A graduated cylinder has 20 ml (cm3) of water placed in it. An irregularly shaped rock is then dropped in the graduated cylinder and the volume of the rock and water in the cylinder now reads 30 ml (cm3). The mass of the rock dropped into the graduated cylinder is 23 grams. a.) Find the volume of the rock dropped into the graduated cylinder.
b.) Find the density of the rock dropped into the graduated cylinder.
Answers
Answer:
Explanation:
Answer:
Explanation:
A. Volume
The volume was found using water displacement. Subtract the initial volume from the final volume.
The graduated cylinder had 20 milliliters of water (initial volume).
After the rock was added, the graduated cylinder read 30 milliliters (final volume).
Substitute the values in and subtract.
The volume of the rock is 10 milliliters.
B. Density
Density can be found by dividing the mass by the volume.
The mass of the rock is 23 grams. We just found the volume of 10 milliliters.
Substitute the values in and divide.
The density of the rock is 2.3 grams per milliliter.
Answer:
Volume = 10 cm3
Density = 2.3g/cm3
Explanation:
volume:
30ml - 20ml = 10ml = 10cm3
density:
density = mass/volume
23/10
2.3g/cm3
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What is the frequency of an event?Group of answer choicesProbabilityDegreeExpected occurrenceIdentification
B. atomic number.
C. molecular mass.
D. molecular size.
Answers
Answers
Ideal gas law is valid only for ideal gas not for vanderwaal gas. Charles' gas law is used here. Therefore the new volume of the balloon in the hot room is 3.68 L.
What is ideal gas equation?
Ideal gas equation is the mathematical expression that relates pressure volume and temperature. Vanderwaal gas can behave as ideal gas low pressure and high temperature.
Mathematically the relation between Pressure, volume and temperature can be given as
PV=nRT
where,
P = pressure of gas
V= volume of gas
n =number of moles of gas
T =temperature of gas
R = Gas constant = 0.0821 L.atm/K.mol
Combining Boyle's and Charles' gas law
V₁/T₁ = V₂/T₂
3.50 L ÷298 K = V₂÷313 K
V₂ = 3.68 L
Therefore the new volume of the balloon in the hot room is 3.68 L.
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yes, according to charles law, this would be equal to 3.68 L
endothermic and exothermic reactions.
4
O Endothermic reactions absorb heat
energy while exothermic reactions
release heat energy.
O Exothermic reactions absorb heat
energy while endothermic reactions
release heat energy.
O Endothermic and exothermic reactions
absorb thermal energy.
O Endothermic and exothermic reactions
release thermal energy.
REM
The prefix exo-
applied to a che
mean energy
re
Answers
Statement-1 is the correct answer that is Endothermic reactions absorb heat energy while exothermic reactions release heat energy.
How can we distinguish between exothermic and endothermic processes?
Chemical reactions that release energy are referred to as exothermic. More energy is produced than is needed to break the bonds between the reactants when bonds are formed in the byproducts of exothermic processes.
Chemical processes that either use or absorb energy are referred to as endothermic. In endothermic reactions, more energy is absorbed when bonds in the reactants are broken than is released when new bonds are formed in the products. Since an isothermic chemical reaction uses exactly as much energy as it produces, there is no net energy change.
Therefore, the first statement is the right response.
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Answers
1. Find the atomic radius of thorium (Th). The atomic radius of thorium is approximately 180 picometers (pm), which is 180 x 10^-12 meters.
2. Convert 1.80 mm to meters. There are 1,000,000 picometers in a millimeter, so 1.80 mm is equivalent to 1.80 x 10^-3 meters.
3. Divide the length you want to span (1.80 x 10^-3 meters) by the atomic radius of thorium (180 x 10^-12 meters):
(1.80 x 10^-3 meters) / (180 x 10^-12 meters) = 10,000,000
So, you would need to line up approximately 10,000,000 thorium atoms side by side to span 1.80 mm.
Answers
Answer:
Average atomic mass = 79.9034 amu
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
For first isotope:
% = 50.69 %
Mass = 78.9183 amu
For second isotope:
% = 49.31 %
Mass = 80.9163 amu
Thus,
Average atomic mass = 79.9034 amu
Answers
Saturation on the other hand deals with how much solute (solid) you can disolve in a solvent. As you add solute to solution it can only disolve a certain amount before the solvent becomes "satutated" and no more solute will desolve into a homogenous blend with the solvent. You then see precepitants start coming out of solution and falling to the bottom of the container the solution is contained in.