There are 13 fish in an aquarium. Seven of the fish are guppies. How manynon-guppies are in the aquarium?
A. the number of guppies
B. the total number of fish
C. the number of non-guppies
( what is the variable in the problem?)
Answers
Answer:
6 non-guppies; C. the number of non-guppies
Step-by-step explanation:
13-7=x
(x is the number of non-guppies)
13-7=6
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Will give brainliest
Use the empirical rule (68 - 95 - 99.7%) to estimate the probability of a gorilla living longer than 14.3
years.
Percent % pls
Answers
the probability of a gorilla living longer than 14.3 years is 83.9%
Given :
The lifespans of gorillas in a particular zoo are normally distributed
Mean is 16 years and standard deviation is 1.7 years
Empirical rule diagram is attached below
We need to find the probability of a gorilla living longer than 14.3
Lets find out 14.3 lies in which standard deviation on left or right
mean is 16
14.3 lies on first standard deviation on left of mean 16
So we find out the area that covers after 14.3
The area after 14.3 is
the probability of a gorilla living longer than 14.3 years is 83.9%
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Final answer:
The probability of a gorilla living longer than 14.3 years is estimated to be 81.2% using the empirical rule.
Explanation:
To estimate the probability of a gorilla living longer than 14.3 years, we can use the empirical rule, also known as the 68-95-99.7% rule. According to this rule, for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations.
The average lifespan of gorillas in this zoo is 16 years, with a standard deviation of 1.7 years. To estimate the probability of a gorilla living longer than 14.3 years, we need to calculate the z-score. The z-score formula is:
z = (x - μ) / σ
where x is the value we want to find the probability for, μ is the mean, and σ is the standard deviation.
Plugging in the values, we have:
z = (14.3 - 16) / 1.7
Solving this, we get a z-score of -0.88. Using a z-table or a calculator, we can find that the probability of a gorilla living longer than 14.3 years is approximately 0.812, or 81.2%.
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Answers
Answer:
6 miles
Step-by-step explanation:
Let's say the length of the sides of the square is x.
The area of a square is denoted by: A = x².
Here, we're given that twice the area of the square is 72, so we can write this is 2 times the area, which is 2 * x². Set this equal to 72 and solve:
2x² = 72
x² = 36
x = 6
Thus the answer is 6 miles.
Answer:
6 miles
Step-by-step explanation:
2A = 72
A = 72/2
A = 36
Area = s²
36 = s²
s = 6 miles
Answers
Answer:
y = 3/4x +2
Step-by-step explanation:
The slope intercept form of an equation is
y = mx+b
where m is the slope and b is the y intercept
Y-intercept=(0,2) slope=3/4
y = 3/4x +2
b. What is the probability that the gun detects speeding and the driver was not speeding?
c. Suppose the police stop a driver because the gun detects speeding. What is the probability that the driver was actually driving below the speed limit?
Answers
Answer:
a) P(A∩B) = 0.21
b) P(A∩B') = 0.0072
c) P(B'|A)=0.0072/0.2172=0.0331
Step-by-step explanation:
A = the gun will detect a speeder
B = driver is actually speeding
P(A|B) = 0.75
P(A|B')=0.01
P(B') = 0.72
a) by definition
P(A∩B)=P(A|B)*P(B)=0.75*(1-0.72)=0.21
b) by definition
P(A∩B')=P(A|B')*P(B')=0.01*(0.72)=0.0072
c)
by bayes theorem
P(B'|A)=P(A|B')*P(B')/P(A)
by total probability theorem
P(A)=P(A∩B)+P(A∩B')=0.21+0.0072=0.2172
so
P(B'|A)=0.0072/0.2172=0.0331
Final answer:
The probabilities asked in the question are calculated using basic principles of probability: a) the probability that the radar gun detects speeding and the driver was speeding is 21%, b) the probability that the radar gun detects speeding, and the driver was not speeding is 0.72%, c) given that a driver is stopped because the radar gun detected speeding, the probability that they were actually driving within the speed limit is 3.3%.
Explanation:
The probability of a speed detection can be divided into two different categories – the probability of an accurate detection (where the driver is actually speeding), and a false detection (where the driver is not speeding).
a. The probability that the gun detects speeding and the driver was speeding is calculated by the accuracy of the gun, which is 75%, multiplied by the percentage of drivers that are actually speeding. Given that 28% of the drivers exceed the speed limit (100% - 72% safe drivers), the probability is 0.75*0.28 = 0.21 or 21%.
b. The probability that the gun detects a speeder when the driver is not speeding is calculated by multiplying the probability the gun makes an error (1%) and the chance that the driver is driving within the speed limit (72%). So, 0.01*0.72 = 0.0072 or 0.72%.
c. If the police stop a driver because the gun detects speeding, the probability that the driver was actually driving safely is calculated by taking the probability that the gun gives a false speed reading (0.72%) and dividing it by the total probability that the gun detects a speeding vehicle (accurate detection + false detection = 21% + 0.72% = 21.72%). So, 0.72 / 21.72 = 0.033 or 3.3%.
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Answers
The height and length of the box to the nearest tenth will be 10.6 inch and 7.4 inch respectively.
Explanation
Suppose, the height of the box is inch
As the length of the box is 3.2 in. less than the height, so the length will be:
Given that, the width of the box is 2.3 inch. and the volume is 180.4 inch³
Formula for Volume of a box:
So, the equation will be....
Now using quadratic formula......
(Negative value of is ignored as the height can't be negative)
So, the height to the nearest tenth will be 10.6 inch and the length will be:
2. Regular pentagon PENTA has side lengths that are 9 meters long. To the nearest square meter, find the area of the pentagon.
Area of pentagon PENTA = _____square centimeter
Answers
Given
1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.
2) Regular pentagon PENTA with side lengths 9 m
Find
The area of each figure, rounded to the nearest integer
Solution
1) The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
Answer:139 cm squared
The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².