How are work, force, and distance related?

Answers

Answer 1
Answer:

The correct answer of this question is: Work = Force . Distance

EXPLANATION:

The work is said to be done by a body if the force applied on the body has a component along the direction of displacement.

Let us consider a body of mass m.

The body is acted upon by a constant force F . Due to this force, the body undergoes a displacement of S .

Let \theta is the angle between force and displacement.

Hence, the component of force along the direction of displacement is Fcos\theta..

The work done by that body is calculated as -

                         Work done W = Fcos\theta * S

                                                 = FScos\theta

                                                 = \vec F.\vec S    [ ∵ \vec A.\vec B=\ ABcos\theta\ ]

Let \theta=\ 0^(0).

Hence, work done W = FScos0

                                   = FS                   [ cos0 = 1]

Hence, the relation between work, force and distance can be written as -

                             Work = force . distance

Answer 2
Answer: they are directly related because work is the amount of force x the distance so without any of this two u cnt get work

Related Questions

A 60-kg person is traveling in a car moving at 16 m/s, when the car hits a barrier. The person is not wearing a seat belt, but is stopped by an air bag in a time interval of 0.20 s. Determine the average force that the air bag exerts on the person?
How does an action potential differ from simple depolarization
The acceleration due to gravity for an object on the surface of the Earth is g. The distance from the Earth to the Moon is roughly 60 RE, where RE is the radius of the Earth. What is the centripetal acceleration of the moon during its (roughly circular) revolution around the Earth
Dark spots on the photosphere are known asA. the corona.B. the chromosphere.C. sunspots.D. solar wind.
Which of the following is not a type of pulley systemA fixed B movable C combination D advantageous

Which type of wave interaction is shown in the diagram?wave A
MAAAAA
wave B
MAAAA
wave A + B
PAMA
A. Destructive interference
B. Diffraction subtraction
C. Diffraction gradient
D. Constructive interference

Answers

Answer: Constructive interference

Explanation: Just took the test

Final answer:

The diagram shows destructive interference between two waves, resulting in a smaller amplitude wave.

Explanation:

The type of wave interaction shown in the diagram is destructive interference.

In destructive interference, two waves combine and create a new wave with a smaller amplitude. This occurs when the crests of one wave align with the troughs of another wave, causing cancellation.

In the diagram, wave A and wave B are out of phase, meaning their crests and troughs do not align. When they combine, the resulting wave has a smaller amplitude than either individual wave, indicating destructive interference.

Learn more about Destructive interference here:

brainly.com/question/31857527

#SPJ2

What does the process skill measuring mean?

Answers

Answer:

Process Skills: Observing - using your senses to gather information about an object or event. It is description of what was actually perceived. using standard measures or estimations to describe specific dimensions of an object or event

Explanation:

i hope this isnt confusing

This is the most basic skill in science. Observations are made by using the 5 senses. Good observations are essential in learning the other science process skills.

Examples:

The learner will be blind folded and make observations using the sense of touch.

The learner will create observations about a coin using the 5 senses.

The learner will mix primary colors to create more colors.

Use the H-R diagram to answer the following questions.What is the approximate temperature of the supergiant Betelgeuse?

Which star on this diagram is the most similar to the Sun in luminosity and temperature?

Answers

Answer: The answer is 3000 K and Centauri A.

Explanation:

Just did it and got it right ♡´・ᴗ・`♡

Answer:

What is the approximate temperature of the supergiant Betelgeuse?  

3000 K

Which star on this diagram is the most similar to the Sun in luminosity and temperature?

Centauri A

Which description could describe the motion of the object between 7 and 12 seconds (the highlighted area)?a. The object is moving at a constant, negative, velocity. It is negative because it is moving back towards the origin.

b. The object is at rest.

c. The object is going down a hill with a changing speed.

d. The object is speeding up, as it travels back towards the origin.

Answers

Answer:

A  it is still at the same passe and it is going back down

Explanation:

Answer:

The correct answer to your question is A. The object is moving at a constant, negative, velocity. It is negative because it is moving back towards the origin.

Explanation:

The threshold of hearing for humans is 30 decibels.
True
False

Answers

False. Thirty decibels is not the threshold for the human ear. The human ear can hear sounds between 0 to 140 dB. The so-called hearing threshold for humans is 0 dB. It does not mean that at this level there is no sound instead we just can't hear it.

A wave with a wavelength of 15 m travels at 330 m/s. Calculate its frequency.

Answers

Given the value of wavelength and speed at which the wave travels, the frequecy of the wave is 20 Hertz.

What is Wavelength?

Wavelength is simply the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.

From the wavelength, frequency and speed relation;

λ = v ÷ f

Where λ is wavelength, v is velocity/speed and f is frequency.

Given the data in the question;

  • Wavelength λ = 15m
  • Speed of the wave v = 300m/s
  • Frequency f = ?

To determine the frequency of the wave, we substitute our given values into the expression above.

λ = v ÷ f

f = v ÷ λ

f = 300m/s ÷ 15m

f = 20s⁻¹

f = 20Hz

Given the value of wavelength and speed at which the wave travels, the frequecy of the wave is 20 Hertz.

Learn more about Speed, Frequency and Wavelength here: brainly.com/question/27120701

{ \boxed {\red {\boxed {\green {\boxed {\blue {\boxed{ \bold{frequency = (velocity(v))/(wavelength(λ)) }}}}}}}}}

\mathsf{frequency = \frac{330ms {}^( - 1) }{15m} }

\purple{ \sf{frequency \: = \: 22m {}^( - 2) } {s}^( - 1) }