Jake bought 4.08 pounds of apples he then bought 2.19 pounds of oranges how many pounds of fruit did he buy altogether? (SHOW YOUR WORK) place value charts (ONES).(TENTHS) (HUNDREDTHS) (THOUSANDS) also please dont give wrong answers im bad at math ❤️

Answers

Answer 1

Answer:

Answer:

6.27 lbs

Step-by-step explanation:

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Lori ran 4.63 miles last weekend and 5.876 miles this weekend. How many miles did she run in all?

Answers

Answer:

10.506

Step-by-step explanation:

its just adding and math lol- if u dont trust it look it at a calculator- hope this helped!!<3

he ran 6,339 in total

If 150 mg of a drug is ordered IVP stat over 2 minutes, and the concentration of the drug is 75 mg/mL, find the total number of milliliters, and indicate how many milliliters you will administer per minute.A.

1 mL total, 1 mL/min.

B.

2mL total, 1 mL/min.

C.

4 mL total, 2 mL/min.

D.

10 mL total, 5 mL/minute

Answers

Answer:

(B) 2mL total, 1 mL/min.

Step-by-step explanation:

Given:

Amount of drug ordered = 150 g

Time = 2 minutes

Concentration of the drug = 75 mg/mL

now,

Concentration = Amount of drug / volume .........(1)

thus,

Volume = Amount of drug / Concentration

Volume = 150 g / (75 g/mL)

Volume = 2 mL

also,

milliliters to administer per minute = Volume / time

milliliters to administer per minute = 2 mL / 2 min = 1 mL/min

Hence, the correct answer is option (B)

One question in the survey asked how much time per year the children spent in volunteer activities. The sample mean was 14.76 hours and the sample standard deviation was 16.54 hours.Required:

a. Based on the reported sample mean and sample standard deviation, explain why it is not reasonable to think that the distribution of volunteer times for the population of South Korean middle school students is approximately normal.
b. The sample size was not given in the paper, but the sample size was described as large. Suppose that the sample size was 500. Explain why it is reasonable to use a one-sample t confidence interval to estimate the population mean even though the population distribution is not approximately normal.
c. Calculate and interpret a confidence interval for the mean number of hours spent in volunteer activities per year for South Korean middle school children.

Answers

Answer:

a. If the distribution was normal, many values would be negative, what is incompatible with the response variable (hours dedicated to volunteer activities).

b. If the sample is big, accordingly to the Central Limit Theorem, the sampling distribution shape tends to be normally-like, so we can apply a one-sample t-test.

c. The 95% confidence interval for the mean is (13.307, 16.213).

Step-by-step explanation:

a. If the distribution was normal, the values with one or more standard deviation below the mean would be negative, what is incoherent for this case. This, in a normal distribution, represents approximately 16% of the values.

If we calculate the probabilty for a normal distribution with the sample parameters, the probability of having "negative hours" is 18.6% (see picture attached).

b. If the sample is big, accordingly to the Central Limit Theorem, the sampling distribution shape tends to be normally-like, so we can apply a one-sample t-test.

The sampling distribution standard deviation is also reduced by a factor of 1/√n.

c. We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=14.76.

The sample size is N=500.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=(s)/(√(N))=(16.54)/(√(500))=(16.54)/(22.3607)=0.7397$

The t-value for a 95% confidence interval is t=1.965.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=1.965 \cdot 0.7397=1.453$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 14.76-1.453=13.307\n\nUL=M+t \cdot s_M = 14.76+1.453=16.213$

The 95% confidence interval for the mean is (13.307, 16.213).

I am a 3-digit number. If you switch my first and last digits, I decrease by 297. Also, mymiddle digit is 6 less than my first digit, which is 2 less than 2 times my last digit. What
number am I?

Answers

Answer:

Step-by-step explanation:

Let the 3-digit number is abc = 100a + 10b + c.

We have:

100a + 10b + c - 100c - 10b - a = 297
b = a - 6
a = 2c - 2

Simplify the first equation:

99a - 99c = 297
a - c = 3
a = c + 3

Solve for c by substitution:

2c - 2 = c + 3
2c - c = 3 + 2
c = 5

Find a:

a = 3 + 5 = 8

Find b:

b = 8 - 2 = 6

The number is:

Imagine you and Janice are the only ones working as telemarketers for a large cooperation. You make 70% of the calls and each call takes you Exponential amount of time with parameter λ1 = 2 hrs-1 . Janice, on the other hand, makes the remaining 30% of total calls. Each call takes her Exponential amount of time with parameter λ2 = 4 hrs-1 . A certain call was made 30 minutes ago and it is still ongoing. What is the probability that you made this call?

Answers

Answer:

The probability that you made this call is 0.8639.

Explanation:

Parameter for you = λ1 = 2

⇒ β1 = 1 / λ1 = 1 / 2 = 0.5

Parameter for Janice = λ2 = 4

⇒ β2 = 1 / λ2 = 1 / 4 = 0.25

Probability that you made a for 0.5 hours or more:

$P(X\geq 0.5)=e^(-0.5/0.5)=0.3679$

Probability that Janice made a for 0.5 hours or more:

$P(X\geq 0.5)=e^(-0.5/0.25)=0.1353$

Overall probability that a call was made for 0.5 hours of more

= (0.7 x 0.3679) + (0.3 x 0.1353)

= 0.2981

Probability that you made the given call

= 0.7 x 0.3679 / 0.2981

= 0.8639

jermey has a weekend job as soccer referee. one weekend, he earns $140 by working 4 games. another weekend he earns $210 by working 6 games. if jeremy graphed an equation that represented his total earning based on the number of games worked, what would be the slope of the graph

Answers

Answer:Jeremy's weekend work would follow the equation of the standard line. The equation of the standard line is y=mx+b. b= 0, The slope of the line is equal to m, where m according to the given problem is equal to 35. Every hour of Jeremy weekend would pay $35.

Jeremy's equation

y= 35x

m=35

I think the answer is 35

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