Which addition does the model below represent?3 + (negative 1)3 + 4
3 + (negative 4)
3 + 1

Answers

Answer 1
Answer:

Answer:

3+(-4)

Step-by-step explanation:

i got it right


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Does anyone seriously know how to do these

Answers

Thats simple!
h(x)= (x^(2)+3x )/(4x+27)
find h(-8)
All we need to do is PLUG IN THE -8
h(-8)= ((-8)^(2)+3(-8) )/(4(-8)+27)
        =(64-24)/(-32+27) (negative²=positive,                                                                                negative×positive=negative)
        =(40)/(-5)
h(-8)=-8

Which of the following is the radical expression of a to the four ninths power ?

Answers

first if a>0 sqrta=a^(1/2), and (a^p)^q=a^pxq

sqrt(a^4/9)= (a^4/9)^1/2=a^4/9x1/2=a^(2/9)
so the answer is 
a^(2/9)

Please help? I'll fail if I miss this....Which triangle is similar to triangle SRT? (6 points)


Triangle QRP

Triangle PST

Triangle PQR

Triangle TRP

Answers

Answer:

TRP

got the answer right on the test!

Round 736 to nearest ten

Answers

The answer is 740
Because the 6 at the end is higher then 5 therefore we round it up x
740 because 736 the 6 is a high number and anything 5 or higher u round it up

Let f(x) = x – 4 and g(x)=1/x. The graph of (g o f)(x) is shown below. What is the domain of (g o f)(x)?

all real numbers except x = –4
all real numbers except x = 0
all real numbers except x = 4
all real numbers

Answers

Answer:

domain is all real numbers except x=4

Step-by-step explanation:

f(x)= x-4 and g(x)=(1)/(x)

We need to find (gof)(x)

(g o f)(x)= g(f(x))

Plug in x-4 for f(x)

(g o f)(x)= g(f(x))=g(x-4)

Now we plug in x-4 for x in g(x)

(g o f)(x)= g(f(x))=g(x-4)=(1)/(x-4)

(g o f)(x)=(1)/(x-4)

Domain is the set of all x values for which the function is defined

To find out the x values that is undefined we set the denominator =0 and solve for x

x-4=0, x=4

When x=4 the denominator becoems 0 that is undefined

So domain is all real numbers except x=4

Oi-All real numbers except x=4 

they would all intersect 0 still

If the velocity of a car on a timed test drive on an airfield is given by the function:V= 24t - 3t(squared)
Where v is in m/s and t is in seconds
Starting from rest, the car comes to rest again after 8 seconds. How far has it travelled during that time?

Answers


The graph of the car's speed is a piece of an inverted parabola,
that cuts the time axis at zero and at 8 sec. 

The distance the car travels during that 8 seconds is the area
between the parabola and the time axis.  If you intend to calculate
it, then I'm afraid you're going to need to integrate the speed function.

           V = 24t - 3t²

Distance = integral of (24t - 3t²), evaluated from zero to 8 seconds.

Integral of (24t - 3t²) =

             t²/2 - 3t³/3  =  12t² - t³

Evaluated between zero and 8 seconds, the integral is

             12(8²) - (8)³ =

               768 - 512  =  256 meters .