CHEMISTRY HIGH SCHOOL

Plz I need help is the 2nd time I post this

Answers

Answer 1

Answer:

Answer:

2--->C

6---->E

3---->D

4--->A

5--->B

1---->F

Explanation:

I think so, sorry if its wrong.

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How much calcium hypochlorite (65% strength) is needed to make 200 L of 2% hypochlorite solution? (Assume that a 1% solution is equivalent to 10,000 mg/L concentration)

Answers

To solve this we use the equation,

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

65 x V1 = 2 x 200 L

V1 = 6.15 L

Which of the following defines sublimation?Solid ➡ Gas

Solid ➡ Liquid

Liquid ➡ Solid

Gas ➡ Solid

Answers

solid to gas
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Which term defines the amount that a solute can dissolve into a solution? A. solute level
B. solution level
C. solubility level
D. saturation level

Answers

The correct answer for the question that is being presented above is this one: "C. solubility level." The term defines the amount that a solute can dissolve into a solution is called the solubility level. The higher the solubility level, the faster it dissolves.

An aqueous solution of lithium hydroxide contains hydroxide ions as the only negative ion in the solution. Lithium hydroxide is classified as an

Answers

An Arrhenius acid refers to a component, which dissociates in water to produce hydrogen ions, or it can also be stated as that the acid enhances the concentration of hydrogen ions in an aqueous solution. On the other hand, an Arrhenius base refers to a component, which gets dissociate in water to produce hydroxide ions, or it can be said that a base enhances the concentration of hydroxide ions in an aqueous solution.

Therefore, an aqueous solution of lithium hydroxide comprising hydroxide ions as the sole negative ion in the solution is classified as an Arrhenius base.

Answer is an Arrhenius Base.

a gas at 155 kPa and 298 K occupies a container with an initial volume of 1.00 L. By changing the volume, the pressure of the gas increases to 605 kPa as the temperature is raised to 398 K. What is the new volume?

Answers

Given: P1=155kPa P2=605kPa T1=298K T2=398K V1=1.00L

Unknown: V2=?

Formula: V2= V1P1T2/P2T1

Solution: V2= 1.00Lx155kPax398K/605kPax298K
V2= 61,690/180,290=n
Answer: V2= 0.34L is the new volume

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0.001011 g
0.000001101 kg
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