A plate moves south at a rate of 2 cm/year. How many meters south from its original location will the plate be in 4,000 years? 8,000 meters south 4,000 meters south 200 meters south 80 meters south

Answers

Answer 1

Answer:

The distance (in meters south) the plate will be given that the plate is moving at a rate of 2 cm/year is 80 meters south (last option)

How do i determine the distance?

Speed is defined as distance travelled per unit time. This is mathematically written as

Speed = Distance travelled / time

If we make distance the subject, we have

Distance travelled = Speed × time

The following data were obtained from the question:

Speed of plate = 2 cm/year = 2 / 100 = 0.02 m/year
Time = 4000 years
Distance travelled =?

Distance travelled = Speed × time

Distance travelled = 0.02 × 4000

Distance travelled = 80 meters south

Thus, we can conclude that the distance travelled is 80 meters south (last option)

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Answer 2

Answer:

the plate will be 80 meters south from its original location in 4,000 years. The correct answer is (d) 80 meters south.

The plate moves south at a rate of 2 cm/year. To find out how many meters south it will be in 4,000 years, we need to convert the years to centimeters and then meters.

In 4,000 years, the plate will have moved: 2 cm/year x 4,000 years = 8,000 cm.

Now, to convert 8,000 cm to meters, we need to divide by 100 (since there are 100 centimeters in a meter):

8,000 cm / 100 = 80 meters.

So, the plate will be 80 meters south from its original location in 4,000 years. The correct answer is (d) 80 meters south.

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Complete question is:

A plate moves south at a rate of 2 cm/year. How many meters south from its original location will the plate be in 4,000 years?

a. 8,000 meters south

b. 4,000 meters south

c. 200 meters south

d. 80 meters south

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One way to remove nitrogen oxide from smokestack emissions is to react it with ammonia: 4 NH3 (g) + 6 NO (g) ----------> 5 N2 (g) + 6H2O (I)Fill in the blanks below:

12.3 mol of NO reacts with ______ mol of ammonia
5.87 mol of NO yields _______ mol nitrogen

Answers

Final answer:

12.3 moles of nitrogen oxide (NO) react with 8.2 moles of ammonia (NH3) in the given reaction. The reaction of 5.87 moles of NO yields 4.89 moles of nitrogen (N2).

Explanation:

The overall reaction equation represents an ideal stoichiometric ratio where 4 moles of ammonia (NH3) react with 6 moles of nitrogen oxide (NO) to produce 5 moles of nitrogen (N2) and 6 moles of water (H2O). Let's work with this ratio to fill in the blanks of your question.

Given that 6 moles of NO react with 4 moles of NH3, we can set up a ratio to find the unknown quantity of NH3 that reacts with 12.3 moles of NO: (4 NH3 / 6 NO) x 12.3 NO = 8.2 moles of NH3

Similarly, 5 moles of nitrogen are produced per 6 moles of NO reacted, so we can find out how much nitrogen is produced from 5.87 moles of NO: (5 N2 / 6 NO) x 5.87 NO = 4.89 moles of nitrogen.

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Final answer:

12.3 moles of NO reacts with 8.2 moles of Ammonia. 5.87 moles of NO yields 4.89 moles of Nitrogen.

Explanation:

In these types of problems, we use the concept of mole ratios from the balanced chemical equation. According to the reaction, 4 moles of NH3 react with 6 moles of NO to yield 5 moles of N2. Therefore, for 12.3 moles of NO, we apply the ratio 4/6 to determine that it reacts with 8.2 moles of NH3.

Similarly, 5.87 moles of NO, based on the ratio 5/6, yields 4.89 moles of N2. So, these are the missing quantities for the reaction.

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Pentane, C5H12, will react as shown below:____C5H12(l) + ____O2 --- ______CO2 +_______ H2O

H20(g)

1. Balance the equation above by putting coefficients into each blank space.

1C5H12+ 8O2----- 5CO2+ 6 H2O (this is what I got)

2. How many atoms of oxygen are in 144 grams of pentane?

step 1: 144g of C5H12*(1mole/72.17)= 1.995moles of C5H12
step 2: 1.995moles of C5H12*(8moles of O2/1mole of C5H12)= 15.962 moles of O2
step 3: 15.962 moles of O2*(6.02*10^23 atoms of O2/1mole of O2)= 9.609*10^24 atoms of O2 (I don't know if I did this right)

3. How many atoms of oxygen are in 192 grams of carbon dioxide gas?

step 1: 192 grams of CO2 *(1mole of CO2/44.01grams of CO2)= 4.363 moles of CO2
step two: 4.36moles of CO2* ( 1 mole of O2/1mole of CO2)=
step 3: 4.363* (6.02*10^23) = 2.627*10^24 atoms of O2 (I don't know if this is correct.

4. A) CIRCLE ONE: True or False:

reactant you begin with fewer grams of is your limiting reactant.

B) If 32 g of oxygen gas and 32 g of pentane are combined, how much water will be produced, in moles? (Use your reaction from the top of the first page)

NEED HELP ASAP THANK YOU!!!

Answers

1) That looks right

2) Step 1: Moles=Mass/Mr, so it's 144/72= 2mol
Step 2: Stoichiometry means the ratio of oxygen to pentane is 1:8 so moles of oxygen is moles of pentane times 8. 2*8=16mol of oxygen
Step 3: 16= 9.6*10^24

3) The ratio of oxygen to carbon in CO2 is 1:2
so it's 192/3 = 64
64*2=128g
Moles = Mass/Mr = 128/32 = 4mol = 2.41*10^24 atoms of oxygen
Basically you needed to work out the mass of oxygen using ratios before using a moles equation instead of just working with moles

4) True

5) 1C5H12+ 8O2----- 5CO2+ 6 H2O
32g 32g

Moles of oxygen = Mass/Mr = 32/32= 1mol so you'd need 0.125mol of pentane to react fully
Moles of pentane= Mass/Mr = 32/72=0.4mol so you'd need 3.2mol of oxygen to react fully

This makes oxygen the limiting factor, because you need more of it to react fully with the pentane, so we use oxygen

Stoichiometry means for every 8mol of oxygen there's 5mol of CO2
So, 1/8*5=0.635mol of CO2

In Rutherford's gold foil experiments, some alpha particles were deflected from their original paths but most passed through the foil with no deflection. Which statement about gold atoms is supported by these experimental observations

Answers

The experiment shows that the atoms are mostly empty spaces with most of the mass concentrated at the center, which is the nucleus of the atom.

What are Rutherford's experiments?

Rutherford's model also called Rutherfords' atomicmodel was a model describing the nuclear atom or the planetary model of the atom. It gave a description of the structure of atoms.

It was proposed the year 1911 by the New Zealand-born physicist named ErnestRutherford. This model was used to describe the atom. It described the atom as tiny and dense which has a positively charged core called the nucleus.

In the nucleus of the atom, almost all the mass is the atom is concentrated. Around the nucleus, there are the light, negative particles which are called electrons. These circulate around the nucleus at some distance like planets revolve around the Sun.

Therefore, the experiment shows that the atoms are mostly empty spaces with most of the mass concentrated at the center, which is the nucleus of the atom.

Answers

elements and compounds might appear different, yet they share many similarities, like being made up of atoms and having bonds linking their atoms together. Elements and compounds also share the qualities of being both pure and homogeneous substances. Substances can be categorised as either elements or compounds. Both of these are made up of atoms, the only difference is an element is made of one type of atom whereas compounds are made of two or more different types of atoms.

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