A blood bank needs 5 people to help with a blood drive. 18 people have volunteered. Find how many different groups of 5 can be formed from the 18 volunteers.

Answers

Answer 1
Answer:

Hence, the different groups of 5 can be formed from the 18volunteers is

^(18)C_5=205632.

What is the permutation and combination?

Permutation and Combination form the principles of counting and they are applied in various situations.

A permutation is a count of the different arrangements which can be made from the given set of things. In permutation the details matter, as the order or sequence is important.

Here given that,

A blood bank needs 5 people to help with a blood drive. 18 people have volunteered.

So,

^nC_r=(n!)/(r(n-r)!)

Here n=18, r=5

Then

^(18)C_5=(18!)/(5(18-5)!)\n\n^(18)C_5=(18!)/(5(13)!)\n\n^(18)C_5=((18)(17)(16)(15)(14)(13))/(5(13))\n\n^(18)C_5=((18)(17)(16)(15)(14))/(5)\n\n^(18)C_5={(18)(17)(16)(3)(14)}\n\n^(18)C_5=205632

Hence, the different groups of 5 can be formed from the 18volunteers is

^(18)C_5=205632.

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Answer 2
Answer:

Answer:

u can have max of 3 with remainder of 3

Step-by-step explanation:


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Y -2x=4 solve the equation for the variable y. What is y?

Y'all I'm crying...help ​

Answers

Answer:

Below in bold.

Step-by-step explanation:

C1 = 180 - C2

= 180 -  (170-2x)

= 10 + 2x

So B3 = 10+2x (alternate angles).

and B2 = 90 - B3

= 90 - (10 + 2x)

= 80 - 2x.

Can somebody possibly solve this???Consider a rectangle, for which perimeter = 2l+2w. perimeter = 2 l + 2 w . If the length of a rectangle is 5 m or less than twice the width, and the perimeter is 44 m long, find its length and width.

Answers

Final answer:

To determine the length and width of a rectangle, we can set up an equation using the given information and solve for the variables. By substituting the width back into the equation for the length, we find that the width is 9 meters and the length is 13 meters.

Explanation:

To solve this problem, we can start by using the given information to create equations. Let's assume that the width of the rectangle is 'w' meters. According to the problem, the length of the rectangle is 5 meters or less than twice the width, so the length can be represented as 2w - 5 meters.

The formula to calculate the perimeter of a rectangle is 2l + 2w, where 'l' is the length and 'w' is the width. We are given that the perimeter is 44 meters, so we can set up the equation as follows:

2(2w - 5) + 2w = 44

Simplifying the equation, we get:

4w - 10 + 2w = 44

Combining like terms, we have:

6w - 10 = 44

Next, we can isolate the variable by adding 10 to both sides:

6w = 54

Finally dividing both sides by 6, we find that:

w = 9

Therefore, the width of the rectangle is 9 meters. Substituting this value back into the equation for the length, we find:

l = 2w - 5 = 2(9) - 5 = 18 - 5 = 13 meters.

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Which of the following is a monomial? A. 3x2 + 2x − 1
B. 4
C. 3x + 4
D. 2x − 1

Answers

"mono" means 1 or single. In algebra, a monomial is any number that is alone or by itself. For this question, among the choices, the monomial is the number 4. Therefore the answer to this question is letter B. 4.

4^3 • 5^3 and 20^3, Are the expressions equivalent? Yes or no?

Answers

Hey there!

4^3 * 5^3 = ?

4^3

= 4 * 4 * 4

= 16 * 4

= [64]

5^3

= 5 * 5 * 5

= 25 * 5

= [125]

125 * 64

= [8,000]

20^3

= 20 * 20 * 20

= 400 * 20

= 8,000

8,000 = [8,000]

Therefore, this statement is TRUE so your answer is: [YES]

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

Yes

Step-by-step explanation:

4³ × 5³

(4 × 5)³

=20³

Both are equivalent

Find the exact value of each trigonometric function:1) cot 135 degrees
2) tan -30 degrees
3) cot (-pi)

Show your work.

This is from trigonometry or Algebra 2.
Please don't answer if you don't know it.

Answers

cot 135 is the same a 1/tan 135, which is equal to 1/-1, so cot 135 is -1

tan -30 is the same as tan 330, which is -√(3 ) / 3

cot -π = 1 / tan π, which is 1 / 0, and you can't divide by 0, so cot -π is undefined

If an object has a mass of 50 kilograms, what would it weigh on Uranus, where the acceleration due to gravity is. 10.5 meters/second2?

Answers

Mass of n object : m = 50 kg.
On Uranus : g ( Uranus ) = 10.5 m/s²
Weight = Mass   x  Acceleration due to gravity
Weight = 50 kg · 10.5 m/s² = 525 kgm/s² = 525 N