% rule. According to this rule, for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations.
The average lifespan of gorillas in this zoo is 16 years, with a standard deviation of 1.7 years. To estimate the probability of a gorilla living longer than 14.3 years, we need to calculate the z-score. The z-score formula is:
z = (x - μ) / σ
where x is the value we want to find the probability for, μ is the mean, and σ is the standard deviation.
Plugging in the values, we have:
z = (14.3 - 16) / 1.7
Solving this, we get a z-score of -0.88. Using a z-table or a calculator, we can find that the probability of a gorilla living longer than 14.3 years is approximately 0.812, or 81.2%.
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