MATHEMATICS COLLEGE

Help due in a bit!subject: Pythagorean Theorem

Do the following lengths form a right triangle?

Answers

Answer 1

Answer:

Answer:

alright this is an easy question to do u have to use the Pythagorean theorem which is a²+b²=c²

so put the number of the triangle in this form for #1

Step-by-step explanation:

1.6²+9²=8²

=117=64

2.5²+13²=12²

=194=144

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PLZZ ANSWER THE QUESTION

Answers

The function is nonlinear because there is an exponent to the x value, indicating that it is a parabola, which means that it is not a straight line.

The total assets of skysong Company are* 183,000 and its Stockholders' equity is 887,000
what is the amount of its total liabilities?

Answers

Answer:

Liabilities = 96,000

Step-by-step explanation:

Use the fundamental accounting equation

Assets = Liabilities + Equity

Substitute the information you are given

183,000 = Liabilities + 887,000

Isolate "Liabilities". Subtract 887,000 on both sides.

183,000 - 887,000 = Liabilities + 887,000 - 887,000

-704000 = Liabilities

This problem is impossible if the equity is 887,000 with 183,000 being the assets. The liabilities will be a negative number.

If the equity = 87,000, following the same steps:

Assets = Liabilities + Equity

183,000 = Liabilities + 87,000

183,000 - 87,000 = Liabilities + 87,000 - 87,000

96,000 = Liabilities

Liabilities = 96,000

Therefore, the total liabilities amount to $96,000.

X^2-10x+y^2-20y=-125 what is x+y=?

Answers

The value of x + y from the equation $x^2-10x+y^2-20y=-125$ is 15

The equation is given as:

$x^2-10x+y^2-20y=-125$

Add 125 to both sides of the equation

$x^2-10x+y^2-20y+125 = 0$

Express 125 as 100 + 25

$x^2-10x+y^2-20y+100 +25 = 0$

Rewrite the equation as:

$x^2-10x +25+y^2-20y+100 = 0$

Group the expressions

$[x^2-10x +25]+[y^2-20y+100 ]= 0$

Express the expressions in both groups as perfect squares

$(x - 5)^2+(y - 10)^2= 0$

Possible equations from the above equation is:

$(x - 5)^2= 0$ and $(y - 10)^2= 0$

Take the square roots of both sides

$x - 5= 0$ and $y - 10= 0$

Solve for x and y in the above equations

$x = 5$ and $y =10$

So, we have:

$x + y = 5 + 10$

$x + y = 15$

Hence, the value of x + y is 15

Read more about quadratic functions at:

brainly.com/question/1214333

Write and solve an equation to find the value of x and the missing angle measures.

Answers

7x + 18 = 8x + 7 bcuz they are alternate exterior angles
18-7 = 8x - 7x
11 = x

So the angle measures are
95 and 95

Answer:

x = 11 --> angles = 95 degrees

Step-by-step explanation:

They are equal to each other so

7x + 18 = 8x + 7

Put the like terms together

18 - 7 = 8x - 7x

11 = x

so when we substitute this value of x into the equations, we get that both angles are 95 degrees.

Hope this helps!

Based on the information marked in the diagram, ABC and DEF must be congruent.True Or False?

Answers

Applying the HL congruence theorem, the information marked in the diagram cannot be congruent, so it is FALSE.

What is the HL Congruence Theorem?

The HL congruence theorem states that if the corresponding legs of two right traingles are congruent, and the their hypotenuse are also congruent, then the triangles are congruent.

From the information given, we are not told if the hypotenuse of the right triangles are congruent, so we can't apply the HL congruence theorem to prove they are congruent. The answer is FALSE.

Learn more about the HL congruence theorem on:

brainly.com/question/2102943

What are the coordinates of point b on ac such that ab=2/5ac

Answers

Answer:

$(-(36)/(7),(40)/(7))$

Step-by-step explanation:

Coordinates of points A and C are (-8, 6) and (2, 5).

If a point B intersects the segment AB in the ratio of 2 : 5

Then coordinates of the point B will be,

x = $(mx_2+nx_1)/(m+n)$

and y = $(my_2+ny_1)/(m+n)$

where $(x_1, y_1)$ and $(x_2,y_2)$ are the coordinates of the extreme end of the segment and a point divides the segment in the ratio of m : n.

For the coordinates of point B,

x = $(2* 2+(-8)* 5)/(2+5)$

= $-(36)/(7)$

y = $(2* 5+5* 6)/(2+5)$

= $(40)/(7)$

Therefore, coordinates of pint B will be,

$(-(36)/(7),(40)/(7))$

Final answer:

The coordinates of B on segment AC such that AB=2/5AC are given by line segment division theorem as ((2x2 + 5x1) / 7 , (2y2 + 5y1)/ 7), where A is (x1, y1) and C is (x2, y2).

Explanation:

The question is asking for the coordinates of point B on line segment AC such that the length of AB is 2/5 times the length of AC.

Since we don't have any specific coordinates for points A, B and C, we can't determine exact coordinates for point B. However, we can describe how to find B based on given points A and C.

If A and C have coordinates (x1, y1) and (x2, y2), respectively, then the coordinates of B can be found using the theorem of line segment division. This theorem says that the coordinates of the point dividing a line segment in the ratio m:n are given by:

((mx2 + nx1) / (m+n) , (my2 + ny1)/ (m+n))

Given the ratio is 2:5, m is 2 and n is 5, substitute the values into the formula:

((2x2 + 5x1) / (2+5) , (2y2 + 5y1)/ (2+5))

So, point B is at ((2x2 + 5x1) / 7 , (2y2 + 5y1)/ 7).