Answers
Answer:
1. Flourine, 2 Ruthenium, 3 Germanium, 4 Francium
Explanation:
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Assuming 54.81 grams of Al are consumed in the presence of excess copper II chloride dihydrate, how many grams of AlCl3 can be produced if the reaction will only produce 66.93 % yield?
b. 8.5 x 10-6 M
c. 6.3 x 10-11 M
d. 1.3 x 10-12 M
e. 5.0 x 10-2 M
f. 1.8 x 10-5 M
Answers
Answer:
c. 6,3x10⁻¹¹M
Explanation:
The solubility of a buffer is defined as the concentration of the dissolved solid in a saturated solution. For the Cd(OH)₂, solubility is:
[Cd²⁺] = S
The dissolution of Cd(OH)₂ is:
Cd(OH)₂ ⇄ Cd²⁺ + 2OH⁻
And the ksp is defined as:
ksp = [Cd²⁺][OH⁻]²
As ksp = 2,5x10⁻¹⁴ and [OH⁻] at pH=12,30 = 10^-(14-12,30) = 0,01995M
2,5x10⁻¹⁴ = [Cd²⁺]×(0,01995M)²
[Cd²⁺] = 6,3x10⁻¹¹M
That means solubility is c. 6,3x10⁻¹¹M
I hope it helps!
Final answer:
The molar solubility of Cd(OH)2 when buffered at a pH of 12.30 can be calculated using the concept of hydrolysis. The correct answer is 6.3 x 10^(-11) M.
Explanation:
To calculate the molar solubility of Cd(OH)2 when buffered at a pH of 12.30, we need to use the concept of hydrolysis. Cd(OH)2 is a slightly soluble salt that undergoes hydrolysis in aqueous solution. At a high pH value, OH- ions react with water to form more OH- ions, shifting the equilibrium towards the hydrolysis reaction.
- First, we write the balanced equation for the hydrolysis reaction: Cd(OH)2(s) ⇌ Cd2+(aq) + 2OH-(aq)
- Since OH- is being produced, we can assume that the concentration of OH- is much greater than that of Cd2+. Therefore, we can ignore the concentration of Cd2+ when calculating the solubility product (Ksp).
- Next, we use the equation for the hydrolysis reaction to write the expression for the solubility product constant (Ksp): Ksp = [Cd2+][OH-]^2
- The concentration of OH- ions in a basic solution is related to the pH by the equation: pOH = 14 - pH
- Using this equation, we can calculate the pOH of the buffered solution: pOH = 14 - 12.30 = 1.70
- Then, we convert the pOH back to OH- concentration: [OH-] = 10^(-pOH) = 10^(-1.70)
- Finally, we substitute the calculated [OH-] into the expression for Ksp to solve for the molar solubility of Cd(OH)2: [Cd(OH)2] = sqrt(Ksp / [OH-]^2)
After performing the calculations, the molar solubility of Cd(OH)2 when buffered at a pH of 12.30 is approximately 6.3 x 10^(-11) M. Therefore, the correct answer is option c. 6.3 x 10^(-11) M.
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Answers
Answer:
The less electronegative atom
Explanation:
Water contains polar bonds. Water is made up of oxygen and hydrogen. Oxygen is more electronegative then hydrogen so it is partial negative (because electron spend more time around oxygen in the polar bond), whereas, hydrogen has a partial positive charge as it is less electronegative (electrons spend less time around hydrogen in this polar bond).
B. net movement of water will be equal
C. water will not move into or out of the cell
D. water will rush out of the cell
Answers
Answers
Answer: The new concentration of the solution is 0.143 M.
Explanation:
Given: = 300.0 mL,
= 0.335 M
= 700.0 mL,
= ?
Formula used is as follows.
Substitute values into the above formula as follows.
Thus, we can conclude that the new concentration of the solution is 0.143 M.
Final answer:
To find the new concentration of the solution, you can use the formula C1V1 = C2V2. Plugging in the given values, the new concentration of the solution is 0.144 M.
Explanation:
To find the new concentration of the solution, we can use the formula:
C1V1 = C2V2
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Plugging in the given values, we get:
(0.335 M)(300.0 mL) = C2(700.0 mL)
Solving for C2, we find the new concentration of the solution to be 0.144 M.
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Answers
Answer:
A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.
Explanation:
More than one pair of electrons can be shared between atoms to form double or triple covalent bonds. Unlike ionic bonds, covalent bonds are often formed between atoms where one of the atoms cannot easily attain a noble gas electron shell configuration through the loss or gain of one or two electrons.
Answers
Solution : Water and Methanol are easily miscible in any amount. so they are not preferred for the liquid-liquid extraction process.
Liquid-Liquid Extraction is also called as solvent extraction. It is the method of seperation of compound based on their relative solubilities in two different immiscible liquids. Generally we use water (polar) and an organic solvent (non-polar).
It is important that the two solvents should not be mix because it is easy to seperate them.
Water and Methanol are easily miscible in any amount. we can not seperate them easily. So that is why we can not use water and methanol as a solvent in liquid-liquid extraction process.
Answer:
they could be joined due to hydrogen bridge-type intermolecular interactions so no phase splitting will be carried out.
Explanation:
Hello,
Liquid-liquid extraction is a widely used separation operation that is suitable when relative volatilities are so close, so an extra substance is used to modify the equilibrium causing a phase splitting (two liquid immiscible phases) which could be leveraged to mechanically separate the two phases. The basic idea lies on the fact that the extra substance must be largely immiscible with the original solvent, to the solute is selectively separated, nonetheless, in this case, water and methanol are largely soluble to each other since they could be joined due to hydrogen bridge-type intermolecular interactions so no phase splitting will be carried out.
Best regards.