Select all points that are on the line through 0,5and 2,8.


4,11
5,10
6,14
30,50
40,60​
select all points that are on the line through 0,5 - 1

Answers

Answer 1
Answer:

Answer:

Options (1), (3), and (4)

Step-by-step explanation:

Since, slope of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

m = (y_2-y_1)/(x_2-x_1)

Therefore, slope of a line passing through (0, 5) and (2, 8) will be,

m = (8-5)/(2-0) = 1.5

Equation of line passing through (x', y') and slope 'm' is,

y - y' = m(x - x')

Therefore, equation of a line passing through (0, 5) and slope = 1.5,

y - 5 = 1.5(x - 0)

y = 1.5x + 5

Since, all the points which lie on this line will satisfy this equation.

For (4, 11),

11 = 1.5(4) + 5

11 = 11

Point (4, 11) lies on this line.

Point (5, 10)

10 = 1.5(5) + 5

10 = 7.5 + 5

10 = 12.5

But 10 ≠ 12.5

Therefore, (5, 10) doesn't line on the line.

Point (6, 14)

14 = 1.5(6) + 5

14 = 14

True.

Therefore, (6, 14) lies on the line.

Point (30, 50)

50 = 1.5(30) + 5

50 = 50

True.

Therefore, (30, 50) lies on the line.

Point (40, 60)

60 = 1.5(40) + 5

60 = 65

But 60 ≠ 65

Therefore, (40, 60) doesn't lie on the line.

Options (1), (3) and (4) and the correct options.

Answer 2
Answer:

Answer:

1, 3 and 4. I had the same question on my assignment :)

Step-by-step explanation:


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Suppose monthly rental prices for a one-bedroom apartment in a large city has a distribution that is skewed to the right with a population mean of $880 and a standard deviation of $50. (a) Suppose a one-bedroom rental listing in this large city is selected at random. What can be said about the probability that the listed rent price will be at least $930?
(b) Suppose a random sample 30 one-bedroom rental listing in this large city will be selected, the rent price will be recorded for each listing, and the sample mean rent price will be computed. What can be said about the probability that the sample mean rent price will be greater than $900?

Answers

Answer:

a) Nothing, beause the distribution of the monthly rental prices are not normal.

b) 1.43% probability that the sample mean rent price will be greater than $900

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = (\sigma)/(√(n))

(a) Suppose a one-bedroom rental listing in this large city is selected at random. What can be said about the probability that the listed rent price will be at least $930?

Nothing, beause the distribution of the monthly rental prices are not normal.

(b) Suppose a random sample 30 one-bedroom rental listing in this large city will be selected, the rent price will be recorded for each listing, and the sample mean rent price will be computed. What can be said about the probability that the sample mean rent price will be greater than $900?

Now we can apply the Central Limit Theorem.

\mu = 880, \sigma = 50, n = 30, s = (50)/(√(30)) = 9.1287

This probability is 1 subtracted by the pvalue of Z when X = 900.

Z = (X - \mu)/(\sigma)

By the Central Limit Theorem

Z = (X - \mu)/(s)

Z = (900 - 880)/(9.1287)

Z = 2.19

Z = 2.19 has a pvalue of 0.9857

1 - 0.9857 = 0.0143

1.43% probability that the sample mean rent price will be greater than $900

Two cyclists, 112 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other, and they meet after 4 hours of riding.a. Write an equation using the information as it is given above that can be solved to answer this problem. Use the variable r to represent the speed of the slower cyclist.

b. What are the speeds of the two cyclists? Put both values in the answerbox, separated with a comma, and select the appropriate units.

Answers

Answer:

Speed of a= 21 miles/hr

r = Speed of b= 7 miles/hr

Speed of a = 3r

Step-by-step explanation:

The cyclist are 112 miles apart

Time traveled by two = 4 hours

Speed of a = 3 * speed of b

If a cylcles 3 times More than b, then a will cover 3*distance of b

But speed = distance/time

Time = 4hours

Total distance=112

a = 3b

3b + b = 112

4b = 112

b = 112/4

b = 28 miles

a = 3b

a = 3*28

a = 84 Miles

They bought traveled 4 hours

Speed of a = 84miles/4 hours

Speed of a= 21 miles/hr

Speed of b = 28miles/4 hours

Speed of b = 7 miles/hr

Final answer:

The slower cyclist is traveling at a speed of 7 mph, while the faster cyclist is traveling at 21 mph.

Explanation:

We first need to recognize that the sum of the distances travelled by each cyclist is equal to the total 112 miles. We can let r represent the speed of the slower cyclist, and since the faster cyclist is traveling 3 times the speed of the slower, we can call his speed 3r.

As they each traveled for 4 hours, the slower cyclist traveled a distance of 4r miles, and the faster cyclist traveled a distance of 4 × 3r = 12r miles. Their combined distances should equal the total distance between them, 112 miles. This forms the equation 4r + 12r = 112.

To solve for r, we combine the like terms on the left side of the equation to get 16r = 112. Dividing both sides by 16, we find r = 7 miles per hour. Therefore, the slower cyclist is traveling at 7 mph, and the faster cyclist is traveling 3 times that speed, giving us 21 mph.

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The equation 2|3x−1|=10 has two solutions, one positive and one negative. Solve the equation to find the solutions.

Answers

The two solutions of the equation 2|3x - 1| = 10 are x = 2 and

x = -4/3.

We have the following equation -

2|3x -1| = 10

We have to solve the equation to find the solutions.

What is modulus function ?

The modulus function is as follows -

for x > 0 , |x| = x

for x < 0 , |x| = - x

According to the question, we have -

2|3x - 1| = 10

|3x -1| = 5

Now, using the modulus property -

3x - 1 = 5       and       3x - 1 = -5

3x = 6        and       3x = -4

x = 2          and        x = -4/3

Hence, the two solutions of the equation 2|3x - 1| = 10 are x = 2 and

x = -4/3.

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9. In City A, the temperature rises 9 from 8 A.M. to 9 A.M. Then the temperature drops 8 from 9 A.M. to 10 A.M. In City B, the temperature drops 5º from 8 A.M. to 9 A.M. Then the temperature drops 4º from 9 A.M. to 10 A.M. a. What expression represents the change in temperature for City A? b. What integer represents the change in temperature for City A? c. What expression represents the change in temperature for City B? d. What integer represents the change in temperature for City B? e. Which city has the greater change in temperature from 8 A.M. to 10 A.M.? 10.​

Answers

a.The expression for temperature change in City A is 9 + (-8)

b.The amount the temperature changes for City A = 1°F

c.The expression for temperature change in City B is -1 + (-3) = -4°F

d.The amount the temperature changes for City B = -4°F

What is temperature?

The degree of hotness or coldness of an object is called as temperature.

Now it is given that,

In City A,

rise in temperature from 8 am to  9 am = 9°F

drop in temperature from 9 am to  10 am = 8°F

In City B,

drop in temperature from 8 am to  9 am = 1°F

drop in temperature from 9 am to  10 am = 3°F

a.The expression for temperature change in City A

rise in temperature =  +9°F

drop in temperature = -8°F  

∴the expression for change in temperature for City A = 9 + (-8)

b.The amount the temperature changes for City A = 9 + (-8)= 1°F

c.The expression for temperature change in City B

drop in temperature = -1°F

drop in temperature = -3°F  

∴the expression for change in temperature for City A = -1 + (-3)

d.The amount the temperature changes for City B = -1 + (-3)= -4°F

Hence,the required answers are,

a.The expression for temperature change in City A is 9 + (-8)

b.The amount the temperature changes for City A = 1°F

c.The expression for temperature change in City B is -1 + (-3) = -4°F

d.The amount the temperature changes for City B = -4°F

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What is the standard form of two hundred fifty three thousandths

Answers

We are given number in words " two hundred fifty three thousandths".

Let us write it in number form: First we would write the number form of "two hundred fifty".

Two hundred fifty = 253.

Now, we need to write three thousandths.

Three thousandths =  .003

Now, we need to combine 253 and 0.003.

On combining we get 253.003.

Therefore, two hundred fifty three thousandths in standard form is 253.003.

Can I use this for my homework for science because am a little girl trying to get an A+ I hope you understand cuz I want a free college I have money but I don't want to waste my moneeeeeyyyyy

Answers

yes of course, college fees are hard, just make sure you try te questions by yourself first, before you go to this, otherwise you are making no effort, and that may hurt you later in life. but yes, you can use this site, i understand why you want to do that.