• Which factors do 3 and 9 have in common? Choose ALL that apply.1
2
3
4
5
6
7
8
9
10

Answers

Answer 1
Answer:

Answer:

3 and 9 both have factors 1 and 3 in common.

Explanation:

A factor is a number that divides into another number exactly and without leaving a remainder. For instance, factors of 15 are 3 and 5, because 3×5 = 15. Some numbers have more than one factorization (more than one way of being factored). For example, 12 can be factored as 1×12, 2×6, or 3×4.

I hope this was helpful to you! If it was, please consider rating, pressing thanks, and marking my answer as 'Brainliest.' Have a wonderful day.

Answer 2
Answer: 3 and 9 are the only ones that are in common for both 3 and 9

Related Questions

Jonah read 5 1/2 chapters in his book in 90 minutes how long did it take him to read one chapter
Which inscribed angles intercept arc RS?
Luis drew a rectangle on his paper that was 112 cm by 16 cm. What is the area and the perimeter of the rectangle that Luis drew on his paper?PLEASE HELP ME OUT!! THIS IS DUE TODAY!​
1. Solve the equation: p + 15 = 51a. p = 65b. p = 46C. p = 66d. p = 36
In the diagram, rectangle ABCD is split in half by . What is the value of tan x? ~ A. B. C. D. E.

The spread of a disease can be modeled as n=200 Square root t, where n is the number of infected,and t is the time(in days). How long will take until the number of infected people reaches 1400

Answers

Answer:

49 days

Step-by-step explanation:

The spread of the disease is modeled as

n = 200 √(t)

where n = number of infected people

t = time (in days)

When the number of infected people is 1400, the number of days t will be:

1400 = 200√(t)\n \n1400 / 200 = √(t)\n\n7 = √(t)\n\n=> t = 7^2 = 49

It will take 49 days for the number of infected people to reach 1400.

Final answer:

Given the function n=200 Square root t where n is the number of infected, and t is time, it will take 49 days for the number of infected people to reach 1400.

Explanation:

To find out how long it will take until the number of infected people reaches 1400, we are going to set n = 1400 (number of infected people) in the given equation, and then solve for t (time in days).

So, 1400 = 200 √t. Dividing both sides by 200, we get √t = 7. Then, squaring both sides give us t = 49 days. So, it will take 49 days for the number of infected people to reach 1400.

Given the function n=200 Square root t where n is the number of infected, and t is time, it will take 49 days for the number of infected people to reach 1400.

Learn more about Function Solving here:

brainly.com/question/31400068

#SPJ3

Heights of women (in inches) are approximately N(64.5,2.5) distributed. Compute the probability that the average height of 25 randomly selected women will be bigger than 66 inches.

Answers

Answer:

the probability that the average height of 25 randomly selected women will be bigger than 66 inches is 0.0013

Step-by-step explanation:

From the summary of the given statistical dataset

The mean and standard deviation for the sampling distribution of sample mean of 25 randomly selected women can be calculated as follows:

\mu_(\overline x) = \mu _x = 64.5

\sigma_(\overline x )= (\sigma)/(\sqrt n)

\sigma_(\overline x )= \frac{2.5}{\sqrt {25}}

\sigma_(\overline x )= (2.5)/(5)

\sigma_(\overline x ) = 0.5

Thus X \sim N (64.5,0.5)

Therefore, the probability that the average height of 25 randomly selected women will be bigger than 66 inches is:

P(\overline X > 66) = P ( (\overline X - \mu_\overline x)/(\sigma \overline x )>(66 - 64.5)/(0.5) })

P(\overline X > 66) = P ( Z>(66 - 64.5)/(0.5) })

P(\overline X > 66) = P ( Z>(1.5)/(0.5) })

P(\overline X > 66) = P ( Z>3 })

P(\overline X > 66) = 1- P ( Z<3 })

P(\overline X > 66) = 1- 0.9987

P(\overline X > 66) =0.0013

the probability that the average height of 25 randomly selected women will be bigger than 66 inches is 0.0013

Write down the general zeroth order linear ordinary differential equation. Write down the general solution.

Answers

The zeroth derivative of a function y(x) is simply the function itself, so the zeroth order linear ODE takes the general form

y(x)=f(x)

whose solution is f(x).

You can use a calculator for this question. Greg builds a new pond which has a volume of 7.35 m3. It is 4.2 m long and 50 cm deep. What is the width of the pond? m

Answers

The formula of getting the volume of a regular prism is L x W x H = V.
Given: V: 7.35m3
           L:  4.2 m
           H: 50 cm (Convert this to meters) = 0.5m
           W: ?
L x W x H = V
4.2 x W x 0.5m = 7.35m3
2.1m2 x W = 7.35m3 <-- Divide both sides by 2.1m2
The result would be W= 3.5m
So the width of the pond is 3.5m
Hope this solution helps you!

Explain how to use the distributive property to find an expression that is equivalent to 20+10

Answers

Answer: 2(10+5)

Step-by-step explanation: half of 20 is 10. half of 10 is five and i put them both in parentheses. outside the parenthesis i placed 2 so it is multiplied to the inner set of numbers.

Correct answer- 2(10+5) :)

A ball is thrown straight up into the air from the top of a building standing at 50 feet with an initial velocity of 65 feet per second the height of the ball in feet can be modeled by the following function: h(t)=-16t^2++16t+96 When does the ball reach its maximum height?

Answers

Answer:

0.5 seconds (at 100 feet in the air).

Step-by-step explanation:

So, the height of the ball can be modeled by the function:

h(t)=-16t^2+16t+96

Where h(t) represents the height in feet after t seconds.

And we want to find its maximum height.

Notice that our function is a quadratic.

Therefore, the maximum height will occur at the vertex of our function.

The vertex of a quadratic function in standard form is given by the formula:

(-(b)/(2a), f(-(b)/(2a)))

In our function, a=-16; b=16; and c=96.

Find the x-coordinate of the vertex:

x=-((16))/(2(-16))=1/2

So, the ball reaches its maximum height after 0.5 seconds of its projection.

Notes:

To find it’s maximum height, we can substitute 1/2 for our function and evaluate. So:

h(1/2)=-16(1/2)^2+16(1/2)+96

Evaluate:

h(1/2)=-4+8+96=100

So, the ball reaches its maximum height of 100 feet 0.5 seconds after its projection.