Please help me. It's urgent

Answers

Answer 1

Answer:

Answer:

a) 7/5

Step-by-step explanation:

$y-(y-1)/(2)=1-(y-2)/(3) \nThrough\ the\ butterfly\ method\ of\ resolving\ denominators\ ,\n(2y-(y-1))/(2) = (3-(y-2))/(3) \n(2y-y+1)/(2) = (3-y+2)/(3) \n(y+1)/(2) =(5-y)/(3) \n3(y+1)=2(5-y)\n3y+3=10-2y\n3y+2y=10-3\n5y=7\ny=(7)/(5)$

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Plz hurry!!! i need help and I dont understand

The function p(x)=x(x-5)(x-2)(x+3) has four zeros. What is the smallest

Answers

Answer: The smallest zero is -3.

Step-by-step explanation:

Zeros of a function are the values of input for which the function gives 0 output.

Here, the given function is,

p(x) = x(x-5)(x-2)(x+3)

For finding the zeroes of p(x),

p(x) = 0

⇒ x(x-5)(x-2)(x+3) = 0,

⇒ x = 0 or x - 5 = 0 or x-2=0 or x+3=0

⇒ x = 0 or x = 5 or x = 2 or x = -3

Thus, the zeros of the given function are 0, 5, 2, -3

In which -3 is smallest.

you can get the zeros by equating each factor by zero
so we have 0 , 5 , 2 , -3
so the smallest one is (-3)

Find all polar coordinates of point P = (2,14°)

Answers

Answer:

$(2,14^(\circ)+360^(\circ)n)\text{ and }(-2,194^(\circ) +360^(\circ)n)$ .

Step-by-step explanation:

If a point is $P=(r,\theta)$ , the all polar coordinates are defined as

In radian : $(r,\theta +2n\pi)\text{ and }(-r,\theta +(2n+1)\pi)$

In degree : $(r,\theta +360^(\circ)n)\text{ and }(-r,\theta +(2n+1)180^(\circ))$

where, n is any integer.

The given point is

$P=(2,14^(\circ))$

So, all polar coordinates are

$(2,14^(\circ)+360^(\circ)n)\text{ and }(-2,14^(\circ) +(2n+1)180^(\circ))$

$(2,14^(\circ)+360^(\circ)n)\text{ and }(-2,14^(\circ) +360^(\circ)n+180^(\circ))$

$(2,14^(\circ)+360^(\circ)n)\text{ and }(-2,194^(\circ) +360^(\circ)n)$

Therefore, the required polar coordinates are $(2,14^(\circ)+360^(\circ)n)\text{ and }(-2,194^(\circ) +360^(\circ)n)$ , where n is any integer.

Find a solution to the inequality x > 7.

Answers

you must isolate the x in order you must divide both of each sides of the inequality by the other variable or coefficients.

Here, x > 7 itself is a solution. It represents x must be less than the 7

Hope this helps!

Find the solution of this system of two linear equations using substitution 11x+3y=103 and y =3x+1

Answers

11x+3y=103 and y=3x+1.

11x+3(3x+1)=103 -----> plug in (3x+1) for y in the first equation. You will want to distribute the 3 to the 3x+1 to get something that looks like:

11x+9x+3=103 ------> now you want to combine like terms

20x+3=103 ---> subtract 3 from both sides
20x=100 ----> divide both sides by 20
x=5

y=3(5)+1 ---> I like to plug in this to the equation that already has y isolated. 3*5 is 15, add 1 and you find that y=16.

(5, 16) will be your final answer (:

Point M is the midpoint of segment QR. If QM = 16 + x and MR = 2(x + 2), find the length of QM.