MATHEMATICS HIGH SCHOOL

Share $420 in the ratio 2:1:4

Answers

Answer 1

Answer:

Answer:

120:60:240

Step-by-step explanation:

2+1+4=7

420/7=60

2*60:1*60:4*60

=120:60:240

Check my work:

120+60+240=420

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Fourteen is 20% of what number?

7/8 is equvlent to what over 24

Answers

We know that 8 x 3= 24
7/8=?/24
7 x 3=21
So the answer is 3
3/24

The vertices of a feasible region are (14, 2), (0, 9), (6, 8), and (10, 3). What is the maximum value of P if P = 180x + 250y?

Answers

For this problem, we must first plot of each point using the given points. Assume that each coordinate given is in the (x,y) form. To get the maximum value, we can plus in each coordinate set to the equation to see which P comes out to be the largest. For (14,2), P=3020. For (0,9), P=2250. For (6,8), P=3080. For (10,3), P=2550. The maximum value for P would be P=3080.

Answer:

It’s C

Step-by-step explanation:

Y=0.81x+25 in standard form

Answers

a standard equation follows the form Ax + By = C, so the answer is -0.81x + y = 25 just by subtracting the x term from both sides

The first one to answer gets ( a best answer )

Answers

Step-by-step explanation:

1- 9.34

2- 5.85

3- 40.14

Hope this can help you

Answer: 1) 9.34, 2) 5.85,

Step-by-step explanation:

Suppose that an object whose is 10th weighs 50 N find the weight of an object whose is 6 kg

Answers

Weight is another term for the force from mass multiplied by acceleration due to gravity, the equation being expressed as $f = ma$ , being force, mass, and acceleration respectively.

We already have 2 parts of the equation, $50 = 10a$

Acceleration due to gravity on the planet is $5 m/s^2$

Plug it into the equation $f = ma$

$f=6kg$ x $5m/s^2$

Weight or force from gravity is 60N.

How many triples of the 3 positive integers (x,y,z) are products of 24

Answers

Final answer:

To find the triples of the 3 positive integers (x,y,z) that are products of 24, consider the prime factorization of 24 and distribute these prime factors among x, y and z. Remember to consider permutations.

Explanation:

The student is asking about triples of positive integers (x,y,z) whose product is 24. To find these triples, consider the prime factorization of 24, which is 2^3*3.

Triplet possibilities are created by distributing these prime factors among x, y, and z. For instance, (1,1,24), (1,2,12), (1,3,8), (1,4,6), (2,2,6), and their permutations.

When considering permutations, remember each triple can be ordered in 3! = 6 ways. Making each distinct triple six separate triples. For example, (1,1,24) becomes [(1,1,24), (1,24,1), (24,1,1), (1,24,1), (1,1,24), (24,1,1)]. Repeat this process for all the distinct triples.

To get the total number of triples, count all the distinct permutations. Keep in mind the triple where all numbers are equal, such as (2,2,6), should be counted only once, as its permutations do not produce distinct triples.