List and describe the 5 health reaped components of fitness.

Answers

Answer 1

Answer: 1.Heart and lung endurance or cardiovascular endurance is the ability to exercise the entire body for long periods of time. 2. Muscular Strength is the amount of force you can put forth with your muscles. 3. Muscular Endurance is the ability to use the muscles, which are attached to the bones, many times without getting tired. 4. Flexibility is the ability to use your joints fully. 5. Body Composition is the percentage of body weight that is fat compared to other body tissue, such as bone and muscle.

Answer 2

Answer:

Answer:

(1) body composition, (2) flexibility, (3) muscular strength, (4) muscular endurance, and (5) cardiorespiratory endurance.

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An object is thrown downward with an initial velocity of 3 feet per second. The relationship between the distance s it travels and time t is given by s = 3t + 16t2. How long does it take the object to fall 70 feet?

A 2.00 × 103 kg car rounds a circular turn of radius 20.0 m. If the road is flat and the coefficient of static friction between the tires and the road is 0.70, how fast can the car go without skidding?

Answers

Answer:

11.7 m/s

Explanation:

In order for the car to remain in circular motion along the road and not to skid, the frictional force between the tires and the road must be equal to the centripetal force.

Therefore, we can write:

$\mu mg = m(v^2)/(r)$

where:

m = 2000 kg is the mass of the car

$\mu=0.70$ is the coefficient of friction

$g=9.8 m/s^2$ is the acceleration due to gravity

v is the speed of the car

r = 20.0 m is the radius of the turn

Substituting and solving for v, we find the speed of the car:

$v=√(\mu gr)=√((0.70)(9.8)(20.0))=11.7 m/s$

suppose that you look into a photometer's eyepiece and the fluorescent disks appear to be equal in intensity. If the distance between the photometer to lamp 1 is 400mm, the distance between the photometer to lamp 2 is 200 mm, and the intensity of lamp 2 is known to be 15 candelas, what is the intensity to lamp 1?

Answers

Use the Inverse square law, Intensity (I) of a light is inversely proportional to the square of the distance(d).

I=1/(d*d)

Let Intensity for lamp 1 is L1 distance be D1 so on, L2 D2 for Intensity for lamp 2 and its distance.

L1/L2=(D2*D2)/(D1*D1)

L1/15=(200*200)/(400*400)
L1=15*0.25
L1=3.75 candela

High intensity sounds are perceived as relatively loud sounds. The sound waves which are most intense and perceived as loud sounds are those which have a ______ . Identify the one characteristic which is unique of such sound waves.

Answers

Explanation:

loud sound depends on amplitude, intensity, frequency and energy.

as already mention high intensity sounds are perceived as loud sounds.

and the intensity of the sound is the rate at which the energy through a cross sectional area of a medium. higher intensity means higher amplitude. if we put more energy as source means we providing higher amplitude vibrations to the particles which cause the increase in intensity result is louder sound.

Any substance that yields a hydrogen ion when placed in a water solution is called a(n) _____.

Answers

its known as an acid

H2SO4 sulfuric acid

yes ...it is called Acid.

How is the horizontal component of velocity for a projectile affected by the vertical component?

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It isn't. The horizontal and vertical velocities are separate. You separate that velocity into the horizontal component which is constant, disregarding air resistance, and vertical velocity which is changed by the acceleration due to gravity. Make calculations separately because they do not influence each other.

When two point charges are a distance d apart, the magnitude of the electrostatic force between them is F. If the distance between the point charges is increased to 3d, the magnitude of the electrostatic force between the two charges will be

Answers

Answer:

The magnitude of the electrostatic force decreases by a factor 9

Explanation:

The electrostatic force between two charges is given by:

$F=k(q_1 q_2)/(d^2)$

where

k is the Coulomb's constant

q1 and q2 are the two charges

d is the distance between the two charges

We see that the magnitude of the force is inversely proportional to the square of the distance. If the distance is increased to 3d: d' = 3d, the new electrostatic force would be:

$F'=k(q_1 q_2)/((d')^2)=k(q_1 q_2)/((3d)^2)=(1)/(9) k(q_1 q_2)/(d^2)=(F)/(9)$

So, the electrostatic force decreases by a factor 9.

Decreased by a factor of 9

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